radian | A 21 century R console | Command Line Interface library
kandi X-RAY | radian Summary
kandi X-RAY | radian Summary
radian is an alternative console for the R program with multiline editing and rich syntax highlight. One would consider radian as a ipython clone for R, though its design is more aligned to julia.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Search the text
- Start the RADOS program
- Create a read console
- Set environment variables
- Display user input
- Create the default buffer
- Load settings
- Load the prompt
- Performs a prompt
- Check the arguments passed to the constructor
- Remove attributes from kwargs
- Get completions
- Check if the cursor is in a string
- Get all installed packages
- List installed packages
- Configure the retic function
- Commit text
- Move to the cursor position
- Go to the next history
- Append text to the history
- Get the package version
- Set cursor position
- Load history items
- Load history strings from file
- Read the long description from the README md file
- Return True if the current buffer has a complete index
radian Key Features
radian Examples and Code Snippets
Lines of Code : 13License : Permissive (MIT)
Copy#! /bin/bash
# R history: Remove duplicates, commented lines, blank lines, starting `+` symbol
# NOTE the location of your ~/.radian_history. Should be the default.
tac ~/.radian_history | \
awk '!a[$0]++' /**
* === IFFParser ===
* - Parses data from the IFF buffer.
* - LWO3 files are in IFF format and can contain the following data types, referred to by shorthand codes
*
* ATOMIC DATA TYPES
* ID Tag - 4x 7 bit uppercase ASCII chars: ID4
* sig def radians(degree: float) -> float:
"""
Coverts the given angle from degrees to radians
https://en.wikipedia.org/wiki/Radian
>>> radians(180)
3.141592653589793
>>> radians(92)
1.6057029118347832
License : No LicenseCopyfunction centroidRingPointFirst(lambda, phi) {
lambda00$2 = lambda, phi00$2 = phi;
lambda *= radians, phi *= radians;
centroidStream.point = centroidRingPoint;
var cosPhi = cos$1(phi);
x0 = cosPhi * cos$1(lambd >>> math.sin(math.radians(45))
0.7071067811865476
def cosine(x, n):
x = x % (2 * pi)
total = 0
for i in range(0, n + 1):
total += ((-1) ** i) * (x**(2*i) / math.factorial(2*i))
return total
def cosine(x, n):
x = x % (2 * pi)
if x &gimg = tf.image.random_crop(value = img, size=(2, 2))
img = tf.image.random_crop(value = img, size=(2, 2, 3))
img = tf.keras.preprocessing.image.random_rotation(img, 90, row_axis=0, col_axisdef computeAngle(arr):
# Naive inefficient algorithm
n, m = arr.shape
yCenter, xCenter = (n-1, m//2-1)
lineLen = m//2-2
sMax = 0.0
bestAngle = np.nan
for angle in np.arange(0, math.pi, math.pi/300):
i = import math
print('Enter the radians of the angle (a*π/b): ')
a = int(input('a value(top): '))
b = int(input('b value(bottom): '))
radians = ((a*math.pi)/b)
print('')
print('Finding...')
while radians > 2 * math.pi:
radians -= 2if radians > 0 and radians < (math.pi/2):
print(f'The angle {radians}rad is in the I quadrant')
elif radians > (math.pi/2) and radians < math.pi:
print(f'The angle {radians}rad is in the II quadrant')
elif radians >Community Discussions
Trending Discussions on radian
QUESTION
i am currently a bit stuck in programming a PROCESSING Sketch. Lets say I have a bunch of rectangles that move up the sketch window like bubbles… They have different sizing and color… And I want to let them rotate around its own axis while they move up. I tried using pushMatrix(); and popMatrix(); – and even translate(); but I guess its a bit more complicated because i use OoP and variables in the constructor for X and Y Position of each rectangle…
This is the code to my sketch:
...ANSWER
Answered 2021-Jun-14 at 18:01When rotating something in place, what usually works best is using translate in such a way that you're drawing it "at the origin". In your case, that means that you want to translate such that the first two parameters of rect() are both zero. So you translate, then rotate, then draw the rectangle "at the origin".
