gini | Calculate the Gini coefficient of a numpy array | Data Manipulation library

 by   oliviaguest Python Version: Current License: CC0-1.0

kandi X-RAY | gini Summary

kandi X-RAY | gini Summary

gini is a Python library typically used in Utilities, Data Manipulation, Numpy applications. gini has no bugs, it has no vulnerabilities, it has a Permissive License and it has high support. However gini build file is not available. You can download it from GitHub.

This is a function that calculates the Gini coefficient of a numpy array. Gini coefficients are often used to quantify income inequality, read more here.
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              gini has a highly active ecosystem.
              It has 137 star(s) with 32 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 7 have been closed. On average issues are closed in 225 days. There are no pull requests.
              It has a positive sentiment in the developer community.
              The latest version of gini is current.

            kandi-Quality Quality

              gini has 0 bugs and 0 code smells.

            kandi-Security Security

              gini has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              gini code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              gini is licensed under the CC0-1.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              gini releases are not available. You will need to build from source code and install.
              gini has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              gini saves you 3 person hours of effort in developing the same functionality from scratch.
              It has 10 lines of code, 1 functions and 1 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed gini and discovered the below as its top functions. This is intended to give you an instant insight into gini implemented functionality, and help decide if they suit your requirements.
            • Calculate the Gini coefficient .
            Get all kandi verified functions for this library.

            gini Key Features

            No Key Features are available at this moment for gini.

            gini Examples and Code Snippets

            No Code Snippets are available at this moment for gini.

            Community Discussions

            QUESTION

            Reading an online .tbl data file in python
            Asked 2021-Jun-11 at 06:50

            Like the Title says, I am trying to read an online data file that is in .tbl format. Here is the link to the data: https://irsa.ipac.caltech.edu/data/COSMOS/tables/morphology/cosmos_morph_cassata_1.1.tbl

            I tried the following code

            ...

            ANSWER

            Answered 2021-Jun-11 at 06:50

            Your file has four header rows and different delimiters in header (|) and data (whitespace). You can read the data by using skiprows argument of read_table.

            Source https://stackoverflow.com/questions/67927318

            QUESTION

            Function runs into an error after successfully processing the first few results
            Asked 2021-Jun-04 at 18:12

            I have some data that I am trying to apply a function over. It goes to a URL, collects the JSON data and then stores it into a folder on my computer.

            I apply the following code:

            ...

            ANSWER

            Answered 2021-Jun-04 at 18:12

            Consider doing this with possibly/safely

            Source https://stackoverflow.com/questions/67842102

            QUESTION

            Visualizing values in a normalized plot
            Asked 2021-May-17 at 17:18

            I have some data that I would like to plot, visualizing in a normalized chart. Dataset:

            ...

            ANSWER

            Answered 2021-May-17 at 17:18

            If you're having a single column and plotting only the "Gini" column, you can select that column and normalize it before plotting it like:

            Source https://stackoverflow.com/questions/67573950

            QUESTION

            How to calculate roc auc score from positive unlabeled learning?
            Asked 2021-May-08 at 22:07

            I'm trying to adapt some code for positive unlabeled learning from this example, which runs with my data but I want to also calculate the ROC AUC score which I'm getting stuck on.

            My data is divided into positive samples (data_P) and unlabeled samples (data_U), each with only 2 features/columns of data such as:

            ...

            ANSWER

            Answered 2021-May-08 at 22:07

            y_pred must be a single number, giving the probability of the positive class p1; currently your y_pred consists of both probabilities [p0, p1] (with p0+p1=1.0 by definition).

            Assuming that your positive class is class 1 (i.e. the second element of each array in y_pred), what you should do is:

            Source https://stackoverflow.com/questions/67438792

            QUESTION

            Performing GridSearchCV on RandomForestClassifier yields lower accuracy
            Asked 2021-May-07 at 19:21

            I am trying to increase the performance of a RandomForestClassifier that categorises negative and positive reviews using GridSearchCV but it seems that the accuracy is always around 10% lower than the base algorithm. Why is this? Please find my code below:

            Base algorithm with 90% accuracy:

            ...

            ANSWER

            Answered 2021-May-07 at 19:21

            The default values of the baseline model is different from the ones given in the grid search. for example The default value of n_estimators is 100. Take a look here

            Source https://stackoverflow.com/questions/67440552

            QUESTION

            Building an ensemble of Random Forest models with VotingClassifier()
            Asked 2021-Apr-16 at 14:50

            I'm trying to build an ensemble of some models using VotingClassifier() from Sklearn to see if it works better than the individual models. I'm trying it in 2 different ways.

            1. I'm trying to do it with individual Random Forest, Gradient Boosting, and XGBoost models.
            2. I'm trying to build it using an ensemble of many Random Forest models (using different parameters for n_estimators and max_depth.

            In the first condition, I'm doing this

            ...

