pycrypto | The Python Cryptography Toolkit | Cryptography library
kandi X-RAY | pycrypto Summary
kandi X-RAY | pycrypto Summary
This is a collection of both secure hash functions (such as SHA256 and RIPEMD160), and various encryption algorithms (AES, DES, RSA, ElGamal, etc.). The package is structured to make adding new modules easy. This section is essentially complete, and the software interface will almost certainly not change in an incompatible way in the future; all that remains to be done is to fix any bugs that show up. If you encounter a bug, please report it in the GitHub issue tracker at.
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Top functions reviewed by kandi - BETA
- Return the SSH private key
- Encrypt data
- Pads data to block_size
- Build a PBKDF1 hash of a password
- Decrypt a PBK2 object
- Decodes an object from binary string
- Pads padding to block_size
- Decrypts a PEM encoded string
- Sign M and K
- Update the state of a component
- Update the state of a smooth mac
- Returns a copy of the CMAC object
- Verify that a MAC is valid
- Verify that a mac is valid
- Return hexadecimal digest
- Verify the signature
- Export the Key object
- Encrypt a private key
- Imports an SSH key
- Imports the given extern key
- Decrypts a private key
- Decrypts a private key from a private key
- Generate a random prime
- Builds the extension modules
- Sign a HMAC - SHA1 hash
- Generate a RSA key
pycrypto Key Features
pycrypto Examples and Code Snippets
Community Discussions
Trending Discussions on pycrypto
QUESTION
I tried with pycrypto, pycryptodome, and crypto seperately.. But it shows ModuleNotFoundError: No module named 'Crypto'
ANSWER
Answered 2022-Feb-07 at 10:58simply deleted my existing folder of pycrpto/pycryptodome-3.11.0 located at ..\Python\Python310\Lib\site-packages (if any..), then tried
pip install pycryptodome
QUESTION
I'm trying to install pycrypto package, but I got still getting an error i don't know why ? i have python 3.9, is there any alternatives ?
As you can see bellow, this is the error that I got :
...ANSWER
Answered 2022-Mar-18 at 15:24pycrypto
doesn't work with python3, you can use instead pycryptodome
:
QUESTION
Cannot install pycrypto. Windows 10, build tools have. P.S(pycryptodome is not installing, required version of python < 3.5) Error
...ANSWER
Answered 2021-Oct-10 at 15:31I'd wager something is missing, or that version of Pycrypto just doesn't work on your Python 3.10 on 64-bit Windows. (Pycrypto hasn't been updated since 2013. You probably don't want to use it.)
Could you get whatever you want done with cryptography
, i.e. pip install cryptography
? There seem to be pre-compiled wheels for Windows for it.
There's also a fork of pycryptodome
, pycryptodomex
, that might help.
QUESTION
I'm new to Yocto and I've been trying to setup for developing with devtool
.
I've followed the instructions from from the Yocto Linux Kernel Development Manual, but I've made a change to Step #2, setting MACHINE = stm32mp1
since I'm targeting the STM32MP157D-DK1. However, Step #5 fails, where it asks you to build the SDK using the command bitbake core-image-minimal -c populate_sdk_ext
with the following error:
ANSWER
Answered 2022-Jan-02 at 13:11I've fixed the build issue. It required adding meta-python2
as I did; but instead of IMAGE_INSTALL_append = " python-dev"
, TOOLCHAIN_HOST_TASK_append = " nativesdk-python-core"
is needed instead in local.conf
.
QUESTION
I have a problem. For my project, I need to move files from the directory to the mega cloud. But when trying to run the code, it gives an error. Also when trying to pip install mega.py it turns out the following:
...ANSWER
Answered 2021-Dec-26 at 17:13Go to your terminal/cmd and write this command if you have pip/pip3:
QUESTION
I am working with pycharm community on a tensorflow model with keras backend, sometimes this error appears in a random time, specially after I call pyplot and close the window:
...ANSWER
Answered 2021-Nov-30 at 20:26Looks like this is part of an actively tracked issue with Tkinter in PyCharm. You can find the reference on the Pycharm's developer's issue tracker. The issue is undiagnosed, but if looking at similar problems with Tk on StackOverflow, one can see that it's an issue with thread safety and/or multithreading.
