Ransom | Various codes related to Ransomware Developement | Encryption library

 by   roothaxor Python Version: Current License: No License

kandi X-RAY | Ransom Summary

kandi X-RAY | Ransom Summary

Ransom is a Python library typically used in Security, Encryption applications. Ransom has no bugs, it has no vulnerabilities and it has low support. However Ransom build file is not available. You can download it from GitHub.

Various codes related to Ransomware Developement
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            kandi-support Support

              Ransom has a low active ecosystem.
              It has 117 star(s) with 82 fork(s). There are 15 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 3 have been closed. On average issues are closed in 33 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Ransom is current.

            kandi-Quality Quality

              Ransom has 0 bugs and 0 code smells.

            kandi-Security Security

              Ransom has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Ransom code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Ransom does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              Ransom releases are not available. You will need to build from source code and install.
              Ransom has no build file. You will be need to create the build yourself to build the component from source.
              Ransom saves you 214 person hours of effort in developing the same functionality from scratch.
              It has 524 lines of code, 16 functions and 2 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Ransom and discovered the below as its top functions. This is intended to give you an instant insight into Ransom implemented functionality, and help decide if they suit your requirements.
            • Generate a file
            • Encrypts a file using AES encryption
            • Make directory
            • Generate text generator
            • Find files in root directory
            • Write an instruction to a directory
            • Create remote desktop
            • Set wallpaper
            • Write the instruction file
            • Perform persistance
            • Destroy shadow copy
            • Delete file
            Get all kandi verified functions for this library.

            Ransom Key Features

            No Key Features are available at this moment for Ransom.

            Ransom Examples and Code Snippets

            This function is used to decrypt a piece of Markdown
            javascriptdot img1Lines of Code : 36dot img1no licencesLicense : No License
            copy iconCopy
            function ransomNoteFromMagazine(magazine, ransom) {
              var hash = {};
              var mLen = magazine.length;
              var rLen = ransom.length;
              var mIdx = 0;
              var rIdx = 0;
            
              while(rIdx < rLen) {
                var rc = ransom[rIdx];
            
                if(hash[rc] === undefined || has  
            Check if a ransom note can build a ransom note .
            pythondot img2Lines of Code : 9dot img2no licencesLicense : No License
            copy iconCopy
            def canConstruct(self, ransomNote: str, magazine: str) -> bool:
                    strs = string.ascii_lowercase
                    alpha = list(map(magazine.count,strs))
                    for i in ransomNote:
                        if (alpha[ord(i)-97] >0):
                            alpha[ord(i)  
            Determines if a ransom note can be found .
            pythondot img3Lines of Code : 7dot img3no licencesLicense : No License
            copy iconCopy
            def canConstruct(self, ransomNote: str, magazine: str) -> bool:
                    for i in range(len(ransomNote)):
                        if(magazine.find(ransomNote[i])>=0):
                            magazine = magazine.replace(ransomNote[i],'~',1)
                        else:
                     

            Community Discussions

            QUESTION

            Python cryptography.fernet file decrypt
            Asked 2021-Feb-05 at 08:37

            I am working on Ransomware for learning.

            So I Copy-and-pasted this and edited it like this but When I encrypt and decrypt a text file, it appends a string that looks like a random string. How can I fix this issue?

            like:

            ...

            ANSWER

            Answered 2021-Feb-05 at 08:37

            the problem is that you encrypt then decrypt. Your encryption and decryption function is working fine the issue is that you always seek to the beginning of the file to write any changes this will work fine with encryption and will work fine with decryption if the the plaintext and ciphertext is of same size(no padding) but will place decrypted plaintext that is not as same same size of ciphertext at beginning of file and leave the rest of file unchanged so you need to truncate the remainder part of ciphertext.

            Source https://stackoverflow.com/questions/66059279

            QUESTION

            Time Complexity Hash Table
            Asked 2020-Jul-29 at 16:13

            I implemented a simple algorithm in 2 ways. One using indexOf and other one using Hash Table.

            The problem: Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.

            First one. Is it Time Complexity O(N^2) because I have N letters in the ransomNote and I can do N searches in the indexOf?

            ...

