startapp | Simple boilerplate ready for development bowtie | REST library

 by   sabuhish Python Version: 0.2.0.0 License: MIT

kandi X-RAY | startapp Summary

kandi X-RAY | startapp Summary

startapp is a Python library typically used in Web Services, REST, Boilerplate, Nginx, Fastapi, Docker, Swagger applications. startapp has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub.

Simple boilerplate ready for development.
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            kandi-support Support

              startapp has a low active ecosystem.
              It has 11 star(s) with 4 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              startapp has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of startapp is 0.2.0.0

            kandi-Quality Quality

              startapp has 0 bugs and 0 code smells.

            kandi-Security Security

              startapp has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              startapp code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              startapp is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              startapp releases are available to install and integrate.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              It has 1363 lines of code, 29 functions and 44 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed startapp and discovered the below as its top functions. This is intended to give you an instant insight into startapp implemented functionality, and help decide if they suit your requirements.
            • Start an application
            • Create the app structure
            • Create the directory structure
            • Check to see if file exists
            • Check if file exists
            • Print a message to stdout
            • Start the application
            • Execute the builder
            • Ends the app
            • Install dependencies
            • Create file
            • Runs virtualenv
            • Create the root folder
            • Create the root directory
            Get all kandi verified functions for this library.

            startapp Key Features

            No Key Features are available at this moment for startapp.

            startapp Examples and Code Snippets

            No Code Snippets are available at this moment for startapp.

            Community Discussions

            QUESTION

            Android Studio Can't Startup
            Asked 2022-Mar-24 at 10:09

            Android studio was working correctly until I restore default setting from File->Manage IDE Settings->Restore Default Setting, Then I can't startup it again.

            Every time I run Android studio I got this error

            I tried to uninstall it and remove settings and SDK then install it again but also it didn't work

            This is The error

            ...

            ANSWER

            Answered 2022-Mar-24 at 10:09

            I solve this issue by deleting a file AppData\Local\Google\AndroidStudioxxxx.x Then uninstall Android studio and install it again

            Source https://stackoverflow.com/questions/71599331

            QUESTION

            Script calls other script as .ps1 but not as a .exe using ps2exe
            Asked 2022-Feb-15 at 16:13
            $password = ConvertTo-SecureString “Password+++” -AsPlainText -Force
            $Cred = New-Object System.Management.Automation.PSCredential ("Admin", $password)
            $FileLocale = Split-Path -Parent -Path $MyInvocation.MyCommand.Definition
            Write-Output $FileLocale
            $AntFile = "$FileLocale\StartApps.ps1"
            Write-Output $AntFile
            Start-Process PowerShell.exe -ArgumentList "-command &$AntFile -UserCredential $Cred"  
            
            ...

            ANSWER

            Answered 2022-Feb-15 at 16:13

            While an executable compiled with ps2exe uses a .ps1 file as input, at runtime no actual .ps1 file is involved, which is why PowerShell's command-reflection variables cannot tell you anything about a running script file.

            When running an actual .ps1 file, you'd use the following about_Automatic_Variables:

            • $PSCommandPath contains the the executing script file's full file path.

            • $PSScriptRoot contains the script file's full directory path (i.e. the full path of the directory in which the script file is located).

            In a ps2exe-compiled executable (.exe), where these variables have no values, you can use the following instead:

            • [Environment]::GetCommandLineArgs()[0] contains the executable file's full file path.

            • Split-Path -LiteralPath ([Environment]::GetCommandLineArgs()[0]) contains the executable file's full directory path.

            Applied to your code - assuming that a separate StartApp.ps1 file is present alongside your .exe file:[1]

            Source https://stackoverflow.com/questions/71127896

            QUESTION

            ImportError: Couldn't import Django inside virtual environment with poetry?
            Asked 2022-Jan-31 at 06:29

            I created a django project, set up a virtual environment, and added django with poetry add.

            inside pyproject.toml:

            ...

            ANSWER

            Answered 2022-Jan-31 at 06:29

            It seems that you have manually created a virtual env in the project directory by e.g. python -m venv venv. So now you have one in /home/tesla/Documents/projects/graphql/graphenee/venv/.

            After that you added some packages with poetry. However, by default poetry will only look for .venv directory (note the starting dot) in the project directory. Since poetry did not find a .venv, it created a new virtual env in /home/tesla/.cache/pypoetry/virtualenvs/graphenee-CXeG5cZ_-py3.9 and installed the packages you added via poetry add there.

            The problem is that you try to use the "empty" virtual env in the project directory instead of the one created by poetry. Fortunately with poetry it is very easy to run command, even without activating the venv, just use poetry run in the project directory.

