simpleR | Using R for Introductory Statistics | Analytics library
kandi X-RAY | simpleR Summary
kandi X-RAY | simpleR Summary
This repository contains all of the code to the section questions in Verzani's simpleR - Using R for Introductory Statistics.
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QUESTION
I'm trying to test a Text
that on my component I can print it in different colors, so on my test I'm verifying it gets the expected color. I was looking for a method to return the color but I did not find any.
From now I'm asserting that the text is correct and the visibility is correct, but when trying to find the method to get the colour I get too deep and I'm looking for a simpler solution.
...ANSWER
Answered 2022-Feb-11 at 09:02I am by no means a compose expert, but just looking at compose source code, you could utilize their GetTextLayoutResult accessibility semantic action. This will contain all the properties that are used to render the Text
on a canvas.
Some quick and dirty extension functions I put up for convenience:
QUESTION
Suppose that we have a very long array, of, say, int
to make the problem simpler.
What is the fastest way (or just a fast way, if it's not the fastest), in C++ to see if an array has more than one common elements in C++?
To clarify, this function should return this:
...ANSWER
Answered 2021-Sep-08 at 08:48(✠Update Below) Insert the array elements to a std::unordered_set
and if the insertion fails, it means you have duplicates.
Something like as follows:
QUESTION
so - I have built a bit of a rules engine in python - but I'm fairly new to python... my engine is fairly nice to use - but adding a new rule is pretty ugly, and I'm wondering if there's a way to clean it up.
The key thing to remember is that rules have side-effects, rules can be combined with ands, ors, etc - and you only apply the side effects if the whole rule succeeded - ie the check if the rule succeeded can't be combined with perfoming the side effect.
So every rule ends up looking something like this:
...ANSWER
Answered 2022-Jan-05 at 22:26Instead of defining multi-line lambdas (which python doesn't allow), you could define multiple lambdas in a list and then use all lambdas in the list as required:
QUESTION
My question is about synchronizing threads. Basically, if I have an OpenMP
code in Fortran
, each thread is doing something. There are two possibilities for synchronizing them (let some variable have the same value in each thread), I think.
- add
!$OMP BARRIER
- add
!$OMP END PARALLEL
. If necessary, add!$OMP PARALLEL
and!$OMP END PARALLEL
block later on.
Are options 1) and 2) equivalent? I saw some question about barrier
in nested threads omp barrier nested threads
So far I am more interseted in simpler scanarios with Fortran
. E.g., for the code below, if I use barrier
, it seems the two if (sum > 500) then
conditions will behave the same, at least by gfortran
.
ANSWER
Answered 2021-Dec-28 at 12:09No, they are not equivalent at all.
For !$omp end parallel
let's think a little bit about how parallelism works within OpenMP. At the start of your program you just have a single so called master thread available. This remains the case until you reach a parallel region, within which you have multiple threads available, the master and (possibly) a number of others. In Fortran a parallel region is started with the !$omp parallel
directive. It is closed by a !$omp end parallel
directive, after which you just have the master thread available to your code until you start another parallel region. Thus !$omp end parallel
simply marks the end of a parallel region.
Within a parallel region a number of OpenMP directives start to have an affect. One of these is !$omp barrier
which requires that a given thread waits at that point in the code until all threads have reached that point (for a carefully chosen value of "all" when things like nested parallelism is in use - see the standard at https://www.openmp.org/spec-html/5.0/openmpsu90.html for more details). !$omp barrier
has nothing to do with delimiting parallel regions. Thus after its use all threads are still available for use, and outside of a parallel region it will have no effect.
The following little code might help illustrate things
QUESTION
I asked a question yesterday about template method overloading and resolving issues using type traits. I received some excellent answers, and they led me to a solution. And that solution led me to more reading.
I landed on a page at Fluent CPP -- https://www.fluentcpp.com/2018/05/18/make-sfinae-pretty-2-hidden-beauty-sfinae/ that was interesting, and then I listened to the Stephen Dewhurst talk that Mr. Boccara references. It was all fascinating.
I'm now trying to understand a little more. In the answers yesterday, I was given this solution:
...ANSWER
Answered 2021-Dec-14 at 16:34Vocabulary
QUESTION
There is a nice question (Which substitution failures are not allowed in requires clauses?) proposing the next problem.
One needs to write a compile-time function template constexpr bool allTypesUnique()
that will return true
if all argument types are unique, and false
otherwise. And the restriction is not to compare the argument types pairwise. Unfortunately, the answer only explains why such function cannot be implemented with some particular approach.
I think the solution can be achieved using multiple inheritance. The idea is to make a class inherited from a number of classes: one for each type T
in Ts
. And each such class defines a virtual function with a signature depending on T
. If some T
is found more than once in Ts
then function f
in a child class will override the function in a base class and it can be detected:
ANSWER
Answered 2021-Sep-18 at 21:35If you use virtual base classes depending on each of the given types, you will get exact one base class instance for every unique type in the resulting class. If the number of given types is the number of generated base classes, each type was unique. You can "measure" the number of generated base classes by its size but must take care that you have a vtable pointer inside which size is implementation dependent. As this, each generated type should be big enough to hide alignment problems.
BTW: It works also for reference types.
QUESTION
edit: I have followed up with a more specific question. Thank you answerers here, and I think the followup question does a better job of explaining some confusion I introduced here.
TL;DR I'm struggling to get proofs of constraints into expressions, while using GADTs with existential constraints on the constructors. (that's a serious mouthful, sorry!)
I've distilled a problem down to the following. I have a simple GADT that represents points called X
and function applications called F
. The points X
are constrained to be Objects
.
ANSWER
Answered 2021-Nov-23 at 10:52I think the correct solution should look something like this:
QUESTION
http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2011/n3255.html defines decay_copy
as follows:
ANSWER
Answered 2021-Oct-26 at 20:04It wasn't in 2011, because:
- We didn't have
auto
return type deduction for functions (that's a C++14 feature), and - We didn't have
auto&&
parameters for functions (that's a C++20 feature), and - Rvalue references were not implicitly moved from in return statements (that's also a C++20 feature)
But in C++20, yes, that is now a valid way to implement decay_copy
. auto
deduction does decay, return v;
implicitly forwards, and everything else is the same.
I guess technically there's an edge case like:
QUESTION
ANSWER
Answered 2021-Nov-18 at 00:03One option to achieve your desired result would be to use stat="bin"
in geom_text
too. Additionally we have to group
by year so that each year is a separate "block". The tricky part is to get the year labels for which I make use of after_stat
. However, as the group
s are stored internally as an integer sequence we have them back to the corresponding years for which I make use of a helper vector.
QUESTION
I'm wondering if there's any simpler way to assign multiple columns in Python, just like the :=
in R data.table
.
For example, in Python I would have to write like this:
...ANSWER
Answered 2021-Nov-14 at 06:21Would something like this work for you:
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