            ANSWER

            Answered 2020-Jul-29 at 16:00

            The version with indexOf() is O(N*M), where N is the length of the ransom note, and M is the length of the magazine. You perform up to N searches, and each search is linear through the magazine array that's N characters. Also, array.splice() is O(M) because it has to copy all the array elements after index to the lower index.

            Hash table access and updates are generally considered to be O(1). The second version performs N hash table lookups and updates, so the overall complexity is O(N).

            Source https://stackoverflow.com/questions/63157411

            QUESTION

            Add div onclick using React, Gatsby, JavaScript
            Asked 2020-Jun-15 at 05:00

            Hello I am trying to add another container div on click. With my current code I am getting the error TypeError: document.getElementById(...) is null. I got this answer from a stackoverflow problem and I beleive it does not work because I am using react/gatsby.

            I have also tried having the inside of trello.js and I am still getting the same error.

            Trello.js:

            ...

            ANSWER

            Answered 2020-Jun-14 at 21:42
            import React from "react";
            
            export default function Button() {
              let click = () => {
                var div = document.createElement("div");
                div.innerHTML = "New DIV";
                div.className = "container";
                document.getElementsByTagName("body")[0].appendChild(div);
              };
            
              return (
                
                  Click Me
                
              );
            }
            

            Source https://stackoverflow.com/questions/62378267

            QUESTION

            Hackerrank Python3 Hash Tables: Ransom Note and dictionary comprehension
            Asked 2020-Jun-11 at 14:44

            I am learning Python, and i use it to solve tasks on HackerRank. I have the problem with exercise Hash Tables: Ransom Note. I have written that code:

            ...

            ANSWER

            Answered 2020-Jun-11 at 14:44

            You cannot referenze the varible your dict comp is assigned to inside itself - it does not update "iteratively".

            It is easy to show:

            Source https://stackoverflow.com/questions/62326895

            QUESTION

            Data encrypted due to ransomware named CERBER attack
            Asked 2020-May-17 at 14:01

            Back in 2016 all of my data on my laptop hard drive was encrypted by the CERBER ransomware. I refused to pay Ransome money to hacker.

            I have all of my important data preserved in an external hard disk. After 4 years now, I am hoping that some solution is there to decrypt my data.

            In these data, there are my childhood images which are once in a lifetime memories.

            Please guys I'll appreciate any kinda help. If you are professional then any premium support would work too.

            Can't wait to hear from you guys.

            Thank you so much in advanced, Siddharth shah

            ...

            ANSWER

            Answered 2020-May-17 at 13:49

            If you are looking for some tool to decrypt your encrypted files and if your extension of those encrypted files is something like

            {10 random characters}.cerber,

            Well, you are in luck!. There's a decryptor tool available. Here's the direct link : Trend micro decryptor

            Good luck!

            Source https://stackoverflow.com/questions/61852614

            QUESTION

            std::unordered_map::count is not working in my code
            Asked 2020-May-03 at 18:52

            I have a doubt with the solution of this question which is stated below -

            Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.

            Each letter in the magazine string can only be used once in your ransom note. Strings["aa", "ab"] should return false and strings["aa", "aab"] should return true according to question.

            Here is the code which I have attempted in the first place and I'm not getting a required output as mentioned above.

            ...

            ANSWER

            Answered 2020-May-03 at 18:52

            unordered_map::count returns the number of items with specified key.

            As you don't use multi_map version, you only have 0 or 1.

            Associated value doesn't change presence of key in map.

            To use count, you should remove key when value reaches 0:

            Source https://stackoverflow.com/questions/61578698

            QUESTION

            All the columns are in one column
            Asked 2020-Apr-16 at 18:01

            All I did was to import libraries and read the data. This is what I get:

            ...

            ANSWER

            Answered 2020-Apr-16 at 18:01

            Probably you are just missing the separator.

            Source https://stackoverflow.com/questions/61256717

            QUESTION

            Is it possible to place all the Kivy code in a python user function, called from Main?
            Asked 2020-Apr-10 at 10:19

            I'm using Kivy for a user interface to a control application. As such, the UI is subsidiary to the essential functionality. For modularity/tidyness, I've been trying to place all the Kivy code in a separate source file and to call it as the last step in Main.

