ssh_client | Educational SSH client | SSH Utils library
kandi X-RAY | ssh_client Summary
kandi X-RAY | ssh_client Summary
These files implement a very basic SSH client that can be used with Ubuntu 15.10 to understand the SSH protocol.
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ssh_client Key Features
ssh_client Examples and Code Snippets
Community Discussions
Trending Discussions on ssh_client
QUESTION
Upgraded Jenkins from 2.257 to 2.339. After the upgrade none of the nodes are able to connect to the master. Jenkins is hosted on Amazon Linux. This is error I am getting when I try to connect a node to the controller:
Logs from Windows Agent :
...ANSWER
Answered 2022-Mar-20 at 17:24There is an open issue about your problem: https://issues.jenkins.io/browse/JENKINS-67258.
According to one of the participant of this issue, a solution is to:
[...] upgrading SSH Build Agents / SSH Slaves Plugin to version 1.32.0 and beyond [...]
QUESTION
I'm using Visual Studio Code Insiders version 1.65.0-insider. Until 3 days ago, I was not having any problem connecting to the remote server at work from my work laptop through a VPN. I have my ssh config file and when I opened vscode (when connected to the VPN), I was asked for my password and it connected without problems.
However, from yesterday I have started getting an error stating Could not establish connection to idk4v: The VS Code Server failed to start. idk4v is the remote machine's name that I gave in my ssh config file. I also get Waiting for server log... in the output continuously. I am pasting the output here from trying out just now. I have removed the non-essential parts for brevity:
...ANSWER
Answered 2022-Feb-15 at 20:37This is very much a hack and absolutely not a long term solution but as a quick work around.
Find the server.sh path in the log you posted, open it in an editor, and add --accept-server-license-terms to the last line so it looks something like "$ROOT/node" ${INSPECT:-} "$ROOT/out/server-main.js" --compatibility=1.63 --accept-server-license-terms "$@". This will accept the terms automatically until this gets patched by MS.
QUESTION
I am creating a script that uses different commands in different servers... To do it, I avoid to use tools like sshpass, and I try to do it by using paramiko (because with paramiko, I can handle exceptions and I can also exit the ssh session).
There are two machines that I must connect to, there are two different commands to use, etc.
The problem is, that I would like to not repeat the code I use twice, my code is something like:
...ANSWER
Answered 2022-Feb-08 at 09:33In general, the smallest element of code re-use is the function. So, make a function for creating the connection, for instance.
QUESTION
I am sure there are a thousand duplicates, but I have not found them as what I have found involve the local terminal, or if about the remote terminal, it is assumed that the live terminal view already exists. In my case the "terminal" aspect of the terminal does not yet exist within the terminal pane.
Setup:
Visual Studio Code installed on Win 10 doing remote development on a Linux based system.
Issue:
When I start Visual Studio Code, it automatically attaches itself to the remote system, as it should.
However, the terminal pane at the bottom of the editing window does NOT contain a "terminal", (i.e. with a prompt that I can type commands into). Instead it shows the output of VS Code's efforts to connect with the remote machine as shown below:
Which contains a lot of text:
...ANSWER
Answered 2022-Feb-01 at 18:41If you click Terminal then New Terminal, you should get a fresh terminal inside remote environment.
QUESTION
I have ec2 instance with ubuntu v20.04 and it has python v3.8.10 and pysftp 0.2.9.
I have generate .pem file from .ppk file using below command
puttygen sftp_server.ppk -O private-openssh -o sftp_server.pem
I am able to connect successfully to sftp server using command line-
...ANSWER
Answered 2022-Jan-28 at 09:18The error comes form underlying Paramiko and is discussed here:
Paramiko authentication fails with "Agreed upon 'rsa-sha2-512' pubkey algorithm" (and "unsupported public key algorithm: rsa-sha2-512" in sshd log)
Though pysftp does not expose the disabled_algorithms parameter.
You better switch to using Paramiko directly. The pysftp is abandoned project. See pysftp vs. Paramiko.
