ika | Yet another LISP Interpreter | Interpreter library

by tioover Python Version: Current License: GPL-2.0

X-Ray Key Features Code Snippets Community Discussions(8)Vulnerabilities Install Support

kandi X-RAY | ika Summary

ika is a Python library typically used in Utilities, Interpreter applications. ika has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. However ika build file is not available. You can download it from GitHub.

ika

Support

Quality

Security

License

Reuse

Support

ika has a low active ecosystem.

It has 11 star(s) with 0 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

ika has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of ika is current.

Quality

ika has 0 bugs and 0 code smells.

Security

ika has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

ika code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

ika is licensed under the GPL-2.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

ika releases are not available. You will need to build from source code and install.

ika has no build file. You will be need to create the build yourself to build the component from source.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed ika and discovered the below as its top functions. This is intended to give you an instant insight into ika implemented functionality, and help decide if they suit your requirements.

Define a lambda expression
Get the reference of a node
Yields pairs from a pair
Compose a thing
Compose the grammar
Check if obj is a subclass of cls
Construct a tuple from a separator
Return a random thing
Helper function for _card_card
Apply a function
Assign a formal value to the environment
Make evaluator function
Compile expression
Indent the given thing
Set the value of a key
Return some things
Return a list of things separated
Declare a flag
Assign an instruction
Produce an expression
Arguments are optional
Return a contiguous sequence of values
Define a grammar
Start instruction
Clear memory
CallCC instruction

Get all kandi verified functions for this library.

ika Key Features

No Key Features are available at this moment for ika.

ika Examples and Code Snippets

No Code Snippets are available at this moment for ika.

Community Discussions

Trending Discussions on ika

angular 13: Module not found: Error: Can't resolve 'rxjs/operators'

Deserializing JSON into C# Object

Call function in a new function

Reversing list of tuples in an if statement

List into a class show it after a a clickable ListView.builder in flutter

how to load json and extract into separate nodes in neo4j

Regex for SoundCloud URL

JQ - What is the data type of comma filter

QUESTION

angular 13: Module not found: Error: Can't resolve 'rxjs/operators'

Asked 2022-Jan-22 at 05:29

I have upgraded my angular to angular 13. when I run to build SSR it gives me following error.

...

ANSWER

Answered 2022-Jan-22 at 05:29

I just solve this issue by correcting the RxJS version to 7.4.0. I hope this can solve others issue as well.

Source https://stackoverflow.com/questions/70589846

QUESTION

Deserializing JSON into C# Object

Asked 2021-Aug-24 at 21:10

I am trying to deserialize a json object into c# object and list the Itinerary items.

Here is my json object:

...

ANSWER

Answered 2021-Aug-24 at 16:38

try this classes

Source https://stackoverflow.com/questions/68910808

QUESTION

Call function in a new function

Asked 2021-May-05 at 08:55

I have a function:

...

ANSWER

Answered 2021-May-05 at 08:49

You are calling get_translations, but ignoring the return value. Since get_translations_from_file has no explicit return statement, it implicitly returns None. To make a long story short, you need to return the value from get_translations:

Source https://stackoverflow.com/questions/67397945

QUESTION

Reversing list of tuples in an if statement

Asked 2021-May-04 at 01:57

I have 2 strings as follows:

...

ANSWER

Answered 2021-May-04 at 01:57

Something like this should work if I understood what you wanted to do:

Source https://stackoverflow.com/questions/67377761

QUESTION

List into a class show it after a a clickable ListView.builder in flutter

Asked 2021-Jan-15 at 15:33

I created these classes and this list to make it clickable in flutter with a ListView.builder. When I click on a name I take me to the clan page. How do I show the list of members in the clan class and make it tapable to the "Member profile page"? or is there a different way to do it?

These are the classes

...

ANSWER

Answered 2021-Jan-15 at 15:33

In your clan class add the following code:-

Source https://stackoverflow.com/questions/65738672

QUESTION

how to load json and extract into separate nodes in neo4j

Asked 2020-Jul-16 at 14:23

i'm newbie in neo4j and need help with my case... i'm trying to load json file with the structure (updated by suggested) like below and extract into 3 nodes (big5_personality, personality_result & personality)

...

ANSWER

Answered 2020-Jul-15 at 03:29

You have multiple issues with your data file. Among them are:

Your Cypher code expects personality_result to be a list of JSON objects. It is not.

(a) It is a single string, not a list.

(b) That string seems to consist of the truncated start of a stringified JSON object (that includes a lot of extra pretty-printing whitespace).

So, everything in your Cypher query starting at the FOREACH will not work.
In your next-to-last MERGE, personality_result.personality should probably be just personality.

You may have other issues, but it is hard to tell until you fix your data file and code.

Source https://stackoverflow.com/questions/62906025

QUESTION

Regex for SoundCloud URL

Asked 2020-Apr-29 at 07:42

I just want to match my url with this URL all possible combinations like www without www, http,https

Basically any input URL that matches with soundcloud music url like

https://soundcloud.com/mazz-ika-free/wegz-molotof-dorak-gai-2020

FIRST PART:- https://soundcloud.com/ (http,https)
SECOND PART :- Alphanumeric with only '-' allowed.
THIRD PART :- Aphanumeric with only '-' allowed

I have tried this regex so far :

...

ANSWER

Answered 2020-Apr-28 at 18:27

One option would be to create a new anchor element from JavaScript, assign the URL to the href attribute, and then check the host property of that anchor:

Source https://stackoverflow.com/questions/61486337

QUESTION

JQ - What is the data type of comma filter

Asked 2020-Mar-01 at 19:16

Question

What is the data type of the JQ comma filter?

Background

I get Cannot iterate over number error when trying to feed the output of the comma filter.

...

ANSWER

Answered 2020-Mar-01 at 05:10

What is the data type of the JQ comma filter?

There's not really such a thing as a data type returned by the comma filter...

Because it doesn't really group the values in a single container data type. Rather, it sends the values separately through the following filters and reports each output separately at the end.

Perhaps a good way to understand it is seeing this result:

Source https://stackoverflow.com/questions/60472049

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install ika

You can download it from GitHub.
You can use ika like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: