lubridate | Make working with dates in R just that little bit | Date Time Utils library

by tidyverse R Version: v1.9.2 License: GPL-3.0

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kandi X-RAY | lubridate Summary

lubridate is a R library typically used in Utilities, Date Time Utils applications. lubridate has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Date-time data can be frustrating to work with in R. R commands for date-times are generally unintuitive and change depending on the type of date-time object being used. Moreover, the methods we use with date-times must be robust to time zones, leap days, daylight savings times, and other time related quirks, and R lacks these capabilities in some situations. Lubridate makes it easier to do the things R does with date-times and possible to do the things R does not. If you are new to lubridate, the best place to start is the date and times chapter in R for data science.

Support

Quality

Security

License

Reuse

Support

lubridate has a low active ecosystem.

It has 685 star(s) with 199 fork(s). There are 47 watchers for this library.

It had no major release in the last 12 months.

There are 62 open issues and 854 have been closed. On average issues are closed in 323 days. There are 4 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of lubridate is v1.9.2

Quality

lubridate has 0 bugs and 0 code smells.

Security

lubridate has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

lubridate code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

lubridate is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

lubridate releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

It has 5515 lines of code, 0 functions and 1 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

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lubridate Key Features

No Key Features are available at this moment for lubridate.

lubridate Examples and Code Snippets

No Code Snippets are available at this moment for lubridate.

Community Discussions

Trending Discussions on lubridate

Remove values from one list based on the IDs removed from another

Count observations over rolling 30 day window

Is there a new solution for downloading package and dependencies for a given R version

Transferring an Excel Moving Average Calculator to R

do() superseded! Alternative is to use across(), nest_by(), and summarise, how?

Transforming complete age from character to numeric in R

Call function to generate the value but without plotting the graph

R Lubridate dmy output format

Merging two Data frames with fuzzy merge/sqldf

How to monthly summarise daily data, using dplyr and lubridate, only if less than 10 days per month are NAs?

QUESTION

Remove values from one list based on the IDs removed from another

Asked 2022-Apr-07 at 21:00

I have a data frame that I have split into a list based on ID (l1). I also have another list l2 that is connected to l1 based on the ID names. One of the list elements has a NA value, and I have removed that element out of the list (l2_new).

I would like to be able to remove the same ID value from l1 that I removed from l2 due to the NA value leading to the expected object. Is there a good way to do this (preferably in base R)?

...

ANSWER

Answered 2022-Apr-07 at 21:00

We can use the names of 'l2_new' to subset the 'l2'

Source https://stackoverflow.com/questions/71788849

QUESTION

Count observations over rolling 30 day window

Asked 2022-Feb-17 at 15:41

I need to create a variable that counts the number of observations that have occurred in the last 30 days for each id.

For example, imagine an observation that occurs on 1/2/2021 (d / m / y) for the id "a". If this observation is the first between 1/1/2021 and 1/2/2021 for the id "a" the variable must give 1. If it is the second, 2, etc.

Here is a larger example:

...

ANSWER

Answered 2022-Feb-17 at 15:41

Left join dat to itself on the indicated condition grouping by the rows of the left hand data frame. We assume that you want a 30 day window ending at current row but if you wanted 30 days ago (31 day window) then change 29 to 30. Both give the same result for this data.

Source https://stackoverflow.com/questions/71159724

QUESTION

Is there a new solution for downloading package and dependencies for a given R version

Asked 2022-Feb-09 at 03:33

I have seen the question asked here from 2018. I'm wondering if there is a better answer today.

Our work computers are bedeviled by an entire IT security department that seems to exist to make them useless. We are allowed to run R 3.6.3 (4.x hasn't been approved yet). We cannot connect to CRAN from behind the corporate firewall. In the past that meant we took our laptops home to install packages. But now we have a download monitor that blocks CRAN downloads even when we're on our own wi-fi.

I was attempting to get around this by downloading the package .zip files on a personal machine, transferring them via CD, and then installing with repos=NULL. I used this code

...

ANSWER

Answered 2022-Feb-09 at 03:33

I'm not sure if it completely addresses your needs, but package checkpoint seems appropriate here. It allows you to download source packages from a snapshot of CRAN taken at a specified date, going back to 2014-09-17. R 4.0.0 was released around 2020-04-24, so the snapshot from 2020-04-01 should work for your purposes.

Here is a reproducible example:

Source https://stackoverflow.com/questions/71021876

QUESTION

Transferring an Excel Moving Average Calculator to R

Asked 2022-Jan-28 at 22:18

so I've been trying to teach myself R and have a calculator I created in excel that I'm trying to get working in R.