All I can do is speculate as to the cause, which is not helpful, however, I can at least collate the suggested workarounds:
Switch to a different Matplotlib backend (See docs: What is a backend?). Such as Qt5, but you will need to make sure they are available in your environment.
This approach is the most promising as other backends are better able to deal with not being the main thread or are explicitly safe for multi-threading. It's also the simplest unless you have a really specific reason for preferring TkAgg.
Do not use the debugger with interactive plots.
Set "Variables Loading Policy" to "Synchronously" in Debugger as suggested by a PyCharm dev in the linked issue.
Enable "Scientific mode" in Pycharm.
More esoteric workarounds such as closing your figures within the code before drawing the second one. Example, after plotting the first figure:
QUESTION
DISCLAIMER: This is INSECURE encryption that I've inherited and everyone involved knows that. What I'm trying to do here is a first step in getting off this legacy system that has even bigger problems that this.
I have an existing system in Java that I am attempting to port to Python that performs an AES encryption as such:
...ANSWER
Answered 2021-Nov-20 at 00:45You need everything to be the exact same between both versions. This is not currently true; fix that.
Your java code uses:
- AES at block size 128, because that's just how AES rolls. Nothing to configure.
- AES key size of 128, 192, or 256 bits.
- The key.
- The Mode of Operation. Your java code uses ECB (which is insecure). You've told your python code to use GCM. That's, obviously, not going to work. You need to specify ECB there, too.
- Given that it's ECB, there is no IV.
- The padding mode. Java code is doing PKCS5Padding here.
- Crypto is fundamentally byte based but you're trying to encrypt strings, which aren't. That means the string is being converted to bytes, and that means a charset encoding is used. You didn't specify in your java code which means you get 'platform default'. Horrible idea, but if you can't change the java side, figure out what that is, and use the same encoding in your python code.
- Finally, your java code base64's the result.
For most of these, I simply can't tell you; the code you pasted is insufficient. For example, AES key size and whether the keys are actually identical? I have no idea - you tell me. How did you make that SecretKey key
object?
I'm not as familiar with python but it sure looks like you base64-encode it, and then decode it again. That's.. no, don't do that. Your java code encodes and that's that. Your python code should base64 encode and that's that.
I'm pretty sure python also defaults to PKCS5Padding.
That leaves the encoding mode which you 100% mismatched between java and python give what little code you pasted, and the way you construct the keys. If the text you're encrypting isn't straight ASCII, it's somewhat likely charset encoding is also causing a difference.
It's crypto. One tiny difference and the outputs will be quite different.
QUESTION
I am new to python and am trying to run a python 2.7 script. Got pip for python 2.7 and installed a dependency of pyCrypto from the mac terminal shell.
The downloaded python script, I want to try, runs fine in the terminal app when I execute it using python2.
Now I open it in vscode and try to run the script in its terminal and I get
...ANSWER
Answered 2021-Aug-14 at 12:16I'm not familiar with VSCode, but you can manually force the chosen architecture slice of anything you launch with the arch
command (see man arch
).
If you have a script that you'd normally launch like:
QUESTION
I'm working on wrapping some code via Cython. The C++ implementation can be found palisade-python-demo ckks_wrapper.h. For the moment, I'm focusing on wrapping the class CiphertextInterfaceType
, copied below for convenience.
ANSWER
Answered 2021-Sep-10 at 06:44Firstly, you don't need to declare it as a private variable. There's no way to do this or purpose in doing this. Responding to your suggestion in the comments that you might be able to use double underscores (__x
) analagous to Python: there's no way for Cython to generate C++ code that can access the private variable therefore there's no value in this.
As a general rule, Cython only needs to know about the parts of the public interface that you want to access. So if you don't need the other functions you can happily omit them too. I'll assume you do though.
Cython does have some understanding of C++ templates using square brackets. There are limitations here but you can cover most code:
QUESTION
When I use the following command to create a new virtual environment, it succeeds.
...ANSWER
Answered 2021-Aug-22 at 01:23When I create my_ven at least with conda 4.9.2
the environment seems to be empty.
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