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QUESTION
I have two large-ish data frames I am trying to append...
In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.
In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.
Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.
Edit: dput(df2)
...ANSWER
Answered 2022-Apr-18 at 03:52Here's one way you could turn state abbreviations into state names using R's built in state vectors:
QUESTION
I have a dataset which include two columns (trip_start_date,trip_end_date). both of these columns were chr datatype so i converted them into dttm using this code:
...ANSWER
Answered 2022-Apr-01 at 21:23You are missing a mutate
.
QUESTION
I want to write a code that can be used on different XML files (all with TEI encoding) to see if specific elements and attributes appear, how often they appear and in what context). To do this I have written the following code:
...ANSWER
Answered 2022-Mar-20 at 19:59The values in your writer.writerow()
will not be defined if an element is missing. You could just define some default values to avoid this.
Try adding the following after the try
statement:
QUESTION
I am just getting started with regular expressions (working with the stringr
package), and I have written some code that does not do exactly what I want it to do. I am working with a dataset with some very messy string data and am trying to clean it up to be used with a google maps API.
I've attached a sample of the data below.
Basically, I want to select every row where loc_01
is a simple street name. By this, I mean I want it to take on the following formats:
A numbered street, such as 10th Ave
; A named street, such as MAIN ST
, and any directional modification of such street names (such as 10TH AVE NW, W MAIN ST, or W 10TH AVE
.)
I have tried the following expression:
...ANSWER
Answered 2022-Jan-04 at 17:35One way could be to add an additional filter
statement (though I'm sure there's a better way to do it).
QUESTION
I have preprocessed this a df containing info on US Emergency and Disaster history, to now contain the ```['Place, Disaster_type, Start_date, End_date Disaster_length, Year'] from 1960-2017.
Now, I would like to create 2 new dfs.
- = to the number of times a disaster occurred in each year,
- = to the number times each type of disaster occurred each year.
This is my current attempt at trying to calculate the number of disasters that happened each year and create a new df, but I'm not sure how to have it specifically count the number of disasters pear year.
...ANSWER
Answered 2021-Jul-10 at 21:05You can call size
on groupby
to get the counts.
QUESTION
I am currently trying to calculate the length of disasters, measured in days, and then with this column that is the difference between the start date and end date, use groupby ( I think), in order to sum the length of disasters for each year, as my data set is from 1960 to present. Eventually, I'd like to also group it by disaster type as well to see how the length of particular disasters changed overtime, but one step at a time.
So far I have converted the dates to pd.datetime format, and then used the code below to create the column with the difference of the two dates
...ANSWER
Answered 2021-Jul-07 at 11:36First change the column creation code to:
QUESTION
I have a data.frame with a column containing California counties in each cell separated by a space. I would like to add a comma and space after each one, however I can't just gsub every space into a comma and space, (i.e. gsub("\s",",\s",text)), as some counties in California have two names, (e.g. Los Angeles, San Francisco, etc.)
Fortunately, the two-word counties all have common first words so I'd like to write a gsub that preserves the space in those counties without adding a comma. I've attached example data as well as what I'd like the final form to look like. For instance, with this data, I'd like to add a comma and space except after "El", "San" and "Del".
Example data:
...ANSWER
Answered 2021-Jun-05 at 00:29Given that you know you are only looking for California counties, one "easy" way is just to replace only spaces that occur after a California county. To get that regex, I just concatenated the CA county names together with |
and added a space. The gsub
will replace any county name followed by a space with the same county name (\\1
), a comma, and a space.
QUESTION
The task at hand is mapping the empprevyearpct value to a county map. The sample data is below.
...ANSWER
Answered 2021-Apr-27 at 20:00You can use geo_join()
to join the two datasets together. After that, you can use geom_sf()
to map it out (this guide may help).
QUESTION
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
//.ts file
...ANSWER
Answered 2021-Apr-27 at 16:44You can do it with the $event
parameter.
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this c.state == val
might not work.
You can use the trim
function to compare your value safely:
c.state.trim() == val.trim()
HTML
QUESTION
I'm reading tables from a website where one of the columns is university name and some of the names have special characters which are the following (but the names are written like I put them here, so is not a task I can fix by reading the web in a different way):
...ANSWER
Answered 2021-Mar-30 at 12:26As Deceze has commented, if the data is corrupted at source there is no guarantee that you can undo the corruption. However, using the data you provided we can make some progress.
Firstly, the vast majority of the strings in your list can be fixed by encoding as latin-1 and then decoding as UTF-8.
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