pmatch | Pattern matching DSL for R

All depends on how varied the location could be and other scenario shapes.

You could separate the column into 2 and then group and count

The issue you do not get offsets for the first capturing group is that you pass 1 as the third, size_t __nmatch, argument to regexec.

The 1 value should be changed to 2 as there will be two groups whenever \(.\)ave regex matches: Group 0 will be holding the whole match and Group 1 will hold the first capturing group value.

So, you need to use

TLDR: the first one listed, so "pearson"

A bit more info:

Line 8 specifies that method <- match.arg(method).

This means that if the user specified method="something" then "something" is used.

However, if the user does not specify the method argument, then the default method = c("pearson", "kendall", "spearman") is used. Ah, but then you will ask, which one? There's 3 listed there! The answer to that is in how the match.arg function works. See ?match.arg, which states that the first element is used.

So in this case, if you call cor(x, y) without specifying the method argument, it's the same as cor(x, y, method="pearson"). @missuse provides an example in the comments at the top, which I've copied here:

You could do:

Perhaps there is a way to get the desired output from pmatch, but I have not been able to figure out how. I tried looking at the source code for the pmatch function here:

Your code is hugely confused. In fact it's so confused I'm not sure what you're trying to do completely: I've based my answer on what you say the classifier should produce at the start of your question.

• First of all your macro refers to sexpr which has no meaning in the macro, and because Scheme macros are hygienic it will definitely not refer to the sexpr which is the argument to classify-sexpr.
• Secondly you don't need a macro at all here. I suspect that you may be thinking that because you are trying to write a macro you must use macros in its construction: that's not necessarily true and often a bad idea.
• Thirdly the syntax of your cond is botched beyond repair: I can't work out what it's trying to do.
• Finally the list classification will never be needed: if you want to classify (1 2 3 (x)) as (number number number (symbol)) then you'll simply never reach a case where you have a list which you want to classify since you must walk into it to classify its elements.

Instead just write the obvious functions do do what you want:

After a long time of trying, i learned a bit more about string manipulation and got it. Probably not the most efficient way but it worked.

OBS: i marked commentaries with "¹", "²", and "³" so that i can explain later.

This is not a fully general solution but hopefully illustrates all the necessary base helper metaprogramming functions you'll need to get there.

We first have to get the names of the available arguments:

Arthur! It seems related to the line separation you are using as expected result. This result with "\r\n" will match only the HTML got by running it in a Windows environment. If your server is a Unix-based one, it won't match, as the line separation is "\n" there.

Try to remove the \r from the expected result and re-run your application.