gender | Predict Gender from Names Using Historical Data | Development Tools library

 by   lmullen R Version: v0.5.2 License: Non-SPDX

kandi X-RAY | gender Summary

kandi X-RAY | gender Summary

gender is a R library typically used in Utilities, Development Tools applications. gender has no bugs, it has no vulnerabilities and it has low support. However gender has a Non-SPDX License. You can download it from GitHub.

Data sets, historical or otherwise, often contain a list of first names but seldom identify those names by gender. Most techniques for finding gender programmatically rely on lists of male and female names. However, the gender associated with names can vary over time. Any data set that covers the normal span of a human life will require a historical method to find gender from names. This R package uses historical datasets from the U.S. Social Security Administration, the U.S. Census Bureau (via IPUMS USA), and the North Atlantic Population Project to provide predictions of gender for first names for particular countries and time periods.
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            kandi-support Support

              gender has a low active ecosystem.
              It has 153 star(s) with 27 fork(s). There are 14 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 8 open issues and 44 have been closed. On average issues are closed in 121 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of gender is v0.5.2

            kandi-Quality Quality

              gender has 0 bugs and 0 code smells.

            kandi-Security Security

              gender has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              gender code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              gender has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              gender releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            gender Key Features

            No Key Features are available at this moment for gender.

            gender Examples and Code Snippets

            Predict the gender of each face .
            pythondot img1Lines of Code : 56dot img1License : Permissive (MIT License)
            copy iconCopy
            def predict_gender():
                """Predict the gender of the faces showing in the image"""
                # create a new cam object
                cap = cv2.VideoCapture(0)
            
                while True:
                    _, img = cap.read()
                    # resize the image, uncomment if you want to resize   
            Predict age and gender .
            pythondot img2Lines of Code : 47dot img2License : Permissive (MIT License)
            copy iconCopy
            def predict_age_and_gender(input_path: str):
                """Predict the gender of the faces showing in the image"""
                # Initialize frame size
                # frame_width = 1280
                # frame_height = 720
                # Read Input Image
                img = cv2.imread(input_path)
                # re  
            Aggregate sales by gender .
            javadot img3Lines of Code : 10dot img3License : Permissive (MIT License)
            copy iconCopy
            private static Dataset aggregateYearlySalesByGender(Dataset dataset) {
            
                    Dataset aggDF = dataset.groupBy(column("year"), column("source"), column("gender"))
                        .sum("transaction_amount")
                        .withColumnRenamed("sum(transaction  

            Community Discussions

            QUESTION

            R plotly separate functional legends
            Asked 2022-Mar-29 at 09:55

            I want to produce a plot via R plotly with independent legends while respecting the colorscale.

            This is what I have:

            ...

            ANSWER

            Answered 2022-Mar-19 at 15:21

            This isn't exactly what you're looking for. I was able to create a meaningful color bar, though.

            I removed the call for interaction between the groups and created a separate trace. Then I created legend groups and named them to create separate legends for gender and age. When I pull color = out of the call to create a colorbar, this synced the color scales.

            However, it assigns colors to the labels for age and gender and that's not meaningful! There are a few things that don't line up with your request, but someone may be able to build on this information.

            Source https://stackoverflow.com/questions/71494308

            QUESTION

            How can I merge two dataframes together with some conditional requirements?
            Asked 2022-Mar-22 at 14:33

            I have two dataframes, df1 and df2. I would like to join the two with the following conditions:

            1. merge df1 and df2 on gender and Test
            2. TestDate in df1 need to be within Date1 and Date2 from df2
            3. all.x = TRUE (keep df1 records)

            How can I handle the second part?

            ...

            ANSWER

            Answered 2022-Mar-21 at 14:44

            Does this work for you?

            Source https://stackoverflow.com/questions/71559360

            QUESTION

            Multiple dimensions conditions in SSAS MDX query not working
            Asked 2022-Feb-25 at 21:19

            I Am having the following data in my SSAS cube.

            My need is to get the value of the measure based on two conditions with two different dimensions using the MDX.

            In this example data, I need to get the Reseller Sales Amount value where the value of Title dimension is equal to Sales Representative and the value of the Genderdimension is equal to Male condition.

            I have tried to achieve the requirement with the Case statement and IIF() function available in the MDX but it is not working.

            Please find the queries I have tried with different functions.

            Using Case statement:

            ...

            ANSWER

            Answered 2022-Feb-25 at 12:03

            You can use a Tuple either directly in the calculated measure:

            Source https://stackoverflow.com/questions/71263212

            QUESTION

            Calibration based on the total of a variable other than the population
            Asked 2022-Feb-18 at 16:08

            I've been working on some survey data using the survey package. I read the documentation available on post-stratification and calibration, however I got stuck trying to calibrate the sampling weights on a total known for the population that is not the population total.

            To make my self clear I prepared an example: Let's say I have income information for a sample stratified by sex, which lets me create the svydesign object:

            ...

            ANSWER

            Answered 2022-Feb-17 at 04:09

            Here is a workaround.

            all your data is stored at dis$variables, from there you can export it and make your calculations. I hope this can inspire better solutions

            Source https://stackoverflow.com/questions/71057827

            QUESTION

            Transforming dummy variables to single column in R
            Asked 2022-Jan-04 at 20:48

            I have the following table in R which lists a person race, gender, age, and cholesterol test. age and cholesterol test are displayed as dummy variables. age can be categorized as low, medium, or high, while cholesterol tests can be categorized as low or high. I want to transform the age and cholesterol columns to be single columns where low is categorized as 1, medium is categorized as 2, and high is categorized as 3. Cholesterol test can be neigh low or high if a person never took one and should be N/A in the expected output. I want the solution to be dynamic so that if I have multiple columns in this format, the code would still work (i.e. there may be some new tests, which can be categorized as high, low, or medium as dummy variables).

