autoplot | Automatic plotting with ggplot | Data Visualization library
kandi X-RAY | autoplot Summary
kandi X-RAY | autoplot Summary
ggplot2 is a versatile plotting package which allows to produce almost any kind of plot from data stored as a data.frame, by combining unit elements. However, it requires the user to design the plot entirely, from scratch. Many R functions for statistical analyses (linear models, mutlivariate analyses, etc.) output objects of a given class and allow to easily plot classic diagnostics using plot(), by defining a specialized method for this generic function. This package aims at reproducing this functionality in ggplot2 while benefiting from its improved versatility. It provides two sets of methods : (i) the augment() methods extract data from the original object and format it as a data.frame (see package broom); (ii) the autoplot() methods use these data.frames and leverage ggplot2 to produce diagnostic plots.
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QUESTION
I the following code:
...ANSWER
Answered 2022-Apr-01 at 13:11Obviously we don't have your data, but using a simple random example should show the options here.
QUESTION
When I plot the survfit plot of data with two different censoring events, the overall plot (s0) doesnt start at time = 0, pstate = 100%, but jumps to 100% when the first cencoring event occurs.
Here you can see in an example, where the jump occurs at time 1, that is the first cencoring event.
...ANSWER
Answered 2022-Mar-30 at 22:53This does seem to be a bug in ggfortify. As a temporary fix, you can set the survival percentage at t = 0 to 100% by doing:
QUESTION
In order to make a time series app with plot for analysis, I want to use the autoplot function of the forecast package, to provide stl decomposition.
However, it seems like there is no functionality given, to resize the text size of x and y axis. The base plot() arguments have no effect:
...ANSWER
Answered 2022-Mar-18 at 11:28autoplot
comes from ggplot2. So you will need to use the ggplot2 functions to adjust items from the autoplot
.
E.g. for adjusting the title size:
QUESTION
I am generating kaplan-meier plots within R and I was wondering if there were a way to create an interactive kaplan-meier plot using the plotly
package? Ideally, I would like to be able to trace the survival "line" using my mouse cursor with the plotly
tooltip box telling me the group, the survival rate, and the time as well.
Here is an mock example of survival analysis that I would like to recreate within plotly
:-
ANSWER
Answered 2022-Feb-22 at 13:01One option is to extract the ggplot figure from a ggsurvplot
object.
QUESTION
I made a PCA plot with autoplot(), but I wanted to have ellipses around only 2 of the groups instead of all 3. Therefore I switched to ggplot. However, it seems that my axes are different between autoplot and ggplot methods. Look at the difference between p1 and p2:
...ANSWER
Answered 2022-Feb-22 at 12:44In the autoplot method, the principal components are scaled, so to get the same result you would do:
QUESTION
I have a PCA plot created with ggplot/ggfortify
and the function autoplot()
, such as in this question: Change point colors and color of frame/ellipse around points
ANSWER
Answered 2022-Feb-21 at 21:44The problem with using autoplot
is that, although it is great for producing nice visualizations of common data structures and models with little effort, it doesn't give you the full freedom to customize the plot. However, it is pretty straightforward to do the whole thing within ggplot. The following is a full reprex:
QUESTION
I want to add a new line and confidence band to a survival analysis plot (Kaplan-Meier curve) created using autoplot
from the ggfortify
package.
However, I receive an error when using geom_ribbon
but not when using geom_line
. The minimal example below illustrates the issue.
ANSWER
Answered 2022-Feb-21 at 04:16If you specify inherit.aes = FALSE
in geom_ribbon()
you avoid that specific error, i.e.
QUESTION
I'm trying to run different forecast modeling methods on a monthly tsibble dataset. Its head() looks like:
...ANSWER
Answered 2021-Dec-17 at 14:57Thanks for the example, I was able to get it to run without any errors, as follows:
QUESTION
I'm novice in R and im doing a forecast for my dataset, as you can see in the diagram, the data before 2019,04 is training data, the part in blue (start from 2019,04- 2019,12) is my forecast and the red line is the test data(2019,04- 2019,12), the time interval is identical, but in the diagram it isn't continuous, how can I fix it?
...ANSWER
Answered 2022-Feb-13 at 10:28if by continuous you mean that the black line is not "connected" to the red nor the blue: each line has a first and last observation which are connected via lines (and have possibly more observations).
Your first value to predict (or test) is, chronologically speaking, after the training data, thus the black line will not reach the blue and red. Also the blue and red line can not reach back to connect as the last observation from training data is not included in theire data.
After forecasting you could include the last observation from the training data in test and prediction set. This will lead to a "continuous" line when plotting.
QUESTION
I have a dataset with time, status ( 1=death, 0 = censored), treatement =1,2 .
I create my survival object km_2, I want to plot Kaplan-Meijer plot using autoplot(). I do not know what my mistake is but setting the attributes ( legendLabs for example ) do not make any change to the basic KM plot.
ANSWER
Answered 2022-Feb-11 at 22:10There are a few things to point out here. Firstly, autoplot
is a generic function, so the method used and the arguments it accepts depends on the type of object you are passing to it. In this case, you are passing a survfit
object, and you will be able to see the correct parameters to use if you type ?autoplot.survfit
into the console.
From this you will see that there is no legendLabs
or plotTable
option, and that the alpha for the confidence intervals is controlled with conf.int.alpha =
. Similarly, the censoring shape is controlled with censor.shape
.
Another issue is that there doesn't seem to be a way to change the factor labels in the legend, but in this case it is easy enough to change them in the data when you create the survfit
object.
Lastly, it's a good idea to make a reproducible example if you want prompt and useful answers. It took a while to recreate a reasonable data structure to test and demonstrate this answer.
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