            However, if I do this, I find that some things don't work properly (for example, creating labels programatically and updating their text by scheduled events).

            Is this something which should be possible? Is there a 'trick' of which I should be aware?

            If the detail of my question is not clear, I can put up some test code to illustrate.

            Monolithic code, which works as expected:

            ...

            ANSWER

            Answered 2020-Apr-10 at 10:19

            You don't have any code that would change the text of your Label. Although you update self.random_number, you don't update the Label's text property, therefore you don't see any change.

            Source https://stackoverflow.com/questions/61103450

            QUESTION

            Removing words in list - loop malfunction
            Asked 2019-Nov-16 at 18:34

            I have written a simple for loop meant to check if all of the words in one list are found in a larger list. It is a practice question found here.

            I do not understand why my function does not execute properly - After running it, what is left in the sample list "note2" is ['one','today'], so it seems like the loop is somehow skipping over those words. Why is that?! I do not understand it conceptually.

            Thank you for your help on this.

            Example lists (two pairs of examples):

            ...

            ANSWER

            Answered 2019-Nov-16 at 18:34

            In the loop you remove elements from the list and then word is looking at the elements of the reduced list.

            Copy the lists in the for loop line using note[:]:

            Source https://stackoverflow.com/questions/58893194

            QUESTION

            dividing tables into sub-tables
            Asked 2019-Oct-07 at 09:59
            var word=[
                            [
                                "0. wordAng - wordPl 1. gap year -  rok przerwy po ukonczeniu szkoly sredniej 2. safety course -  kurs zasad bezpieczenstwa 3. increase -  zwiekszac sie (o ilosci/jakosci)4. decrease -  zmniejszac sie (o ilosci/jakosci) 5. within walking distance -  w odleglosci, ktora mozna pokonac pieszo 6. mention -  wspomniec o czyms 7. overland -  droga ladowa / naziemny 8. memorable -  niezapomniany/ godny zapamietania  9. sign up with -  zapisac sie/zaangazowac/zwiazac sie z  10. deliverer -  doreczyciel/dostawca 11. paragliding -  paralotnia 12. placement -  polozenie/lokalizacja 13. research -  badania naukowe 14. expences -  wydatki 15. cruise ship -  statek rejsowy 16. on board -  na pokladzie 17. off the coast -  z daleka od brzegu 18. available -  dostepne 19. working hours -  godziny pracy 20. deal with -  radzic sobie z 21. counsellor -  doradca/opiekun 22. freelance - pracowac jako wolny strzelec 23. call back -  oddzwonic pozniej 24. take on -  zatrudniac 25. hold a certificate -  posiadac dyplom 26. put through -  polaczyc przez telefon 27. flood -  powodz 28. volcanic eruption -  wybuch wulkanu 29. drought -  susza 30. pollution - zanieczyszczenie 31. earthquake -  trzesienie ziemi 32. pump out -  wypompowywac/emitowac 33. toward -  w kierunku 34. grow - rosnac/uprawiac 35. canoe -  kajak 36. fireworks -  fajerwerki 37. light up - rozswietlic 38. sheke - trzasc sie 39. fall off -  spadac/odpadac 40. twister -  tornado/traba powietrzna 41. calm -  spokojny/nieporuszony 42. weatherman -  prezenter pogody 43. strike -  uderzyc/nadejsc/dopasc 44. pray -  modlic sie 45. prayer -  modlitwa 46. put down -  wpisywac/klasc 47. huge -  ogromny/olbrzymi 48. directly - bezposrednio 49. unexpected -  nieoczekiwany 50. expected -  oczekiwany 51. chase -  gonic/scigac 52. awake -  obudzony/przebudzony/obudzic/przebudzic sie 53. prediction -  przewidywanie 54. predict -  przewidywac 55. spontaneous decision -  decyzja spontaniczna 56. global warming -  globalne ocieplenie 57. rising level -  podnoszacy sie poziom 58. cover -  