Solution:
QUESTION
I am currently a bit stuck! Lets say, have a grid of shapes (nested For-Loop) and I want to use a wave to animate it. The wave should have an offset. So far, i can achieve it. Currently the offset affects the Y-axis … But how can I manage to have a RADIAL offset – you know – like the clock hand, or a radar line… I really would like the offset to start from (width/2, height/2) – and then walks around clockwise. Here is my code and the point where I am stuck:
...ANSWER
Answered 2021-Jun-14 at 18:00Right now, you're defining the size of the ellipses based on a transformation of sin(y). A transformation means it looks like a * sin(b * y + c) + d, and in this case you have
a = tileSize / 2b = 300 / 60 = 5c = frameCountd = tileSize / 2
If you want to do a different pattern, you need to use a transformation of sin(theta) where theta is the "angle" of the dot (I put "angle" in quotes because it's really the angle from the vector from the center to the dot and some reference vector).
I suggest using the atan2() function.
Solution:
QUESTION
I've tried for the last few days without too much success to rotate, scale and translate shapes on the canvas. I've read everything I could find on internet about similar issues but still I cannot seem to be able to adapt it to my own problem.
If everything is drawn on the same scale, I can still drag and drop. If I rotate the shapes, then the mouseOver is messed up since the world coordinates don't correspond anymore with the shape coordinates.
If I scale, then it's impossible to select any shape.
I look at my code and do not understand what I'm doing wrong.
I read some really nice and detailed stackoverflow solutions to similar problems.
For example, user @blindman67 made a suggestion of using a setTransform helper and a getMouseLocal helper for getting the coordinates of the mouse relative to the transformed shape.
I spent some time with that and could not fix my issue. Here is an example of what I tried. Any suggestion is appreciated.
...ANSWER
Answered 2021-Jun-14 at 02:31If I have time tomorrow I will try to implement the following to your code but I can provide you with a working example of how to get mouse collision precision on a rotated rectangle. I had the same struggle with this and finally found a good explanation and code that I was able to get to work. Check out this website
Now for my own implementation I did not use the method on that website to get my vertices. As you'll see in my code I have a function called updateCorners() in my Square class. I also have objects called this.tl.x and this.tl.y (for each corner).
The formulas are what I use to get vertices of a translated and rotated rectangle and the corner objects are what are used to determine collision. From there I used the distance() function (Pythagorean theorem), the triangleArea() function, and then the clickHit() function which I renamed to collision() and changed some things.
Example in the snippet below
QUESTION
I want to make a angle class to be initialized in radians or degrees and I want to return the value and not the Angle object. I found out that named constructors would probably the most efficient way to do this but I am not a 100% sure how I would modify for my case.
...ANSWER
Answered 2021-Jun-13 at 12:16Your Angle class lacks an invariant. That is to say, there is nothing that can be said to be true about an arbitrary object of the Angle class beyond "it contains a double".
Consider this: If I write the following function:
QUESTION
When i call my funtion with a startingAngle=0 it produce a good shape with the correct size. Example:
...ANSWER
Answered 2021-Jun-09 at 21:00Your problem is one of mathematics. You said "As observed, the side length is 10px". It very definitely is not 10px. The distance from (10,5) to (5,0) is sqrt(5*5 + 5*5), which is 7.07. That's exactly what we expect for a square that is inscribed in a circle of radius 5: 5 x sqrt(2).
And that's what the other squares are as well.
FOLLOWUP
As an added bonus, here is a function that returns the radius of the circle that circumscribes a regular polygon with N sides of length L:
QUESTION
If have the following code which simulates a ball to Ball collision. My problem is, that the balls bounce against each other. I want to have the balls stick together like snow particles. Does anyone know how to do that?
