Wats | Code to accompany WATS Plot article | Data Visualization library
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Code to accompany WATS Plot article
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QUESTION
Q-Given a string of lowercase letters in the range ascii[a-z], determine the index of a character that can be removed to make the string a palindrome. There may be more than one solution, but any will do. If the word is already a palindrome or there is no solution, return -1. Otherwise, return the index of a character to remove.
Can anyone tell me wats happening at the s[i] != s[n-1-i]
part in this code of mine.
ANSWER
Answered 2021-Feb-12 at 22:13So i
is the current index, iterating through the first half of the string.
s[i]
is the letter at that index, and s[n-1-i]
will be the letter at the n-1-i
th position. Since n=len(s)
, n-1
will be the final character in the string, and we'll be coming backwards from there with i
. For example, if we take the string foobar
, and i=1
, s[i]
will be o
and s[n-1-i]
will be a
. That's the first if
statement - detecting the first i
at which we are no longer palindromic, that is, the i
th character from the front is not the same as the i
th character from the end.
Once we've established that this pair of characters don't match, we need to determine if removing either one would make our string a palindrome again. There are two possible cases that would make this true:
- Removing the letter at
n-1-i
makes the string palindromic - Removing the letter at
i
makes the string palindromic
We try these two cases in that order. However, rather than recreating the entire input string, minus one letter, we can get crafty and save memory by just testing the substring between our current endpoints for palindrome-ness instead of the entire string. After all, we know that everything outside our current i
- n-1-i
pair is already a palindrome. That's the fancy magic you see in the if
statements - testing the substrings for palindrome-ness.
s[i:n-1-i]==s[i:n-1-i][::-1]
can be broken down into a couple parts. First, s[i:n-1-i]
is the substring between our i
and n-1-i
markers, but does NOT include the letter at n-1-i
. We'll call that sub
. With that substituted back in, we have sub == sub[::-1]
. As you'll recognize from earlier on in the function, that's just how you test if a given string is a palindrome. If sub
is a palindrome, then you know that, by omitting the character at n-1-i
, your entire original string is palindromic. Therefore, we return n-1-i
.
s[i+1:n-i]==s[i+1:n-i][::-1]
breaks down much the same way. The difference is that s[i+1:n-i]
is shifted one character to the right, so the result is the substring between our i
and n-1-i
markers, but this time NOT including the letter at s[i]
and including the one at s[n-1-i]
. If this substring is palindromic, then we know that it's the letter at s[i]
that has to go in order to make the original string a palindrome. Therefore, we return i
In the case where neither one of these things is true, then not only is the input string not a palindrome, but there's no way to remove only one letter to make it one. Therefore, we return -1
to signify that there is no solution.
QUESTION
I am currently working on a program that scrapes Yahoo Finance Earnings Calendar Page and stores the data in a file. I am able to scrape the data but I am confused as to why it only scrapes the first 2 and last 2 columns. I also tried to do the same with a table on Wikipedia for List of S&P 500 Companies and am running into the same problem. Any help is appreciated.
Yahoo Finance Code
...ANSWER
Answered 2019-Nov-17 at 07:23As far as I can tell this nothing to do with the data and everything to do with the representation. Only the first and last columns are printed so as to keep the output from being massive and difficult to read. You can even see at the end of your output that your DataFrame has 9 columns.
Take a look here if you want to print the entire thing. You could also use .info
to get some general information on your columns.
QUESTION
First of all i'm nobbie in Kotlin, trying to learn at home, started making a program for company i work for. Made SQLite database consists of 4 tables, one of them is "Empeloyees" that have data of employees at the company including departments and professions. Second table records Holidays taken by those employees.
This is My Main Activity code:
...ANSWER
Answered 2019-Nov-13 at 05:20I believe that your issue is that a selection from spinner1 doesn't drive spinner2 to change. You also have inefficiencies in that if spinner 2 were to be driven by spinner1 then you would build a new adapter each time.
Perhaps consider the following example that incorporates a single function to return the appropriate ArrayList i.e getArrayList and functions that manage a single instance of the adapter i.e. manageSpinner1 and manageSpinner2 noting that the spinner1's onItemSelected invokes manageSpinner2.
The example also loads some test data via the addSomeData function (this onlt adds data when there is no data).
Note for my convenience the layout used is activity_main.xml (you would just use your layout).
