magrittr | Improve the readability of R code with the pipe

by tidyverse R Version: v2.0.3 License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | magrittr Summary

magrittr is a R library. magrittr has no bugs, it has no vulnerabilities and it has medium support. However magrittr has a Non-SPDX License. You can download it from GitHub.

The magrittr package offers a set of operators which make your code more readable by:.

Support

Quality

Security

License

Reuse

Support

magrittr has a medium active ecosystem.

It has 934 star(s) with 154 fork(s). There are 55 watchers for this library.

It had no major release in the last 12 months.

There are 19 open issues and 172 have been closed. On average issues are closed in 122 days. There are 3 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of magrittr is v2.0.3

Quality

magrittr has 0 bugs and 0 code smells.

Security

magrittr has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

magrittr code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

magrittr has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

magrittr releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

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magrittr Key Features

No Key Features are available at this moment for magrittr.

magrittr Examples and Code Snippets

No Code Snippets are available at this moment for magrittr.

Community Discussions

Trending Discussions on magrittr

Looping `lm` objects using `purrr::map` into `broom::tidy`

How to access group ids for grouped filter operation?

R plotly: Display image on hover

Combine character variable over rows and columns by group in R

Make centered LaTeX tabular table using knitr kable

Breaking up observations across multiple dates in R

Should I use %$% instead of %>%?

How to convert a list of characters that is stored in a single value (per record) into a format that can be analyzed? R

How to automate legends for a new geom in ggplot2?

How to use an expression in dplyr::mutate in R

QUESTION

Looping `lm` objects using `purrr::map` into `broom::tidy`

Asked 2022-Apr-10 at 20:47

I have a several lm objects that I would like to loop into broom::tidy using purrr::map. Is this possible to do?

...

ANSWER

Answered 2022-Apr-10 at 20:47

You need to keep your models in a list (list()), not in a vector (c()):

Source https://stackoverflow.com/questions/71820400

QUESTION

How to access group ids for grouped filter operation?

Asked 2022-Mar-29 at 21:35

I have a data frame containing dates and associated values for three groups as follows.

...

ANSWER

Answered 2022-Mar-29 at 21:25

We can access the name of the current group(s) by using cur_group(). This gives us a tibble with every group being a column containing the current group name, so we need to subset it with $group.

Source https://stackoverflow.com/questions/71668841

QUESTION

R plotly: Display image on hover

Asked 2022-Mar-28 at 17:59

I am trying to reproduce this simple plotly graph that shows images on datapoint hover. The code is available here.

However, I am failing to reproduce it. This is what I have so far:

...

ANSWER

Answered 2022-Mar-28 at 17:59

The 2.0 release of plotly.js dropped d3 as a bundled dependency, so you'll need to bring that in separately now:

Source https://stackoverflow.com/questions/71601216

QUESTION

Combine character variable over rows and columns by group in R

Asked 2022-Mar-22 at 11:33

I am a beginner in R and I am trying to solve a problem in R, which is I guess quite easy for experienced users.

The problem is the following: Customers (A, B, C) are coming in repeatedly using different programms (Prg). I would like to identify "typical sequences" of programs. Therefore, I identify the first programm, they consume, the second, and the third. In a next step, I would like to combine these information to sequences of programms by customer. For a customer first consuming Prg1, then Prg2, then Prg3, the final outcome should be "Prg1-Prg2-Prg3".

The code below produces a dataframe similar to the one I have. Prg is the Programm in the respective year, First is the first year the customer enters, Sec the second and Third the third.

The code produces columns that extract the program consumed in the first contract (Code_1_Prg), second contract (Code_2_Prg) and third contract (Code_3_Prg).

Unfortunately, I am not successful combining these 3 columns to the required goal. I tried to group by ID and save the frist element of the sequence in a new column called "chain1". Here I get the error message "Error in df %>% group_by(ID) %>% df$chain1 = df[df$Code_1_Prg != "NA", : could not find function "%>%<-", even though I am using the magrittr and dplyr packages.

...

ANSWER

Answered 2022-Mar-22 at 11:08

Are you looking for something like this?

Source https://stackoverflow.com/questions/71570900

QUESTION

Make centered LaTeX tabular table using knitr kable

Asked 2022-Feb-16 at 22:19

The knitr::kable with the latex format option produces a tabular environment. For example,

...

ANSWER

Answered 2022-Feb-15 at 20:20

If you use \centering, you'll avoid the extra vertical spacing from the center environment:

Source https://stackoverflow.com/questions/71125606

QUESTION

Breaking up observations across multiple dates in R

Asked 2022-Feb-14 at 21:53

I am hoping to find a data.table + lubridate solution to the following problem.

Suppose that I have the following dataset:

...

ANSWER

Answered 2022-Feb-14 at 14:31

# expand the rows
sample = sample[sample[, .(date = seq(as.IDate(start),as.IDate(end),1)), by=var], on="var"]

# fix the times
sample[, `:=`(
  start = fifelse(as.IDate(start) == date,
                  ymd_hms(paste0(as.Date(start),as.ITime(start))),
                  ymd_hms(paste0(date,"00:00:00"))),
  end = fifelse(as.IDate(end) == date,
                ymd_hms(paste0(as.Date(end),as.ITime(end))),
                ymd_hms(paste0(date, "23:59:59"))),
  date = NULL
)]

Source https://stackoverflow.com/questions/71105287

QUESTION

Should I use %$% instead of %>%?

Asked 2022-Feb-08 at 23:14

Recently I have found the %$% pipe operator, but I am missing the point regarding its difference with %>% and if it could completely replace it.

Motivation to use %$%

The operator %$% could replace %>% in many cases:

...

ANSWER

Answered 2022-Feb-08 at 23:14

In addition to the provided comments:

%$% also called the Exposition pipe vs. %>%:

This is a short summary of this article https://towardsdatascience.com/3-lesser-known-pipe-operators-in-tidyverse-111d3411803a

"The key difference in using %$% or %>% lies in the type of arguments of used functions."

One advantage, and as far as I can understand it, for me the only one to use %$% over %>% is the fact that we can avoid repetitive input of the dataframe name in functions that have no data as an argument.

For example the lm() has a data argument. In this case we can use both %>% and %$% interchangeable.

But in functions like the cor() which has no data argument:

Source https://stackoverflow.com/questions/71008076

QUESTION

How to convert a list of characters that is stored in a single value (per record) into a format that can be analyzed? R

Asked 2022-Feb-08 at 00:24

So I have the following data. In this dataframe I have a username, date, and a list of packages. My goal is to transform that column packages into a format I can analyze.

...

ANSWER

Answered 2022-Feb-07 at 22:31

A solution, based on tidyr::separate:

Source https://stackoverflow.com/questions/71026212

QUESTION

How to automate legends for a new geom in ggplot2?

Asked 2022-Jan-30 at 18:08

I've built this new ggplot2 geom layer I'm calling geom_triangles (see https://github.com/ctesta01/ggtriangles/) that plots isosceles triangles given aesthetics including x, y, z where z is the height of the triangle and the base of the isosceles triangle has midpoint (x,y) on the graph.

What I want is for the geom_triangles() layer to automatically provide legend components for the height and width of the triangles, but I am not sure how to do that.

I understand based on this reference that I may need to adjust the draw_key argument in the ggproto StatTriangles object, but I'm not sure how I would do that and can't seem to find examples online of how to do it. I've been looking at the source code in ggplot2 for the draw_key functions, but I'm not sure how I would introduce multiple legend components (one for each of height and width) in a single draw_key argument in the StatTriangles ggproto.

...

ANSWER

Answered 2022-Jan-30 at 18:08

I think you might be slightly overcomplicating things. Ideally, you'd just want a single key drawing method for the whole layer. However, because you're using a Stat to do the majority of calculations, this becomes hairy to implement. In my answer, I'm avoiding this.

Let's say I'd want to use a geom-only implementation of such a layer. I can make the following (simplified) class/constructor pair. Below, I haven't bothered width_scale or height_scale parameters, just for simplicity.

Class

Source https://stackoverflow.com/questions/70916440

QUESTION

How to use an expression in dplyr::mutate in R

Asked 2022-Jan-23 at 16:43

I want to add a new column based on a given character vector. For example, in the example below, I want to add column d defined in expr:

...

ANSWER

Answered 2022-Jan-23 at 13:30

To get the desired name for the mutated column, you can still use the same syntax and assign the results to a column with the preferred name. To get this name you can use a regular expression to find what is before = and then remove any leading or trailing spaces that might exist.

Source https://stackoverflow.com/questions/70821721

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install magrittr

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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