...ANSWER
Answered 2021-Jun-11 at 12:47void resolveCollision(Particle& particle, Particle& otherParticle) {
float xVelocityDiff = particle.speed.x - otherParticle.speed.x;
float yVelocityDiff = particle.speed.y - otherParticle.speed.y;
float xDist = otherParticle.pos.x - particle.pos.x;
float yDist = otherParticle.pos.y - particle.pos.y;
// Prevent accidental overlap of particles
if (xVelocityDiff * xDist + yVelocityDiff * yDist >= 0) {
// Grab angle between the two colliding particles
float angle = -std::atan2(otherParticle.pos.y - particle.pos.y, otherParticle.pos.x - particle.pos.x);
// Store mass in var for better readability in collision equation
float m1 = particle.mass;
float m2 = otherParticle.mass;
// Velocity before equation
glm::vec3 u1 = rotateVel(particle.speed, angle);
glm::vec3 u2 = rotateVel(otherParticle.speed, angle);
// Velocity after 1d collision equation
glm::vec3 v1(u1.x * (m1 - m2) / (m1 + m2) + u2.x * 2 * m2 / (m1 + m2),
u1.y,
0.0);
glm::vec3 v2(u2.x * (m1 - m2) / (m1 + m2) + u1.x * 2 * m2 / (m1 + m2),
u2.y,
0.0);
// Final velocity after rotating axis back to original location
glm::vec3 vFinal1 = rotateVel(v1, -angle);
glm::vec3 vFinal2 = rotateVel(v2, -angle);
// Swap particle velocities for realistic bounce effect
particle.speed.x = vFinal1.x;
particle.speed.y = vFinal1.y;
otherParticle.speed.x = vFinal1.x;
otherParticle.speed.y = vFinal1.y;
}
}
QUESTION
Does anybody know why the following code doesn't find any Descendants named "PntList3D" in the XDocument? I've run similar code with xml files from different sources and it's worked just fine.
...ANSWER
Answered 2021-Jun-11 at 11:54You need to specify the namespace in your call for Descendants:
QUESTION
I have the following query that calculates the distance between two coordinates. However, I want to select the users that are within the range of n km. Say, for example, I want to select all users that are within a distance of 100km. Therefore, I have to use HAVING clause here. However, I see that the execution is damn too slow. Even with just two records it's returning the results very slowly. I wonder what would happen with a million user records (in future). Therefore, I am seeking an optimization to my current query for efficient and faster running.
ANSWER
Answered 2021-Jun-10 at 08:01The way to do what you want would be repeating the code on your select in the where section
QUESTION
Im not entirely sure what's wrong with my code. The eyes (iris) seem to be locked on the bottom right corner of the eyes and are rotating around on that fixed position. I've looked at tutorials online and tried variety of codes, but none seem to work. The end goal that I would like to achieve is to have the eyes follow the given block.
Thank you in advance!
...ANSWER
Answered 2021-Jun-10 at 09:27What you want is probably something more like this. This will translate the pupils into place, giving it that "following look".
QUESTION
I am trying to calculate the distance (in km) between different geolocations with latitude and longitude. I tried to use the code from this thread: Pandas Latitude-Longitude to distance between successive rows. However, I run into this error:
Does anyone know how to fix this issue?
...ANSWER
Answered 2021-Jun-10 at 00:30You're passing in a Series to the haversine function rather than a simple number for the lat and lon attributes.
I think you can use the apply function to apply the haversine to each row in the dataframe, however, I'm not too sure what the best way is for apply to be able to get hold of the next or previous row.
So, I'd just add a couple of extra columns 'from lat' and 'from lon'. Then you will have all the data you need on each row.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install radian
An installation of R (version 3.4.0 or above) is required to use radian, an R installation binary for your system can be downloaded from https://cran.r-project.org.
python (version 3.6 or above) is also required to install radian. If your system doesn't come with a python distribution, it can be downloaded from https://www.python.org/downloads/ or https://conda.io/en/latest/miniconda.html.
pip is optional but it makes the installation a bit easier.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
