yuu | Yuu - a simple AbemaTV and other website video downloader | Download Utils library
kandi X-RAY | yuu Summary
kandi X-RAY | yuu Summary
A simple AbemaTV and other we(e)bsite video downloader in python.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Main download function
- Copies old file to a new file
- Get parser
- Merge video files
- Returns the path to yuu_data directory
- Delete all files in a folder
- Prepare yuu_download json file
- Compares two version strings
- Parses the given resolution
- Return True if url is a channel
- Obtain a temporary token
- Generate an authentication token
- Download a single chunk
- Setup the AES decryptor
- NoApi version
yuu Key Features
yuu Examples and Code Snippets
>> yuu -h
Usage: yuu [OPTIONS] COMMAND [ARGS]...
A simple AbemaTV video downloader
Options:
-V, --version Show current version
-U, --update Update yuu to the newest version
-h, --help Show this message and exit.
Commands:
do
Community Discussions
Trending Discussions on yuu
QUESTION
My data looks like this:
...ANSWER
Answered 2021-Apr-20 at 11:19QUESTION
Problem: When trying to pass a variable value from JS to XML, only the last entry got rendered with a t-foreach
directive.
Current Result: Only the last item gets to the DOM
...ANSWER
Answered 2021-Apr-19 at 09:34As discussed in a github issue,
As of Owl <2.x, components with nested tags (multiple roots) aren't supported. Thus, the needed functionanality was achieved by following ged-odoo's comment:
- change
line to
- move
t-foreach
belowdiv
application
The resulting code XML is:
QUESTION
I'm trying to get a data from an online JSON, so getting the json and printing it works without issue, but when I want a particular data, my IDE give me this error
...ANSWER
Answered 2021-Jan-13 at 18:21You are getting an array at the top level instead of a JSON object. You should use JSONArray instead of JSONObject to parse the inital response object.
QUESTION
l = ["Youtube", "Instagram", "Facebook"]
a = [
[
"{} {}".format(i[2 * j : 2 * j + 1], i[2 * j + 1 : 2 * j + 2])
for j in range(len(i) // 2)
]
for i in l
]
print(a)
...ANSWER
Answered 2019-Oct-01 at 12:49You don't actually need a double list comp for this. You can accomplish this by slicing up to the last even element and stepping by 2.
If you want them as single strings in a one-deep list:
QUESTION
I want to calculate the mean and Gaussian curvatures of some points in a point cloud.
I have x,y,z, that are coordinates and are 1d arrays. I want to use the below code src but in the input parameters X, Y and Z are 2d arrays, I don't know what means that, and how I can calculate 2d arrays corresponding to them.
...ANSWER
Answered 2017-May-27 at 07:37You have ways to convert your x,y,z data to surface matrices/ 2D arrays. Way depends on, how and what your data is.
Structured grid data:
(i). If your x,y,z corresponds to a structured grid, then you can straight a way get unique values of x,y which gives number of points along (nx,ny) along x and y axes respectively. With this (nx,ny), you need to reshape x,y,z data into matrices X,Y,Z respectively and use your function.
(ii). If you are not okay with reshaping, you can get min and max values of x,y make your own grid using meshgrid and do interpolation using griddata.
Unstructured grid data: If your data is unstructured/ scattered, get min and max, make your grid using meshgrid and do interpolation using griddata , scatteredInterpolant.
Also have a look in the following links:
https://in.mathworks.com/matlabcentral/fileexchange/56533-xyz2grd
https://in.mathworks.com/matlabcentral/fileexchange/56414-xyz-file-functions
QUESTION
I want to code endless scrolling with Adapters & RecyclerViews and I'm fetching my items with Volley from JSON. Though I have read these guides (Codepath and github), I'm finding it difficult to apply it to my own scenario.
...my json has these format:
ANSWER
Answered 2018-Sep-22 at 20:45Change this overridden method of your adapter:
QUESTION
I am calling a imageServer and getting an x-genericbytedata-octet-stream in response. So i was wondering if i can convert it into some format which is manageable like ndarray. This is what i am getting in response
ÿ Ç÷®£®¥Xøan Ð5£ï~KTþ$¹M«_ ü³þœÿ ˆk¡çÆHyAÏbG§ø
A«÷g~ŒieÞÁn¦=Ÿüú
i.¿†ö@µ2lí~¤ŸðjLóÉ&,X.ó¿:ÿ õ¿*ìüTv蚃zXÌñÓ\•Ÿû[X’ĩ쀀0wOóÀ®ŸÆm·Ãú‘ÿ §?¡¬ª|f‘Øñx^àÁW\móVà„³Éä˜Óý’3úÔpë¬P2€2pGõö?Z’êàÛDÊ=jȶ¤3ÝÝÜb”vägõ¯wÑß z‹8óøŠðy®¤U8³ÄIüÇå^ù§åt]0cìq?೫иQñÔkVØ·fàú±ÿ
I want to convert it into an ndarray so that I could use it in opencv.
Thanks
...ANSWER
Answered 2018-Sep-12 at 05:45You can use Pillow and StringIO to convert it to a jpeg image.
QUESTION
I have points organized in three arrays - X
, Y
and Z
. I want to calculate the gaussian curvature for these points.
I found a code that does this (below), but it seems to require a grid of points. I know I can do [x,y] = meshgrid(X,Y)
to get two of the inputs, but how can I get z
?
ANSWER
Answered 2018-May-03 at 11:24If I understand your problem correctly, you should use another "overload" (i.e. syntax) of meshgrid
, which has 3 outputs:
QUESTION
ANSWER
Answered 2017-Dec-12 at 09:50try to follow below code. you get expecting result.
QUESTION
I have some trouble with my python hangman code and i cant seem to be able to fix it. Just to let everyone know I am new to coding and am still learning how to do stuff. It would be much appreciated if anyone could help me. I find that the same happens when I try to "append" at any other part of the code from the while loop from under the "print... dashes" part.Thank you!
Here is the code:
...ANSWER
Answered 2017-Dec-07 at 21:02Ok, so I reviewed your code and you've got more than one problem. THAT'S OKAY. You're new to this. Anyways, I'll go through piece by piece and describe them for you, as well as how to fix them. Ok, let's begin:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install yuu
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page