            ANSWER

            Answered 2021-Apr-16 at 14:50

            You are seeing more than one of the estimators, it's just a little hard to tell. Notice the ellipses (...) after the first oob_score parameter, and that after those some of the hyperparameters are repeated. Python just doesn't want to print such a giant wall of text, and has trimmed out most of the middle. You can check that len(ensemble_model_churn.estimators) > 1.

            Another note: sklearn is very against doing any validation at model initiation, preferring to do such checking at fit time. (This is because of the way they clone estimators in grid searches and such.) So it's very unlikely that anything will be changed from your explicit input until you call fit.

            Source https://stackoverflow.com/questions/67125271

            QUESTION

            How are the votes of individual trees calculated for Random Forest and Extra Trees in Sklearn?
            Asked 2021-Apr-13 at 03:03

            I have been constructing my own Extra Trees (XT) classifier in Rust for binary classification. To verify correctness of my classifier, I have been comparing it against Sklearns implementation of XT, but I constantly get different results. I thought that there must be a bug in my code at first, but now I realize it's not a bug, but instead a different method of calculating votes amongst the different trees in the ensemble. In my code, each tree votes based on the most frequent classification in a leafs' subset of data. So for example, if we are traversing a tree, and find ourselves at a leaf node that has 40 classifications of 0, and 60 classifications of 1, the tree classifies the data as 1.

            Looking at Sklearn's documentation for XT (As seen here), I read the following line in regards to the predict method

            The predicted class of an input sample is a vote by the trees in the forest, weighted by their probability estimates. That is, the predicted class is the one with highest mean probability estimate across the trees.

            While this gives me some idea about how individual trees vote, I still have more questions. Perhaps an exact mathematical expression of how these weights are calculated would help, but I have yet to find one in the documentation.

            I will provide more details in the upcoming paragraphs, but I wish to ask my question concisely here. How are these weights calculated at a high level, what are the mathematics behind it? Is there a way to change how individual XT trees calculate their votes?

            ---------------------------------------- Additional Details -----------------------------------------------

            For my current tests, this is how I build my classifier

            ...

            ANSWER

            Answered 2021-Apr-13 at 03:03

            Trees can predict probability estimates, according to the training sample proportions in each leaf. In your example, the probability of class 0 is 0.4, and 0.6 for class 1.

            Random forests and extremely random trees in sklearn perform soft voting: each tree predicts the class probabilities as above, and then the ensemble just averages those across trees. That produces a probability for each class, and then the predicted class is the one with the largest probability.

            In the code, the relevant bit is _accumulate_predictions, which just sums the probability estimates, followed by the division by the number of estimators.

            Source https://stackoverflow.com/questions/66960207

            QUESTION

            how to find the optimized parameters using GridSearchCV
            Asked 2021-Apr-10 at 22:11

            I'm trying to get the optimized parameters using GridSearchCV but I get the erorr:

            ...

            ANSWER

            Answered 2021-Apr-10 at 22:11

            The classifier.best_estimator_ returns the best trained model which is a DecisionTreeClassifier in this case.

            To access the params use the method get_params() (see here)

            Source https://stackoverflow.com/questions/67039617

            QUESTION

            Reusing a feature to split regression decision tree's nodes
            Asked 2021-Apr-10 at 21:08

            I was left with a little question by the end of a video I've watched about regression tree algorithm: when some feature of the dataset has the threshold with the lower value for the sum of squared residuals, than it is used to split the node (if the number of observations in the node is greater than some predefined value). But can this same feature be used once again to split a node of this branch of the tree? Or the following splits of this branch have to be splitted by thresholds defined by other features (even if the feature that has already splitted other node has a threshold with the lower value for the sum of squared residuals of the observations of this node)?

            Furthermore, I've got the same doubt when studying decision tree classifier: if a feature that has already been used in this branch can split the observations of some node with the lower value for gini's impurity compared to the splits that other features could make, than is this "already used" feature allowed to perform the split or not?

            Thanks in advance for the attention!

            ...

            ANSWER

            Answered 2021-Apr-10 at 21:08

            It's important to remember what data is associated with any node in the tree. Suppose I split my root node on feature x1, where the left child has x1=0 and the right child has x1=1. Then everything in the left subtree will have x1=0. It doesn't make sense to split on x1 anymore - all the data has the same x1 value!

            Source https://stackoverflow.com/questions/67038993

            QUESTION

            Model-evaluation error using cross-validation - average_precision_score
            Asked 2021-Mar-15 at 21:44

            So I have ran the following random forest grid search using balanced_accuracy as my scoring:

            ...

            ANSWER

            Answered 2021-Mar-15 at 21:44

            No idea what your dataset is like or where exactly is the error in your code. Too many redundant parts.

            If the purpose is to use average precision score as stated, then you can use make_scorer, assuming your labels are binary, 0/1 like in example below:

            Source https://stackoverflow.com/questions/66645204

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install gini

            You can download it from GitHub.
            You can use gini like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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