            How can I do this in R?

            input:

            ...

            ANSWER

            Answered 2022-Jan-03 at 18:33

            QUESTION

            Using apply function works, however using .assign() the same function does not?
            Asked 2021-Dec-14 at 17:39

            I am a bit stuck, I have a working function that can be utilised using .apply(), however, I cannot seem to get it to work with .assign(). I'd like this to work with assign, so I can chain a number of transformations together.

            Could anyone point me in the right direction to resolving the issue?

            This works

            ...

            ANSWER

            Answered 2021-Dec-14 at 17:39

            From the documentation of DataFrame.assign:

            DataFrame.assign(**kwargs)

            (...)

            Parameters **kwargs : dict of {str: callable or Series}

            The column names are keywords. If the values are callable, they are computed on the DataFrame and assigned to the new columns. The callable must not change input DataFrame (though pandas doesn’t check it). If the values are not callable, (e.g. a Series, scalar, or array), they are simply assigned.

            This means that in

            Source https://stackoverflow.com/questions/70324030

            QUESTION

            Cannot construct instance of `com.domain.User` (no Creators, like default constructor, exist): cannot deserialize from Object value
            Asked 2021-Nov-28 at 12:49

            I have a controller that accepts ObjectNode as @RequestBody.

            That ObjectNode represents json with some user data

            ...

            ANSWER

            Answered 2021-Nov-28 at 12:22

            Register Jackson ParameterNamesModule, which will automatically map JSON attributes to the corresponding constructor attributes and therefore will allow you to use immutable classes.

            Source https://stackoverflow.com/questions/70143308

            QUESTION

            Shiny app produces error: "arguments imply differing number of rows: 0, 1"
            Asked 2021-Oct-11 at 01:32

            I am trying to create an R Shiny app that calculates a score using ridge regression and then uses that in a random forest model. I saved both models as RDS and kept them in the same folder where the app.R is.

            Then I read the models and data of predicted probabilities and define some functions:

            ...

            ANSWER

            Answered 2021-Oct-11 at 01:32

            The orignial error is occuring because you are not asking for the same input$id as the id you assign in textInput.

            Source https://stackoverflow.com/questions/69453274

            QUESTION

            Tree data structure with multiple keys for each item
            Asked 2021-Sep-18 at 16:06

            I'm working on a chat application using node js that displays a list of online users. Each user has the following attributes:

            ipv4, rank, score, login time

            ipv4 is used when accessing a user.

            Users should be listed according to this sorting strategy:

            • Users with higher rank should be at the top of the list.
            • If the user rank is equal, the users with the highest score should be at the top of the list after high-rank users.
            • If the user score is equal, users with less login time should be at the top of the list after high-score users.

            for example:

            1. Login userA (ipv4:1.1.1.1, rank:0, score:3000, loginTime:1631966424070)

            • list: [userA]

            2. Login userB (ipv4:2.2.2.2, rank:1, score:2000, loginTime:1631966424080)

            • list: [userB, userA]

            3. Login userC (ipv4:3.3.3.3, rank:1, score:1000, loginTime:1631966424090)

            • list: [userB, userC, userA]

            4. Login userD (ipv4:4.4.4.4, rank:0, score:3000, loginTime:1631966424100)

            • list: [userB, userC, userA, userD]

            Access example:

            Get user(ipv4:3.3.3.3) -> return userC

            There are many users and I use the functional-red-black-tree data structure to improve performance. In this data structure, each item has a key and a value. The constructor of this tree takes a comparator function -like array sort comparator- with two parameters, each of which are keys, as a parameter.

            I have defined the user as follows:

            ...

            ANSWER

            Answered 2021-Sep-18 at 16:06

            In your rand example, it is normal that the key (10, 0, 0, 0) will not match, even though ipv4=10 is somewhere in the tree. This is because that node will be more like (10, 66, 35, 19)... which will not be encountered, as the ordering of the tree is mainly based on rank, not on ipv4. The decision to where to drill down in the tree will be based on rank (0), moving to the left side of the tree, while the node you intend to find may be at the right (higher rank 66).

            What you can do is to accompany the tree with a Map, which will map an ipv4 value with an existing Key instance. So every time you insert in the tree, also add the corresponding mapping in that Map. And every time you want to find or want to delete, first retrieve the Key instance from that Map by the ipv4 value you have, and pass that Key instance to the tree's get or remove method.

            Here is a wrapper class that makes this combination. Extend it with any other method you want to include:

            Source https://stackoverflow.com/questions/69235158

            QUESTION

            Why I'm not kept logged in when using Passport and sessions? Passport's "isAuthenticated()" always returns false
            Asked 2021-Sep-13 at 15:00

            I am using Angular, Passport and sessions for authentication. I can create a new user, login but,

            Problem

            when checking if the user is logged using Passport's isAuthenticated() function always returns false. I followed the instructions from various online resources and I am unsure if:

            Question

            I can use passport and sessions with my Angular app? or I am just doing something wrong in my code? I would really appreciate it if you guys have any idea/hint why it's not working. Thank you.

            Backend code

            ...

            ANSWER

            Answered 2021-Sep-13 at 15:00

            I'm just guessing what's wrong because you didn't precise the port of your application in your question, but I assume it's 4200 as I see that you have added these lines to the original project:

            Source https://stackoverflow.com/questions/69118251

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install gender

            You can install this package from CRAN:. The first time you use the package you will be prompted to install the accompanying genderdata package. Alternatively, you can install this package for yourself.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone lmullen/gender

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            git@github.com:lmullen/gender.git

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