przykrywac/pokrywac/przykrywa/pokrywa (czasownik i rzeczownik) 59. glacier -  lodowiec 60. well -  studnia 61. cause -  powodowac 62. precious -  drogocanny 63. collect donations -  zbierac datki 64. fossil fuel -  paliwo kopalne 65. ice cap -  pokrywa lodowa 66. blanket -  koc 67. shortage -  brak/niedobor 68. leak -  przeciekac/wyciek 69. dispose of -  unieszkodliwic/uporac sie z 70. dump -  sklad/zrzut 71. breed -  rasa/gatunek 72. die out -  wymrzec/wyginac 73. scarce -  rzadki/malo spotykany 74. look for -  szukac 75. look after -  opiekowac sie 76. cub -  kocie/mlode 77. cuddly -  milutki 78. fierce-looking -  wygladajacy groznie 79. habitat -  srodowisko/miejsce wystepowania 80. in case of -  w razie/jesli wystapi"
                    ],
                            [
                                "0. wordAng - wordPl 1. alidi - alidi 2. at gunpoint - pod grozba uzycia broni 3. beat sb up - pobic 4. burglar - wlamywacz 5. commit a crime - popelnic przestepstwo 6. criminal - przestepca 7. escape - uciekac 8. force - sila 9. forger - falszerz 10. get out of - wyjsc 11. getaway - ucieczka 12. hand over - przekazywac 13. hand sth in - wreczyc 14. hide - ukryc 15. hold up - napad rabunkowy 16. illegal - nielegalny 17. mugger - bandyta 18. mugging - kradzierz z rozbojem 19. murder - morderstwo 20. murderer - morderca 21. pickpocket - kieszonkowiec 22. prisoner - wiezien 23. ransom - okup 24. rob - rabowac 25. robber - zlodziej 26. robbery - napad  27. shoplifter - zlodziej sklepowy 28. shoplifting - kradzierz sklepowa 29. suspect - podejrzany 30. suspicious - podejrzany 31. suspiciously - podejrzliwie 32. theft - kradziez 33. thieft - zlodziej 34. threaten - grozic 35. tick off - dawac reprymende 36. violence - przemoc 37. appear - pojawiac sie 38. appearence - wygląd 39. author - autor 40. carry out duties - wypelniac obowiazki 41. clever diagnosis - inteligentan diagnoza 42. come out - ukazac sie 43. cuff - mankiet 44. carved pipe - rzezbiona fajka 45. deduce - wnioskowac 46. diary - dziennik 47. edition - wydanie 48. fictional - fikcyjny 49. immediate success - natychmiastowy sukces 50. indicate - wskazywac 51. insult - zniewazac 52. magnifying glass - szklo powiekszajace 53. notice - zauwazyc 54. observation - obserwacja 55. plot - fabula 56. relationships - kontakty 57. shopkeeper - kupiec 58. smooth patch - gładka lata 59. solve mysteries - rozwiazywac zagadki 60. tattoo - tatuaz 61. tradesman - handlowiec 62. trai - szkolic 63. who is behind it - kto za tym stoi 64. accuse sb of sth - oskarzyc kogos o cos 65. accused of - oskarzony o 66. arrest - aresztowac 67. cctv - kamera przemyslowa 68. avidence - dowody 69. fill in a form - wypelniac formularz 70. fingerprint - odcisk palca 71. forensic - sadowy 72. murder case - sprawa o morderstwo 73. proof - dowod 74. prosecute - oskarzac 75. punish - karac kogos 76. report - raport 77. scene of crime - miejsce przestepstwa 78. traces - slady 79. confess guilt - przyznawac sie do winy 80. court -sad 81. defendant - oskarzony 82. end up in jail - trafic do wiezienia 83. go on trial - miec proces 84. guilty - winny 85. innocent - niewinny 86. judge - sedzia 87. jury - lawa przysieglych 88. lawer - prawnik 89. make statements under oath - zeznawac pod przysiega 90. minor - drobny 91. pass sentence - wydawac wyrok 92. sentence sombady to - skazywac kogos na 93. try - sadzic 94. under oath - pod przysiega 95. victim - ofiara 96. witness - slabosc"
                            ]
                        ];
            
            ...

            ANSWER

            Answered 2019-Oct-07 at 09:59

            I think you want to split by number and then split by hyphen. For example,

            Source https://stackoverflow.com/questions/58267108

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Ransom

            You can download it from GitHub.
            You can use Ransom like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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