geospatial | R package for data | Dataset library
kandi X-RAY | geospatial Summary
kandi X-RAY | geospatial Summary
An R package with the data sets used in the DataCamp course Working with Geospatial Data in R.
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QUESTION
I have a spark dataframe that looks like this:
...ANSWER
Answered 2021-Jun-08 at 00:13I manage to solve the problem. I had to use the following function
QUESTION
Uber has released h3, a framework for efficiently handling big data in the geospatial file. Using h3, I attempted to get the location of a hexagonal grid location as shown in the figure. (https://eng.uber.com/h3/)
I got the location of the hexagonal grid from the following code. Then I plotted it on a two-dimensional map to see if it covered the entire earth. However, I'm not getting valid hexagons on the boundaries(-90°,90°,-180°,180°). And it doesn't seem to cover the entire globe. (hexagonal grid)
...ANSWER
Answered 2021-Jun-02 at 18:56Yes, H3 covers the entire globe. What you're seeing in that image are rendering artifacts - depending on how you render a global grid in a flat projection, you may get similar artifacts at the poles or across the antimeridian. See e.g. this map for a projection of H3 that renders correctly across the antimeridian, though it still has some issues around the poles.
QUESTION
I use the newest snapshot of Apache Sedona (1.3.2-SNAPSHOT) to do some geospatial work with my Apache Spark 3.0.1 on a docker cluster.
When trying out the first example in the tutorials section (http://sedona.apache.org/tutorial/sql/), I am suffering a NoClassDefException as a cause of a ClassNotFoundException:
...ANSWER
Answered 2021-May-31 at 12:11GeoSpark has moved to Apache-Sedona . Import dependencies according to spark version as below :
QUESTION
I am trying to include shapefiles as package data in Python, and I'm having a tough time understanding what to do with the stream
of data. Pandas' read_excel() and read_csv() work just fine, but when I try to access more complicated filetypes, I don't know what I should do:
ANSWER
Answered 2021-May-24 at 15:35geopandas.read_file()
should normally open it with GeoPandas 0.9.0 or newer. The following snippet works on my end. If you have some specifics which do not work, try to expand your question with a minimal reproducible example.
QUESTION
My approach to creating a choropleth map via plotly
seems pretty straightforward--load in the DataFrame, load in the geojson, assign the necessary features to the custom polygons, and plot.
Obviously there is a missed step somewhere when referencing of the custom polygons as only a blank map appears after a lengthy loading time.
One major thing to note is that about half of the polygons are located within states, but are their own custom polygon within the states. Therefore to my knowledge, choropleth_mapbox
is the more suitable solution.
A sample of the image, showing custom polygons within the states:
The code:
...ANSWER
Answered 2021-May-21 at 23:49Your output is not a choropleth_mapbox, it is a choropleth. Are you missing showing us any layout code? Without seeing all of your code, it's hard to determine the root cause of your issue so instead I'll show you a simple working example of how to connect a geojson to a dataframe and display it as a choropleth_mapbox below.
QUESTION
I'd like to do an Europe map, so I was trying with this code but I don't really know how it works.
...ANSWER
Answered 2021-May-19 at 18:16I think you assumed that the europa object still had an item named @data
, but if you look at it that is not the case:
QUESTION
I'd like to download inside Shiny a georeferenced PDF file (geoPDF) and for this a need some steps like convert the plot in ggplot format to tiff, populate the spatial coordinates, create a geo tiff, and finally my geoPDF. But several steps in downloadHandler()
function in tempdir()
directory results always in the error:
ANSWER
Answered 2021-May-15 at 20:54One thing I notice is that you have no output to file
in download handler. Perhaps your lines:
QUESTION
I have a Vue component like this...
...ANSWER
Answered 2021-May-05 at 11:42Yep, you are not mocking the store right. And I also would like to say, that you are using the store in a little strange way but it is up to you.
I made some changes to component to make the decision of your problem as clear as possible.
QUESTION
I have a set of geospatial data with me that also has the corresponding timestamps in a separate column.
Something like this:
Timestamp Latitude Longitude 1 1.56 104.57 2 1.57 105.42 4 1.65 103.32 12 1.76 101.15 14 1.78 100.45 16 1.80 99.65I want to be able to cluster the data based on their timestamps rather than their distances.
So for the above example, I should obtain 2 clusters: 1 from the 1st 3 data points, and 1 from the remaining 3. I would also like to obtain the range of timestamps for each cluster is possible.
From what I've researched so far, I've only gotten either geospatial distance clustering, or time-series clustering, both of which do not sound like what I need. Are there any recommended algorithms for what I am trying to do?
...ANSWER
Answered 2021-Apr-27 at 05:03Here density-based spatial clustering of applications with noise or shortly DBSCAN algorithm will be helpful in your case. DBSCAN is a density-based clustering algorithm which groups the points based on the closeness between them.
From what I understood in my quick research, DBSCAN draws a circle around its core. The circle's radius is called epsilon. All the points within the single circle will be counted in the same cluster. Larger the epsilon, the more points you will have in your cluster & vice versa.
There is more to this algorithm which you can find on this & this links.
Why DBSCAN is good for Timeseries Clustering:DBSCAN does not require k (number of clusters) as the input
In your case, there might be many clusters of time periods. Trying to fit an elbow curve to find the best number of clusters will be time-consuming & inefficient.
The below code snippet will do your task,
QUESTION
I have 3, two dimensional arrays that represent geospatial data. Each array shape is (721,1440)
, i.e., 721 latitude values and 1440 longitude values. I want to compute a weighted mean of these 3 arrays. Normally that is simple and would generally be sum(array*weight)/sum(weights). This works great except in cases where you have nans in the data.
In my specific case arr1
should have a weight of 0.7, arr2
0.2, and arr3
0.1. However, anytime there is a nan, the mean obviously becomes nan. In my case the only data with nans is arr3
.
What I want though is when there is a nan for the weighted mean to only comprise of the first two arrays, which would be (arr1*0.7 + arr2*0.2)/0.9
. I tried using xr.where()
to accomplish this but for some reason it goes hog wild on my RAM and crashes my kernel every single time. Are there any other ways to accomplish this task?
ANSWER
Answered 2021-Apr-19 at 15:01You can use np.nansum()
and np.isnan()
:
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