            To check Django installation:

            Source https://stackoverflow.com/questions/70907702

            QUESTION

            Django - Not being able to merge front end to backend
            Asked 2022-Jan-30 at 13:51

            Im learning programming and im completely new in it..i was working on a project and i have used django for back-end. Now the problem im currenctly facing is that i got no idea how should i link frontend and backend ?.. first we created backend (where there is login/signup/and dashboard) using django and boostrap,js .. and the backend work perfectly so below the folder structure of the backend we are working on.

            so this is the structure of the backend .. to be more clear check 2nd image.

            Here you can see that, budgetwebsite folder which is just below the folder authentication. budgetwebsite is our main thing or a part of our system..

            then we did django startapp for authentication(for username validation and email)

            then we did django startapp for userincome(here we worked on userincome like add/delete income)

            then we did django startapp for expenses(here we worked on expenses like add/delete/expense)

            and that userpreference is our admin panel.

            thats for the backend section

            Now lets move on the front end section aswell.

            then we created a different folder name front end and we started working on it.

            So now lets move to the problem... i just want to merge this front end and back end ..

            below is my code of setting.py

            ...

            ANSWER

            Answered 2022-Jan-30 at 13:51

            Let's assume you want the user to get the expense app to open when he first visits your wesite

            So the expense app will have it's own views.py and you have to create a urls.py for it and also all the other apps too.

            now in the urls.py file of the expense you have to write the url patternss for that app

            urls.py

            Source https://stackoverflow.com/questions/70915016

            QUESTION

            empty path breaks after adding the first app in django
            Asked 2022-Jan-23 at 16:05

            I created a new django app and ran it using python manage.py runserver . It ran normal and I could see the default page

            With the shell outputting:

            ...

            ANSWER

            Answered 2022-Jan-23 at 16:05

            You didn't do anything wrong, the default django page only shows if you don't have any other url patterns to try (Github)

            Now you need to add a path at / or you can just call the django one if you'd prefer

            Source https://stackoverflow.com/questions/70823874

            QUESTION

            Django: Fetching data from an open source API
            Asked 2022-Jan-18 at 22:56

            I am trying to fetch public holiday data for France, Australia and Germany from https://date.nager.at/ with the documentation at https://date.nager.at/swagger/index.html and store it in a JSON file.

            Until now, I have created an endpoint /fetch_and_save with its own URL, but only managed to write dummy data in the views.py file. How do I fetch the data above and store it in a database through Django?

            Edit: I have been asked to show the code. I ran

            ...

            ANSWER

            Answered 2022-Jan-18 at 22:56

            Here you have some clues, how to do that in simple way:

            fetch_and_save/views.py

            Source https://stackoverflow.com/questions/70762827

            QUESTION

            Realm accessed from incorrect thread using async and await
            Asked 2021-Dec-20 at 06:27

            Running the code below i get "Realm accessed from incorrect thread." error on the second try! realm.write({ line , the first write line causes no error. Any idea on how to fix it?

            ...

            ANSWER

            Answered 2021-Dec-20 at 06:27

            i fixed with the below , removed the await Realm() and consolidated writes into one

            Source https://stackoverflow.com/questions/70346625

            QUESTION

            Django error 'ModuleNotFoundError: No module named 'ocore'
            Asked 2021-Dec-08 at 06:51

            New to Django and have just started building out a new project following a tutorial.

            I have created a virtual environment as follows:

            pip install virtualenv

            virtualenv myproject_3_7_3

            I then activate the virtual env and install Django as follows:

            cd myproject_3_7_3

            source bin/activate

            pip install django

            This installs Django version 3.2.10 successfully, so then I activate the project, add some folder structure and create an app using the following commands:

            django-admin startproject myproject

            cd myproject

            mkdir apps

            mkdir apps/core

            python manage.py startapp core apps/core

            I then open VSCode and I can see the project and all of the default folders/files there.

            To start the app I run:

            python manage.py startapp core apps/core

            But I immediately get the following error in the terminal.

            ...

            ANSWER

            Answered 2021-Dec-08 at 06:51
            Spelling mistake

            I tried to replicate your error.

            While creating the app you mistakenly created with name "ocore".

            But in settings.py

            Source https://stackoverflow.com/questions/70267381

            QUESTION

            How are applications (which accepts different types of requests like http and smtp) deployed on different ports on servers?
            Asked 2021-Nov-06 at 10:00

            I'm a beginner in all these http and tcp/ip thing. So there maybe many things in these questions that may not make sense or are totally incorrect.

            First I will add all the questions I had in mind since, I could not put them on title.

            I work on django (python framework) for web development.