QUESTION
I have a Python 3 application running on CentOS Linux 7.7 executing SSH commands against remote hosts. It works properly but today I encountered an odd error executing a command against a "new" remote server (server based on RHEL 6.10):
encountered RSA key, expected OPENSSH key
Executing the same command from the system shell (using the same private key of course) works perfectly fine.
On the remote server I discovered in /var/log/secure that when SSH connection and commands are issued from the source server with Python (using Paramiko) sshd complains about unsupported public key algorithm:
userauth_pubkey: unsupported public key algorithm: rsa-sha2-512
Note that target servers with higher RHEL/CentOS like 7.x don't encounter the issue.
It seems like Paramiko picks/offers the wrong algorithm when negotiating with the remote server when on the contrary SSH shell performs the negotiation properly in the context of this "old" target server. How to get the Python program to work as expected?
Python code
...ANSWER
Answered 2022-Jan-13 at 14:49Imo, it's a bug in Paramiko. It does not handle correctly absence of server-sig-algs extension on the server side.
Try disabling rsa-sha2-* on Paramiko side altogether:
QUESTION
I'm trying to configure routers with a python script and wanted to use paramiko expect to do the job. The function change_password is part of a class and contains the following paramiko-expect-lines (with self.ssh_client as an instance of paramiko.SSHClient):
...ANSWER
Answered 2021-Nov-23 at 14:55in case anybody has a similar problem:
I took out the multiline expects and replaced it by only expecting the last line. I guess I missunderstood the docs and thought I'd have to expect both lines. New code as follows works without timeout.
QUESTION
...
file = 'ip.txt'
arquivo = open(file, "r").readlines()
for linha in arquivo:
linha = linha.strip()
print(linha + " Sucesso")
ssh_client =paramiko.SSHClient()
ssh_client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh_client.connect(hostname=linha,username='root',password='Server123@')
ftp_client = ssh_client.open_sftp ()
file = 'qnttestl.txt' #diretorios
arquivo = list(open(file, "r").readlines())
for linha in arquivo:
linha = linha.strip()
print(linha)
#fila = arquivo
file = 'qnt.txt'
txts = list(open(file, "r").readlines())
for linha in txts:
v2 = open('ip.txt', "r").readlines()
for linha in v2:
linha = len(linha.strip())
ftp_client.put (linha, '/root/test.txt')
## this line that sends the file that is in "qnttest.txt" to "ftp", but it is sending all files from "qnttest.txt to a "ftp" only, I want it to send a file (one line of " qnttest.txt") for each "ftp" in "ip.txt", each line of "qnttest.txt" is a file ##
## essa linha que envia o arquivo que ta no "qnttest.txt" para o "ftp", só que ela ta enviando todos arquivos do "qnttest.txt pra um "ftp" só, quero q ela envie um arquivo(uma linha do "qnttest.txt") para cada "ftp" que ta no "ip.txt", cada linha do "qnttest.txt" é um arquivo ##
ftp_client.put ('test.html', '/root/test.html')
ftp_client.put ('test.pl', '/root/test.pl')
ftp_client.put ('test.txt', '/root/test.txt')
...
ANSWER
Answered 2021-Nov-12 at 10:48If you want to send one file to one ftp then you should first read all data from both files and later use zip() to create pairs (ftp1, file1), (ftp2, file2), etc.
QUESTION
Context: I am trying to use the paramiko Python library to SSH into an EC2 instance from within an AWS Lambda function (written with Python 3.7). The EC2 instance in question exists in a VPC. I know the public IP of this EC2 as well. I have already created a lambda layers package for Paramiko and am able to use the import paramiko statement with no errors so I know the library works fine.
Attempted Solution: I have utilized this tutorial to try to SSH into the EC2 mentioned above. The code I have thus far is as follows (some information has been randomized for privacy):
...ANSWER
Answered 2021-Sep-21 at 01:383.81.62.55 is a public IP. You must use your instance private IP or default EC2 dns url provided by the aws for the instance.
QUESTION
This is how I am trying to retrieve the external IP address of vms:
...ANSWER
Answered 2021-Sep-11 at 18:30I believe 'ansible_host' variable would do the trick. The playbook below outputs the ip address of the vm.
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No vulnerabilities reported
Install ssh_client
You can use ssh_client like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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