jolla | Python Web Framework | REST library
kandi X-RAY | jolla Summary
kandi X-RAY | jolla Summary
jolla is a pure API server framework,and it is based on the gevent. When I wrote Jolla,what I want to do is a high performance API server for you to simply obey its short rule,and get your calculation result fast be sent to browser or mobile for your service.so I made Jolla as simple as possible. Hope you guys like it.
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Top functions reviewed by kandi - BETA
- View of a blog
- Get the value of the key
- Add a value to the cache
- Return q data
- Add q value
- Render data as JSON
- Render the index page
- Render a template file
jolla Key Features
jolla Examples and Code Snippets
soup = BeautifulSoup(html,"html.parser")
print(soup.ip)
>>> "134.201.250.155"
#!/usr/bin/env python3
import fileinput
with fileinput.FileInput(filename, inplace=True, backup='.bak') as file:
for line in file:
print(line.replace(text_to_search, replacement_text), end='')
cities = r"new york|dallas|rochester|houston|san diego"
print (df['string'].str.findall(cities)
.apply(lambda x: x if len(x) >= 1 else ['no match val'])
.str[-1])
0 rochester
1 housto
cities = r"new york|dallas|..."
def last_match(s):
found = re.findall(cities, s)
return found[-1] if found else ""
df['string'].apply(last_match)
#0 rochester
#1 houston
#2 san diego
#3
Community Discussions
Trending Discussions on jolla
QUESTION
I want to extract the all addresses from this string. The regex should be generic.
Input string:
...ANSWER
Answered 2020-May-26 at 13:32You can use String.split() function or StringTokenizer class to split a comma separated String in Java.
QUESTION
I am getting a syntax error on line 16 denoting "bad string"
Not sure what is wrong here.
...ANSWER
Answered 2019-Jul-29 at 05:38At the first look, the JSON given to the question looks good. However, there are few issues. To understand it, let's remove some data and make it simple. So, here is the simple JSON that has issues.
QUESTION
This is a further question from how to create data frames (not just one) at once in r. I really can't understand the error message. I have two data frames:
...ANSWER
Answered 2018-Dec-07 at 03:35# this is a nice library for R
library(tidyverse)
# name your variables
# (you can use these as arguments to a function or something)
start = place$name[7]
end = place$name[8]
# wrap your computation into a function which takes
# a row of a data frame as input
compute_route_time = function(row) {
# get a vector of stops that you can loop through
stops = unlist(row)
# distance from start to first stop
time = mapdist(from = start, to = stops[1])$seconds
# iterate through the rest of the route
n_stops = length(stops)
for (i in 1:(n_stops-1)) {
time = time + mapdist(from = stops[i], to = stops[i+1])$seconds
}
# finish rout
time = time + mapdist(from = stops[n_stops], to = end)$seconds
# collect row as a data frame to preserve old columns
row = as.data.frame(row)
# add time column
row$time = time
return(row)
}
route1 %>%
dplyr::rowwise() %>%
dplyr::do(compute_route_time(.))
QUESTION
from urllib.request import urlopen
from bs4 import BeautifulSoup
apikey='*****d2deb67f650f022ae13d07*****'
first='http://api.ipstack.com/'
ip='134.201.250.155'
third='?access_key='
print(first+ip+third+apikey)
#html=urlopen(first+ip+third+apikey)
soup=BeautifulSoup(html,"html.parser")
print(soup)
...ANSWER
Answered 2018-Nov-30 at 13:26The documentation is very helpful here - what you need to do is in there:
QUESTION
I got a list of Variables of unequal size
...ANSWER
Answered 2018-Nov-03 at 13:22I would use merge
. I try to provide a minimal domain-agnostic working example:
QUESTION
With a data frame df like below
...ANSWER
Answered 2018-Sep-21 at 07:40By using dplyr
you could do something like this.
QUESTION
I have a dataframe containing house price data, with price and lots of variables. One of these variables is a "sub-area" for the property, and I am trying to incorporate this into various regressions. However, it is a factor variable with almost 3000 levels.
For example:
...ANSWER
Answered 2018-May-25 at 14:47You didn't give a reproducible example, but I think this will work for identifying those places which count==1
QUESTION
I have a DataFrame with thousands of rows and two columns like so:
...ANSWER
Answered 2017-Sep-04 at 06:15cities = r"new york|dallas|..."
def last_match(s):
found = re.findall(cities, s)
return found[-1] if found else ""
df['string'].apply(last_match)
#0 rochester
#1 houston
#2 san diego
#3
QUESTION
I have an RDD of type Elem:
...ANSWER
Answered 2017-Aug-11 at 20:32Solved it by converting the RDD[Elem]
into a List[Elem]
:
QUESTION
I have the following ui.R
...ANSWER
Answered 2017-Apr-20 at 06:26You do not have any input called input$location_description
It should be
plotData <- subset(zones, pressure_zone_name==input$zones & location_description==input$sampleLocation)
instead of
plotData <- subset(zones, pressure_zone_name==input$zones &
location_description==input$location_description)
EDIT
Sorry for missing out the main point of the question.Since availablelocations
is a data.frame
your updateSelectInput
should be as follows :
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