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kandi X-RAY | warren Summary
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Trending Discussions on warren
QUESTION
I am trying to use Celery to create periodic tasks in my application. However, I cannot see the outputs of the periodic task that I wrote.
The backend is on a Windows-based redis-server. The server is up and running.
project/celery.py
...ANSWER
Answered 2021-Jun-04 at 09:08You need to start celery beat
, because that him that will read the database and execute your task.
install : https://github.com/celery/django-celery-beat
so in CLI, you need to execute :
QUESTION
In this University Database:
...ANSWER
Answered 2021-Mar-16 at 16:03Gag. This would seem to answer the question:
QUESTION
i am using python json and i want to let my Python code search for specefic Keywords in a JSON-File.
Basically it should search for the "profilename" and then go one line down and print the email of the profile out.
...ANSWER
Answered 2021-May-04 at 10:08If I understand you correctly, you are trying to find a profile by the field profilename
and return the user's email
.
QUESTION
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
//.ts file
...ANSWER
Answered 2021-Apr-27 at 16:44You can do it with the $event
parameter.
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this c.state == val
might not work.
You can use the trim
function to compare your value safely:
c.state.trim() == val.trim()
HTML
QUESTION
I have some tables in my database and I'm trying to transact between them. My aim is to show the project name and the employees in that project in the form of cards on my projects page as in the image below. (Other than the method I mentioned, if there are better ways to do this, I ask you to share.)
When trying to do this, the first thing that came to my mind was to use leftJoin. Together with the projects, I thought of pulling the users in that project together and showing them by using foreach nested. If I just want to shoot projects, there will be no problem and the first 4 projects come and everything works fine. But since I needed to attract the users in that project along with my projects, when I used leftJoin, I got an output as you can see below. I had to use pagination as I needed to show 4 projects per page, and when I used pagination, the lines that came in were inconsistent. While waiting for 4 projects and their employees to arrive, the first 4 lines came. (3 employees of 1 project and the first employee of the other project have arrived.)
My code:
...ANSWER
Answered 2021-Apr-26 at 07:51You may consider using Eloquent relationship instead of left join. In fact left join wouldn't work that well in your case since you will have to group all users in the same project from the rows afterwards. Example of Eloquent relationship using whereHas
and with
as follows.
QUESTION
Does anybody use the w2ui.com component library? There is a cool input component (called combo) that filters a list as you type.
But it doesn't seem to work when it is inside of a popup. When you type in the input box, nothing appears in the filter like it does in the demo.
Here is my javascript:
...ANSWER
Answered 2021-Apr-13 at 22:41You have a different problem then what I initially thought. You're calling the init function of the combo before you open the popup, but the entire content of the popup is created dynamically, when you open it. Which means the element you're trying to init the combo on doesn't yet exist at that time.
So you have to call the init combo function every time you open the popup, after it has rendered its contents.
Here's the fix:
QUESTION
I'm getting this error message in my table view controller class
value of uitableviewcell has no member delegate
Here is an image of the error.
Is there anything that should be changed in my code?
...ANSWER
Answered 2021-Apr-13 at 06:48You should assign your delegate and data source to your table view instance, and not your table view cell.
In order to do that, create an outlet link with your table view in the TViewController file and then edit your code like this:
QUESTION
I'm trying to find the fastest way to return the index of a given element in a sorted array. np.searchsorted()
seems to be specifically designed for the job. It uses binary search, which should be faster than the generic np.where()
, which I'm assuming needs to loop through the entire array in O(N). However to my surprise, np.searchsorted()
takes the same amount of time as np.where()
, even for large arrays. Here's a MWE:
ANSWER
Answered 2021-Apr-07 at 15:26You used the Python builtin function sorted
to sort the random values, so a
is a Python list, not a NumPy array. Internally, searchsorted
will create a NumPy array from that list, which means copying the list, so the actually complexity is O(n) instead of O(log(n)). The same is true for using np.where
: the comparison of the Python list to a numpy.float64
value will end up converting the list to a NumPy array first.
If you change the creation of a
to something like
QUESTION
I am doing a problem that requires me to balance any binary search tree, with a criteria that the left and right subtree on each level should have the same amount of nodes or at most 1 node difference
How can I approach this problem? So far I have transformed the tree into a linked list.. and thats it. Im pretty sure thats the first step but not too sure. I have looked everywhere for resources, but the closest thing I could find was day-stout-warren algorithm which balances based on height and not amount of nodes.
I am just looking for pseudocode
...ANSWER
Answered 2021-Mar-29 at 23:05Add all nodes to an array in inorder traversal, then it should be roughly like this:
QUESTION
I have a database table (table A) looks like this, in SQL Server 2016:
TableA:
...ANSWER
Answered 2021-Mar-17 at 20:40Next time you would need to provide ##1-4. And learn from this answer what it means, i.e. a minimal reproducible example. You copy it to SSMS and launch it there.
Here is how to implement it in SQL Server 2016:
STRING_SPLIT()
to break it down, one AssignedTo per row.SELECT ... FOR XML ...
to revert it back to one row for each task.
SQL
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