InformationValue | Information Value CRAN Pkg : Performance Analysis | Development Tools library

by selva86 R Version: Current License: No License

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kandi X-RAY | InformationValue Summary

InformationValue is a R library typically used in Utilities, Development Tools applications. InformationValue has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Information Value CRAN Pkg: "Performance Analysis and Companion Functions that Aid Accuracy Improvement for Binary Classification Models". Author: "Selva Prabhakaran" selva86@gmail.com.

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InformationValue has a low active ecosystem.

It has 9 star(s) with 3 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

There are 3 open issues and 0 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of InformationValue is current.

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InformationValue has no bugs reported.

Security

InformationValue has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

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InformationValue does not have a standard license declared.

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InformationValue releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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Community Discussions

Trending Discussions on InformationValue

sql query about latest date

joining two tables with group by in sql

PL/SQL procedure to output line the given date if not existing, latest date should be given

sql query about given date if not existing, give latest date

Error in xj[i] : invalid subscript type 'list' when do LDA in R

WOE transformation for validation data

QUESTION

sql query about latest date

Asked 2020-May-20 at 03:36

I have these two tables.

...

ANSWER

Answered 2020-Mar-23 at 22:40

You would need to correlate the subquery to the outer query, so it gives you the latest date per attribute rather than the overal latest date.

Also it is unclear to me why you need that computation with count(distinct ...) in the outer query.

Side note: always use modern, standard join syntax (with the on keyword) rather than implicit joins (with a comma in the from clause).

I would suggest:

Source https://stackoverflow.com/questions/60822475

QUESTION

joining two tables with group by in sql

Asked 2020-Apr-19 at 09:25

hello i am trying to join these two tables but am not able to. i have the data seperately but unfortunately i cant join them as there is a group by statement involved in table nr 2 which makes the join a little bit complicated.

table nr 1; -- includes all data

...

ANSWER

Answered 2020-Mar-17 at 21:37

You seem to be looking to pull out the most recent price per attribute. If so, you can filter with a correlated subquery that gives you the last date per attribute:

Source https://stackoverflow.com/questions/60730533

QUESTION

PL/SQL procedure to output line the given date if not existing, latest date should be given

Asked 2020-Mar-24 at 16:21

I have this table informationvalues with the contents:

Now I create a procedure where I need to input a date parameter which should output line the correct attr with given price. If the date doesn't exist the latest date should be selected.

The solution table for to_date('01-jan-19') would look like this:

This would be then output line in the procedure.

Should I select to correct tuple and output line it or would it be best to just bulk collect everything and then check in a for loop with an if statement what tuple I need to display.

What I have so far:

A select statement with the tuples I am looking for:

...

ANSWER

Answered 2020-Mar-24 at 16:21

Please try:

Source https://stackoverflow.com/questions/60831284

QUESTION

sql query about given date if not existing, give latest date

Asked 2020-Mar-24 at 15:37

I have this table.

InformationValues(attr , dateOfValue, price)

Table Content:

I need to select all attr with the same date if it doesn't exist the latest date should be selected.

For example with TO_DATE('01-jan-19')

Solution table should look like this:

My sql query so far:

...

ANSWER

Answered 2020-Mar-24 at 07:49

I was confused by the question

if you mean, the data chosen is crossed out, try this one:

Source https://stackoverflow.com/questions/60824002

QUESTION

Error in xj[i] : invalid subscript type 'list' when do LDA in R

Asked 2019-Mar-16 at 12:48

mydat=structure(list(spent = c(73.5, 73.5, 73.5, 73.5, 73.5, 73.5, 
73.5, 73.5, 73.5, 73.5, 73.5, 29.74, 29.74, 29.74, 29.74, 29.74, 
29.74, 29.74, 29.74, 29.74, 29.74, 29.74, 73.71, 73.71, 73.71, 
73.71, 73.71, 73.71, 73.5, 73.5, 73.5, 73.5, 73.5, 73.5, 73.5, 
73.5, 73.5, 73.5, 73.5, 29.74, 29.74, 29.74, 29.74, 29.74, 29.74, 
29.74, 29.74, 29.74, 29.74, 29.74, 73.71, 73.71, 73.71, 73.71, 
73.71, 73.71), realpurchase_cash = c(501, 502, 503, 504, 505, 
506, 507, 508, 509, 510, 511, 512, 513, 514, 515, 516, 517, 518, 
519, 520, 521, 522, 523, 524, 525, 526, 527, 528, 73.5, 73.5, 
73.5, 73.5, 73.5, 73.5, 73.5, 73.5, 73.5, 73.5, 73.5, 29.74, 
29.74, 29.74, 29.74, 29.74, 29.74, 29.74, 29.74, 29.74, 29.74, 
29.74, 73.71, 73.71, 73.71, 73.71, 73.71, 73.71), id = c(123L, 
123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 
123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 123L, 
123L, 123L, 123L, 123L, 123L, 124L, 124L, 124L, 124L, 124L, 124L, 
124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L, 
124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L, 124L
), flag = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 0L, 
0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 
0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L)), .Names = c("spent", 
"realpurchase_cash", "id", "flag"), class = "data.frame", row.names = c(NA, 
-56L))

...

ANSWER

Answered 2019-Mar-16 at 12:48

subset wants a vector and you give him a data frame (i.e. a list). Do

Source https://stackoverflow.com/questions/55196855

QUESTION

WOE transformation for validation data

Asked 2019-Feb-23 at 22:04

I'm doing logistic regression & XGBoost and converted all variable into WOE's. This was done for the training data set. Now I would like to validate my model on my validation & out-of-sample test data. WOE were produced by using the Hmisc::CUT2 function and then apply InformationValue::WOE

...

ANSWER

Answered 2019-Feb-23 at 22:04

Finally i have a solution,

using package: scorecard is helpful. In my case i used the determined breaks breaks_list in scorecard::woebin und create the data with scorecard::woebin_ply

Source https://stackoverflow.com/questions/54803289

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You can download it from GitHub.

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