treehugger | Takes care of your environment on AWS | AWS library
kandi X-RAY | treehugger Summary
kandi X-RAY | treehugger Summary
Takes care of your environment (variables) on AWS.
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Top functions reviewed by kandi - BETA
- Print out the contents of the tree
- Create a EnvironmentDict from a dictionary
- Return the base encryption context
- Decrypts all keys in the environment
- Edit a file
- Context manager for os umask
- Load and decrypt and decrypts a file
- Returns a dict representation of the environment
- Return kms client
- Get current region
- Execute command
- Decrypt and decrypt a file
- Encrypt and encrypt a file
- Get the version number from a file
treehugger Key Features
treehugger Examples and Code Snippets
Community Discussions
Trending Discussions on treehugger
QUESTION
I have a single page website design in html, javascript and css. There are lots of images on the webpage and all have different-different animation effects according to their categories. I have used wow.js for animation effects on window scroll. While scroll through images, CPU and GPU usage is going very high, due its effect the scrolling is jerky, not smooth. Could anyone please look into this. I have created a codepen example. Please have a look:-
...ANSWER
Answered 2019-Jun-25 at 06:30You can probably gain a lot of performance by using Intersection Observer (IO) instead of listening to the scroll event. IO was introduced because listening to the scroll event and calculating height/width of elements results in poor performance.
First you have to create a new observer:
QUESTION
In my scala code I have a Class[_ <: AnyVal]
instance, such as the one obtained from classOf[Int]
.
When I try to obtain the scala type name from this (using classOf[Int].getName
), I am expecting to see "scala.Int"
, but instead I am getting the primitive Java type's name: "int"
How can I get the scala type name from my Class
variable, in case I am dealing with either a java primitive equivalent, or the default boxed java equivalent (such as java.lang.Integer
)
In case you are wondering why I would need this; I am generating some scala code using treehugger, and the information about whether I need to generate e.g. a scala.Int
comes from a library that provides a Class[_]
ANSWER
Answered 2019-Apr-20 at 21:44If you only want to handle primitive types,
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install treehugger
You can use treehugger like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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