connect-4 | Connect 4 That Was Made In Python | Download Utils library
kandi X-RAY | connect-4 Summary
kandi X-RAY | connect-4 Summary
Connect 4 That Was Made In Python
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Top functions reviewed by kandi - BETA
- Minimax minimax the ladder
- Score piece
- Checks if a piece is the winning move
- Evaluate the player s score
- Return a list of valid locations
- Find the next open row in the board
- Drop piece from a piece
- Checks if the given column is a valid location
- Check if the board is a terminal node
- Pick a piece from the board
- Draw a board
- Find the next open open row in the board
- Create a board
- Drops piece from board
- Print a board
connect-4 Key Features
connect-4 Examples and Code Snippets
Community Discussions
Trending Discussions on connect-4
QUESTION
I'm trying to validate my websites SSL certificate with help from the tls_certificate_check library, Elixir and some calls to the Erlang :ssl module. The end goal is get the expiration date of the certificate, and maybe some other metadata. Here is my code:
ANSWER
Answered 2021-Nov-18 at 23:32It turns out that I should be using a charstring and not a string for the host parameter:
QUESTION
I'm trying to create a simple connect-4 game using NumPy's 2D arrays, The idea is to when a player chooses a column, It will replace the largest number in that column with a piece
...ANSWER
Answered 2021-Oct-09 at 15:57The output of np.max is a scalar value, and is not your matrix. You want to use np.argmax. This will output the position of the maximum value (or list of positions, if many).
You can use the following code to implement the desired behavior:
QUESTION
class Board:
def __init__(self, N):
'''Board for a Connect-N game, the board will have N+2 Col and N+3 Rows'''
self.num_row = N + 3
self.num_col = N + 2
self.cols = [Column(self.num_row) for i in range(self.num_col)]
self.row = [Column(self.num_col) for i in range(self.num_row)]
pass
#return
def display(self):
'''display the board'''
print ('\u26AA' '\u26AB')
#for rown in range(3):
# for col in range(2):
# btn = tk.Button(width = '5',height = '2', text = '')
# btn.bind("", on_btn_click)
# btn.grid(row = rown, column = col )
def drop_disk(self, c):
'''drop a disk at column c'''
pass
def check_winning_condition(self):
'''check if there is a winner'''
return True
class Column:
def __init__(self, r):
'''each column has r rows'''
self.rows = [0]*r
N = 4 #standard Connect-4
board = Board(N)
board.display()
ANSWER
Answered 2020-Nov-07 at 09:41You can use the __str__ method to print your board:
Once the game works the way you need, you can easily build a GUI with tkinter around it, in a separate set of files.
In the following example, I am using a list of lists to represent the board. I changed the settings to represent the traditional 6 rows and 7 columns of connect-4.
QUESTION
So I am trying to make a text-based game of connect-4 for the purposes of better understanding Python and how it actually works.
Short version
- How can I append printed text from every run-through of a while loop to a print output that exists just before the while loop
- Out of the two methods seen below (The work in progress and the current successfully working one) which is a better practice of executing the desired output?
Long version
I am trying to use a looping system to print out an array in an evenly spaced and aesthetically pleasing format after every turn is taken, so users have clear feedback of what the current board looks like before the next turn is taken. To do this I want to be able to have lines of code that are as small as possible for making it easier to read the code itself. Although this might not be the best practice for executing this scenario I want to understand this way of coding better so I could apply it to future projects if need be.
In terms of the actual execution, I am trying to use a while loop to append 7 positions of an array one after another in the same output line for array positions that are in the same row. after this, I want to print the next row on the line below the previous one as seen in the code below "Desired output".
Thank you in advance for your answers, suggestions and comments.
Work in progress
...ANSWER
Answered 2020-Jun-07 at 12:46The simple fix is to use end=' ' on the print inside the while loop on j and then add a print() after it:
QUESTION
I tried to make a MiniMax AI using a tutorial,
The AI doesn't work and just goes on the bottom row and build up each time, reporting a column index of 0, 1, 2, 3, 4, 5, 6 and then for the next row and so on. The only thing I managed to find a lot different in the code output compared to mine and the tutorials working version was the depth of the minimax algorithm as it goes along. Where this was the depth of the working one as it recurred, and this was the depth of my one (it was longer than this but my console didn't keep all of it). I've tried a lot of things to get it working including reworking the board system to multiple lists inside a list and many other things like deleting some parts of the code and reworking scores but it doesn't seem to change.
My minimax function is:
...ANSWER
Answered 2020-May-05 at 17:35The board is passed passed to your minimax function as a parameter node, but inside the function you use board.
Reference program: def minimax(board, depth, alpha, beta, maximizingPlayer):
Your program: def minimax(node, depth, alpha, beta, maximizingPlayer):
Your recursive minimax function is therefore not working as expected.
Edit: To fix this replace board inside minimax with node (don't change node in the function definition to board)
Edit 2: Also check the function scorePos - you have a hardcoded computerDisc instead of using the function argument.
Edit 3: Additionally, other helper functions like isBoardFull() and isSpaceFree() should operate on the board copy, not the global variable.
QUESTION
I'm writing a connect-4 game with Tkinter, and I would to present several menu options to the user during the course of the game.
The problem is that the menus tend to be presented together, as in the piece of code below. For example, in present_player_choice(), I'd like to present a menu for playerA, get an answer, and then present a menu for playerB. This is not that crucial here, but it's a problem I keep running across.
after() does not seem to be the answer, as I do not want the menu to disappear after a certain space of time, but rather to disappear after the user has submitted an answer.
Also: In writing an 'ok' button for the menu, I've used 'quit.' But quit closes the entire widget! I want the gui to continue, and simply the menu to close, not the entire GUI!
I know these questions sound rather clueless, but I've been working on this for a while and am genuinely confused. Thanks in advance for any help.
...ANSWER
Answered 2020-Feb-19 at 14:24The quickest way to do this is to add a Frame to your class that we can use to reset the content and then move the call for player B into a condition in the assign_player method to update the frame for player B when a selection is chosen.
You may also want to add tristatevalue=0 to your radio buttons so that there is no default selection.
Example:
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Install connect-4
You can use connect-4 like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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