The activity MainActivity.kt is (note that much of your original code has been commented out) :-
QUESTION
I need to run the program NACCESS on my MacOS X High Sierra.
The most prominent error is if: Expression Syntax.
This error is probably because the NACCESS executable is a CSH script with #!/bin/csh
on its first line.
I changed the first line to #!/bin/bash
and began getting errors such as
./naccess: line 14: syntax error near unexpected token `1'
./naccess: line 14: ` exit(1)'
Again, I think this is happening because the executable needs to be executed in a CSH shell, not bash. exit(1)
is formatted for the CSH shell, whereas bash would want exit 1
, according to this resource.
I tried typing csh
into Terminal to switch shells, but an echo $SHELL
command just tells me I'm still in bash.
I looked at my shell choices with grep '^#!' /usr/bin/*
and cannot find any CSH shells. I attempted to download tcsh
using homebrew. But I really have no idea what I'm doing at this point.
I know CSH shells aren't encouraged, but how do I get a CSH shell up and running on my Mac, or how do I otherwise get NACCESS to run?
[EDIT] Here are the first few lines of the NACCESS code:
(Note that I am running it with the .pdb file argument and also that I have set path_to_naccess_repository appropriately. I do get the usage naccess pdb_file [-p probe_size] [-r vdw_file] [-s stdfile] [-z zslice] -[hwyfaclqb]
readout if I run only ./naccess
)
ANSWER
Answered 2018-Sep-27 at 20:20The SHELL
variable simply lists your first login shell, it will not change if you run another shell. echo $0
will show you you are running csh
. Your options are either to stay in bash
and change the shebang to tcsh
:
QUESTION
So I have a Label
being initialized by a WebService. I want to see if that label contains any commas. The problem is, even if the label has commas, Contains()
returns false
and if I do a Split()
, the array is only 1 element long, containing the entire string.
ANSWER
Answered 2018-Sep-12 at 14:30The following line is always going to evaluate to false:
QUESTION
I have a class called martCrawler which import other 3 crawlers from other files
However, the code becomes too long as the crawler imported increased.
Is there a better practice managing the code like this?
Thanks in advance~
...ANSWER
Answered 2018-Aug-04 at 13:45Then why not store all the crawlers in a dict from the beginning?
As an example:
QUESTION
"code for sending email above is the code .iam tired of scratching my head but still not able to see the image in the mail. I am converting the image into base 64 encoded string and also following the sendgrid syntax still not able to send the image .i dunno wats going wrong here.:"
...ANSWER
Answered 2017-Dec-05 at 15:21If I look to the https://sendgrid.com/docs/API_Reference/Web_API_v3/Mail/index.html
I see it is attachments not attachment
Also there is content_id instead of ContentId
Also make sure, you are using right version (I am pointing to v3 but I think you can choose to use v2)
QUESTION
I have to write a function which return True
even if one word between the two strings matches.
willis towers watson
and willis singapore
-> True
as willis
matches
willis towers watson
and willis s pte ltd
-> True
as willis
matches
willis towers watson
and will tow wat
-> False
as no Word
matches
I unsuccessfully tried a regex:
...ANSWER
Answered 2018-Jun-09 at 20:41Just split the strings into sets of words and check if the two sets intersect.
QUESTION
For some reason the back to top button I am using for this website I coded isn't working at all. When I hide the button it won't reappear so I then made it visible to see if it would work but it still wouldn't do anything. Not sure if it's the rest of the code besides the jquery code that's causing it. I used the back to top btn code elsewhere and it works just fine, also used chrome dev tools and no errors pop up. Any help would be appreciated!
...ANSWER
Answered 2018-May-10 at 02:10First, I think your problem is only caused by the fact that you closed the body tag before the footer tag.
so first try to put the right before the
Then add to your jquery code a preventdefault()
fonction before processing
QUESTION
I am going to dynamically create local branches(like Hotfix_Test1, Hotfix_Test2 each at different time) and push it to remote.
These branches should contain the source available in a branch called Release which is another local
Release is already pushed to remote from local using git commands
- git checkout -b Release git push
git push --set-upstream origin Release
I create a git object and trying the following code to create hotfix branches dynamically
...
ANSWER
Answered 2017-Jul-18 at 15:18You already called createdBranchCommand:
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