Adidas | adi account gen - uses sharklasers | Email library

you can use apply with a function such that:

A CASE statement and LAG function can do this:

replace only works on the first found item in the string. You can either use replaceAll, or split and join, which is more cross-browser friendly as below:

I understand, that it might be a bit far from what you expect for an answer - but why don't you have a look at a reactive tool, like Vue? It has all the tools that you might need for such a task, and maybe more:

• the whole quiz can be abstracted to a simple array of objects (the questions)
• next, prev, set default answer becomes a breeze
• easy to extend (with questions)
• simple to update (template, features, etc.)

You can create a custom function that takes a row as an input, and then apply it to the dataframe rowwise using the argument axis=1:

This is not the correct use of bind:

If brand names aren't multiple words, we can simply split Company Name on white space and look up membership:

You need to use element.remove() instead of element.style.display ="none"

Why? element.remove() - will remove the DOM element altogether. element.style.display ="none" - Will only hide it for the end user. But it will still be there on the DOM tree.

Js Fiddle for solution below:

Fixed a few thing in you code as well. Added comment lines in the places where I fixed things

1. Next button now disappears on the last question
2. Previous button now disappears on the first question

Edit:

Edited the code snippet with few logical changes. Now the answers are maintained in the array as expected. Although the buttons dont retain colour. This can be handeled in the previous and next button click functions in the same way which you have done the getLinks method.

When you write a for loop, there are 3 parts within the brackets. The first part declares a variable which is scoped to the loop. The second part is the condition for when the loop should finish. The third part is how the variable should change after each time round the loop.

You can see this working perfectly in NextQuestion:

for (let y = 0; y < question.chosenAnswer.length; y++) { ... }

The first part declares a variable called y and sets its value to zero. Each time round the loop, the third part runs, so y becomes 1, then 2, and so on. Each time, the second part is checked to see if the loop should continue. If y is still smaller than the length of question.chosenAnswer then the loop will run again, but at some point y becomes equal to question.chosenAnswer.length and the loop stops. The key point is that y isn't getting bigger automatically, it's getting bigger because that's what we've specified in the third part of the loop.

Now let's have a look at your loop in PrevQuestion:

for (let y = 0; y > question.chosenAnswer.length; y--) { ... }

Again y starts at zero, but this time we are decreasing it's value each time (using y--) so it's value becomes -1 then -2 and so on. y keeps getting smaller so it never ends up larger than question.chosenAnswer.length, which is what would stop the loop. The consequence of this is that your loop will run infinitely, and the code after the loop will never execute.

It's hard to know for sure without seeing the full code, but most likely you want y++ same as in NextQuestion. An alternative would be to keep y-- but change the variable's initial variable and the end condition. For example, this would be fine:

for (let y = question.chosenAnswer.length; y > 0; y--) { ... }

Which is best in your case simply depends on which order you want y to take the values from 0 to question.chosenAnswer.length - if it should go from smallest to largest, or the other way round.