In R, I'd like to calculate a 45 day moving average based on loan prices I have. The data sample in excel is here:

dput output in R is here:

...

ANSWER

Answered 2022-Jan-28 at 19:37

Something like this? I have defined a variable ndays to test with the posted data.
Also note that since Loan is a logical variable, there is no need to test the equality with TRUE or "TRUE".

Source https://stackoverflow.com/questions/70899085

QUESTION

do() superseded! Alternative is to use across(), nest_by(), and summarise, how?

Asked 2022-Jan-20 at 20:08

I'm doing something quite simple. Given a dataframe of start dates and end dates for specific periods I want to expand/create a full sequence for each period binned by week (with the factor for each row), then output this in a single large dataframe.

For instance:

...

ANSWER

Answered 2022-Jan-19 at 16:23

Not sure if this exactly what you are looking for, but here is my attempt with rowwise and unnest

Source https://stackoverflow.com/questions/70773763

QUESTION

Transforming complete age from character to numeric in R

Asked 2021-Dec-01 at 22:20

I have a dataset with people's complete age as strings (e.g., "10 years 8 months 23 days) in R, and I need to transform it into a numeric variable that makes sense. I'm thinking about converting it to how many days of age the person has (which is hard because months have different amounts of days). So the best solution might be creating a double variable that would show age as 10.6 or 10.8, some numeric variable that carries the information that 10years 8month 5days is greater than 10years 7month 12days.

Here is an example of the current variable I have

...

ANSWER

Answered 2021-Dec-01 at 21:26

Split on space, then compute. Note, you might want to change the average days in a year, in a month as needed:

Source https://stackoverflow.com/questions/70191127

QUESTION

Call function to generate the value but without plotting the graph

Asked 2021-Nov-25 at 18:48

I have a function where it is possible to generate a map and a coef_val value, but I would like to know if it is possible to call this same function and get just the generated value, without plotting the graph? One possibility that I know exists is to make a new function, for example, f2, without the plotting part, but I wouldn't want to do it this way. Is there another way?

...

ANSWER

Answered 2021-Nov-20 at 16:52

You can redirect the plot to a NULL file. Relevant section from help(pdf):

file: a character string giving the file path. [...] If it is ‘NULL’, then no external file is created (effectively, no drawing occurs) [...]

So, in order to not produce any plot:

Source https://stackoverflow.com/questions/70014020

QUESTION

R Lubridate dmy output format

Asked 2021-Nov-20 at 16:40

I'm working with Lubridate package for formatting the dates in my data.

...

ANSWER

Answered 2021-Nov-20 at 16:40

lubridate::dmy() creates a date-object from a string in the DMY format.

When you print a date object, it is by default shown in the ISO 8601 format aka YYYY-MM-DD.

To print the date in the DMY format, you can use format(date, "%d/%m/%y") (note that this will convert the date object to a string).

To change the default way dates are printed, you have to look at locales (eg see this).

Source https://stackoverflow.com/questions/70047717

QUESTION

Merging two Data frames with fuzzy merge/sqldf

Asked 2021-Nov-05 at 19:16

I have the following dataframes (df11 and df22) I'd like to do a merge/full join on with "UserID=UserID" and date difference <= 30 . So if the UserIDs match up AND the date's are less than or equal to 30, I'd like them merged into one singular row. I've looked at fuzzy join here and sqldf here but I can't figure out how to implement either of those for my data frames.

...

ANSWER

Answered 2021-Nov-05 at 17:59

One way is to first create "+/- 30 day" columns in one of them, then do a standard date-range join. Using sqldf:

Prep:

Source https://stackoverflow.com/questions/69856811

QUESTION

How to monthly summarise daily data, using dplyr and lubridate, only if less than 10 days per month are NAs?

Asked 2021-Oct-30 at 23:55

I have daily meteorological data (temperature and precipitation) from 1955 to 2017 from different locations and I want to summarize each variable into monthly averages but only if the number of NAs in each month is less than 10.

I put four months of temperature data with different amounts of NAs as example (1st month: 1 NA, 2nd month(31days): 30 NA, 3rd month: 0 NA, 4th month: all data as NA):

...

ANSWER

Answered 2021-Oct-30 at 23:55

library(dplyr)
library(lubridate)

df %>% 
  mutate(month = month(DATE),
         year = year(DATE)) %>% 
  group_by(month, year) %>% 
  summarize(prcp = if (sum(is.na(TMAX)) <= 10) mean(TMAX, na.rm = T) else NA,
            .groups = "drop")

Source https://stackoverflow.com/questions/69745643

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

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Install lubridate

You can download it from GitHub.

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For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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