cyper | Cython performed inline : compile and run your Cython | Data Manipulation library
kandi X-RAY | cyper Summary
kandi X-RAY | cyper Summary
Cython performed inline: compile and run your Cython snippets on the fly. It is aiming to provide a flexible alternative to the IPython Cython magic command outside the IPython/Jupyter environment.
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Top functions reviewed by kandi - BETA
- inline code .
- Update flags based on code .
- Suppress compiler output .
- Context manager to set environment variables .
- Build a cython build .
- Exports module to target .
- Load a module .
- Return the directory of the given frame .
- Return the name of the SO extension .
- Join two paths together .
cyper Key Features
cyper Examples and Code Snippets
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Trending Discussions on cyper
QUESTION
ANSWER
Answered 2021-Sep-16 at 13:04The quotation marks in your query results indicate that this property is stored as a string. The order by
is therefore alphabetical, not numeric. Try casting the results (or the property itself) to an int.
QUESTION
Neo4j version: 3.5.16
What kind of API / driver do you use: Python API with py2neo to run the query with graph.run()
Py2neo version: 4.3.0.
Hey all,
I'm trying to optimize a cypher query to retrieve a variable length path.
The graph is created each time data arrives and startNode and endNode are fixed on their name property. Once created the graph, I have a startNode and an endNode and the corolllary/objective is:
"From all the possible paths with a minimum length of X and a maximum length of Y, I want to find the shortest path that yields the highest aggregated relationship value".
What I actually have managed to do is: "get the path of length between X and Y that yields the highest aggregated relationship value" with the following cyper query:
...ANSWER
Answered 2020-Mar-27 at 13:53Since you are basically looking for strongest one in shortest length. You can come around the performance problem with a trick. You can query the graph with fixed length than variable length. But you have to query n2-n1+1 times , in your case , 4 times , first with length 4, and then 5 and so on . You can stop querying if you find a path at any point. This approach will tremendously decrease the data loaded each time. But you have to hit the graph multiple times.Its most likely that average time taken for four hits approach will be less than single hit with variable length. The reason being you don't calculate all the paths of higher length if you find a lower length solution. Since,longer the path gets, the time taken will grow exponentially.
This is not possible only using cypher . One way is writing neo4j procedure in java and using that in cypher query . The second way is : hitting neo4j using different query. i am writing python code for your case here ,
QUESTION
I want to achieve the basic task of connection to a neo4j database using C++.
For this, I got libneo4j-client and copied the code from https://neo4j-client.net/. Compilation works fine.
Now I executed the following code:
...ANSWER
Answered 2020-Mar-06 at 11:08The problem was solved by downgrading the version of Neo4J.
Version 4.0.1 uses a higher version of the bolt protocol, which isn't documented so far, and thus not used by neo4j-client
.
Version 3.5 uses the old protocol (bolt version 1) and is thus compatible.
QUESTION
To create and save a Node in Neo4J using py2Neo. We do.
...ANSWER
Answered 2020-Feb-09 at 20:52You can just supply the labels as extra arguments:
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Installation: pip install cyper
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