            I'm confused as to how servers work. And how is the destination port is decided through the url?

            MAIN Q : What I have learned so far is that through DNS we get the ip address of the website. And port (Both destination and source) are decided by the TCP. And sent through TCP headers. But how does it decide which port should it go to in a server(i.e. destination port).

            MY ANS TO ABOVE QUESTION : After spending lots of my time, I have come to know that, http requests default to 80 and https defaults to 443 and similarly other types of requests also defaults to some port. So we can figure out the ip address based on this.

            But this rises another question in my mind.

            Another Question : I have also built a simple django website and deployed it on pythonanywhere. But I deployed it as a whole application. Suppose my django application accepts different types of requests like HTTP, HTTPS, SMTP, etc. Then how will the port for these specific tasks be decided? Because all these requests will come under single application, so they should run on the same port. I don't think the server will change anything in the application itself. So how will the destination port now be decided?

            NOTE : I'm not sure if it is possible to make an application in django which accepts different types of requests. But it should be possible because we can create different app - with startapp and run on different url.

            Where ever I read, it said that the default port for http is 80, then that means it should also be possible to change it?

            MOST IMPORTANT QUES AND TO SUMMARIZE ALL DOUBTS Suppose I have a project which accepts different requests. And I want to deploy it on server then how will http requests and smtp requests are separated? Do I have to manually make different apps and then deploy on different ports or something? If not and everything runs on same port, then how is this port decided in the browser? Suppose my domain name is xyz.com then how will the specific port be accessed on the server?

            Basically how is a destination port decided?

            ...

            ANSWER

            Answered 2021-Nov-06 at 10:00

            As you have already seen, protocols generally have a default assigned port (80 for http, 443 for https, 25 for smtp, ...). The main protocols in use on the Internet have their port assigned by the IANA.

            Some applications also use a port by default (for example, the database service PostreSQL is configured by default to use the port 5432). https://web.mit.edu/rhel-doc/4/RH-DOCS/rhel-sg-en-4/ch-ports.html

            Most of the time you can omit the port, because the application you use know the default and use it for you. When you ask your web browser to send a request to http://example.com, behind the scene the request is sent to http://example.com:80.

            You can configure your applications to listen on a different port than their default. People might want to do this for different purposes (non-exhaustive list):

            • for security (changing the port used by a service to make harder for attackers to know this service is present -not using port 22 for ssh)
            • because some port ranges require some privileges. Your operating system require a root/admin account to use the ports below 1024 (that is why development tools uses some exotic ports by default -as 8080 or 8000 for web server-, the use of non-admin account is expected). Most ISPs block port 25 on their Internet boxes to prevent spam. Etc.
            • because of conflicts (the port is already taken)

            Changing the ports this way can be configuration-heavy (you have to configure the service and all its clients).

            Now, the other part of the question : how can the same port be used by different services?

            If you want to expose different services on the same port you can use something like a reverse proxy. It is an application that listen on a port and redirect the traffic based on rules, and sometimes they offer the possibility to modify the content (to name a few: Traefik, Caddy. General web servers also have reverse proxy capabilities: Nginx, Apache with mod_proxy, ...).

            For example, imagine you have 2 web applications and you want them to be accessible on port 80. You could configure these applications to use different ports (let's say 8080 and 8081), have the reverse proxy to listen on port 80 and redirect requests based on the url used (it could redirect app1.example.com:80 to localhost:8080 and app2.example.com:80 to localhost:8081). Only port 80 has to be accessible from the outside.

            Source https://stackoverflow.com/questions/69862445

            QUESTION

            I have to use ctrl+s everytime to updatde UI . Setstate() not working. Where to use setstate() properly?
            Asked 2021-Oct-05 at 08:49

            I I'm writing a code for weather application, with only two screens. And I'm using openWeatherApi to fetch weather data using http protocol from json file which is present on internet, to my weather UI. Now the the issue is that,the data from json is coming perfectly to terminal,but It does not come to UI screen until I press ctrl+s.The UI does not updates until I press ctl+S. When I run the code first time It does not show the current weather status(which is in Celsius degree),it just shows null, a written null on the screen,where current weather should be shown, and also the image behaves like that as well. Now I'm not getting is a setstate() issue or else. I don't know why the UI is not updating.I'm providing every file that I'm using. Please Help!.

            Flutter Doctor

            ...

            ANSWER

            Answered 2021-Oct-05 at 08:49

            You are not calling setState in the right place, set state should be called after you have retrieved the data from the api, here is how you can fix that in the weather_page.dart :

            Source https://stackoverflow.com/questions/69440227

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install startapp

            You can download it from GitHub.
            You can use startapp like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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