oscrypto | free Python crypto library backed by the OS | Cryptography library
kandi X-RAY | oscrypto Summary
kandi X-RAY | oscrypto Summary
A compilation-free, always up-to-date encryption library for Python that works on Windows, OS X, Linux and BSD. Supports the following versions of Python: 2.6, 2.7, 3.2, 3.3, 3.4, 3.5, 3.6, 3.7, 3.8 and pypy.
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Top functions reviewed by kandi - BETA
- Perform the handshake .
- Verify signature .
- Loads the bcrypt key object .
- Called when an error occurs .
- Submit codecov . json .
- Recursively walk through AST nodes .
- Make a HTTP request .
- Parse a PKCS12 certificate .
- Extract certificates from system
- Verify a PSS signature .
oscrypto Key Features
oscrypto Examples and Code Snippets
Lines of Code : 5License : Strong Copyleft (CC BY-SA 4.0)
Copyboto3==1.13
botocore==1.16
snowflake-connector-python==2.2.7
snowflake-sqlalchemy==1.2.3
#!/usr/bin/env python3
# *-* coding: utf-8 *-*
from oscrypto import asymmetric
from endesive import pdf
def main():
dct = {
b'sigflags': 3,
b'contact': b'me@email.com',
b'location': b'City',
b'signingdaCommunity Discussions
Trending Discussions on oscrypto
QUESTION
Been struggling for a few hours. I'm trying to hit this link That has these contents:
...ANSWER
Answered 2021-Aug-27 at 21:16AdminOfThings provided a good pointer in a comment, but let me try to put it all together:
QUESTION
Recently my lambda code stopped working. I am no longer able to create connection to Snowflake with sqlalchemy. See error stack below.
...ANSWER
Answered 2021-Jan-13 at 19:26For completeness, moving the answer from @Clement in a comment to an answer:
This error can happen when loading the oscrypto (libcrypto) if the memory usage is too high. The OOM state cascades upward.
QUESTION
Package Control is not loading in Sublime Text 3 running on MacOS, Catalina 10.15.6.
None of the Package Control commands are shown in the Command Palette.
I have checked that Package Control was not in ignored_packages, have manually reinstalled Package Control (multiple times), and even uninstalled and reinstalled Sublime Text 3.
When I start Sublime Text 3 the error below is shown in the console when it tries to load Package Control. It looks like the problem relates in some way to OpenSSL, specifically to the libcrypto.dylib file.
I recently updated/upgraded my system using Homebrew and suspect that something occurred during the update that has caused the problem.
...ANSWER
Answered 2020-Dec-09 at 19:56@MattDMo, you were correct that it was a 32-bit versus 64-bit problem AND that Will Bond would help. After posting a ticket on Package Control, @wbond responded right away suggesting that I move the file /usr/local/lib/libcrypto.dylib.
For the sake of completeness, @wbond asked for the output of the terminal command:
QUESTION
After upgrading to macOS Big Sur my snowsql scripts all fail with "The Library Security could not be found"
...ANSWER
Answered 2020-Nov-25 at 20:39Could you try the following steps?
- Move the User's snowsql directory to a backup: mv ~/.snowsql ~/.snowsql.prebigsur
- Move the SnowSQL application to the trash from the Applications folder.
- Make sure "/Applications/SnowSQL.app" is gone.
- Then download and install the latest SnowSQL from the darwin repo (https://sfc-repo.snowflakecomputing.com/snowsql/bootstrap/1.2/darwin_x86_64/index.html)
QUESTION
I am trying to encrypt a password in python and decrypt it in java springboot application using the jasypt library through jasypt plugin.
What i have done so far
- For simplicity i have used a zero salt and a fixed iv
- I have written the python script to perform the encryption using hselvarajan's pkcs12kdf ...
ANSWER
Answered 2020-Jun-25 at 08:53PBEWITHHMACSHA512ANDAES_256 applies PBKDF2 to generate the key. Encryption is performed with AES-256, CBC.
The (originally) posted Jasypt test function used RandomIvGenerator, which creates a random IV. For the salt, ZeroSaltGenerator is applied, which generates a salt consisting of 16 zero bytes.
To implement the Python function you are looking for, it is best to use a fixed IV, e.g. with StringFixedIvGenerator. StringFixedSaltGenerator provides a corresponding functionality for the salt (FixedStringSaltGenerator has the same functionality but is deprecated since 1.9.2). StringFixedSaltGenerator and StringFixedIvGenerator encode the passed string with UTF-8 by default (but another encoding can be specified), so that the salt (or IV) 0000000000000000 is hex encoded 0x30303030303030303030303030303030.
Note that a fixed salt and IV may only be used for testing. In practice, a new random salt and a new random IV must be used for each encryption. Since salt and IV are not secret, they are usually concatenated with the ciphertext on byte level (e.g. in the order salt, iv, ciphertext) and sent to the receiver, who separates the parts and uses them for decryption.
If the same parameters (especially the same salt and IV) are used on both sides, then encryption with Python and decryption with Java works.
Encryption with Python (PyCryptodome):
QUESTION
I've spent half a day trying to figure it out on my own but now I've run out of ideas and googling requests.
So basically what I want is to connect to our Snowflake database using snowflake-connector-python package. I was able to install the package just fine (together with all the related packages that were installed automatically) and my current pip3 list results in this:
ANSWER
Answered 2020-Jun-30 at 15:16
AttributeError: module 'snowflake' has no attribute 'connector'
Your test code is likely in a file named snowflake.py which is causing a conflict in the import (it is ending up importing itself). Rename the file to some other name and it should allow you to import the right module and run the connector functions.
QUESTION
I am trying to connect to Amazon S3 using boto3 and snowflake-connector-python for which I am running the following packages:
ANSWER
Answered 2020-Jun-23 at 15:30What is the way to resolve this conflict?
You can try to follow the path of using the lowest agreeable version. To break it down:
- The
snowflake-connector-pythonpackage dependencies appears to be restricting its use ofboto3library to1.13.xat most. - Your requirements specify an explicit version of
boto31.14.x. - Your use of the simple
boto3APIs (going by the snippet shared) does not appear to involve any 1.14.x specific changes or features. boto31.13.xreleases continue to work against the live AWS S3 service.
Therefore, try using an accepted version of boto3/botocore in place of the current version(s):
QUESTION
I tried to sign and verify by C++ cryptoAPI and it works well. The cryptoAPI use the certificate from the store(Personal) on windows to do this. Could I do the same thing by python without export private key or input passphrase?
I tried pycrypto, oscrypto, wincertstore module, but they can't do this.
...ANSWER
Answered 2020-Jan-22 at 07:15You can interface with the Crypt32 dll Using ctypes to access it's functions.
How can I use a DLL file from Python? provides a good idea, but is written in python 2.5, so see the tutorial in the docs for info and a reference.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install oscrypto
You can use oscrypto like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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