ABIF | Ruby ABIF

by 545ch4 Ruby Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | ABIF Summary

ABIF is a Ruby library. ABIF has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Handle ABIF (Applied Biosystems Genetic Analysis Data File Format) FSA, AB1 and HID files.

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Quality

Security

License

Reuse

Support

ABIF has a low active ecosystem.

It has 4 star(s) with 0 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

ABIF has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of ABIF is current.

Quality

ABIF has 0 bugs and 0 code smells.

Security

ABIF has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

ABIF code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

ABIF is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

ABIF releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

It has 468 lines of code, 12 functions and 6 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed ABIF and discovered the below as its top functions. This is intended to give you an instant insight into ABIF implemented functionality, and help decide if they suit your requirements.

Unpack data .
Create a new BIFF file .
Parses a file .
Combines an array of bit - wise strings .
Unpack a directory .
Initialize a new cipher
Test if file is given
Print the current application .
adds to the counter
Initiates the zip .

Get all kandi verified functions for this library.

ABIF Key Features

No Key Features are available at this moment for ABIF.

ABIF Examples and Code Snippets

No Code Snippets are available at this moment for ABIF.

Community Discussions

Trending Discussions on ABIF

How do I read integers from big-endian binary file if Windows/Delphi/IDE implies little-endian order?

How to subtract a column from another specific column using an identifier

Convert daily returns to monthly returns in r

QUESTION

How do I read integers from big-endian binary file if Windows/Delphi/IDE implies little-endian order?

Asked 2020-Nov-26 at 07:35

I am very confused. I need to read binary files (.fsa extension by Applied Biotechnology aka ABIF, FASTA files) and I ran into a problem reading signed integers. I am doing everything according to this manual https://drive.google.com/file/d/1zL-r6eoTzFIeYDwH5L8nux2lIlsRx3CK/view?usp=sharing So, for example, let's look at the fDataSize field in the header of a file https://drive.google.com/file/d/1rrL01B_gzgBw28knvFit6hUIA5jcCDry/view?usp=sharing

I know that it is supposed to be 2688 (according to the manual, it is a signed integer of 32 bits), which is 00000000 00000000 00001010 10000000 in binary form. Indeed, when I read these 32 bits as an array of 4 bytes, I get [0, 0, 10, -128], which is exactly the same in binary form.

However, if I read it as Integer, it results in 16809994, which is 00000001 00000000 10000000 00001010 in bits.

As I understood from multiple forums, they use Swap and htonl functions to convert integers from little-endian order to big-endian. They also recommend using BSWAP EAX instruction for 32bit integers. But in this case they work in a kind of wrong way, specifically: Swap, applied to 16809994, returns 16779904 or 00000001 00000000 00001010 10000000, and BSWAP instruction converts 16809994 to 176160769, i.e. 00001010 10000000 00000000 00000001

As we can see, built-in functions do something different from what I need. Swap is likely to return the correct result, but, for some reason, reading these bits as an Integer changes the left-most byte. So, what is wrong and what do I do?

Upd. 1 For storing the header data I use the following record:

...

ANSWER

Answered 2020-Nov-26 at 07:35

Here is a implementation example using pure pascal:

Source https://stackoverflow.com/questions/65005050

QUESTION

How to subtract a column from another specific column using an identifier

Asked 2020-Apr-01 at 08:50

We have Net Asset Values (NAV) over several years for over 100 mutual funds where the mutual funds start and end at different dates.

The NAVs are monthly and we also made a column marking them with a number for each month (1-12) and the year. We also have monthly risk free return, where we did the same by making a column and marking them with a number for each month (1-12) and the year.

We now need to subtract the right monthly risk free asset to the dedicated NAV. The data for the risk free return and the NAV are in different data frames. We have pulled 50 lines from each data frames if this helps illustrate the problem/create a solution.

Here is a selection of the data frame for the NAV (dput(dfNAV[1:50,]):

...

ANSWER

Answered 2020-Mar-31 at 18:01

Sound like join dfNAV and dfRF using Month and Year as identifiers. Take all columns from dfNAV and Rf from dfRF.

base R:

Source https://stackoverflow.com/questions/60953609

QUESTION

Convert daily returns to monthly returns in r

Asked 2020-Mar-31 at 11:59

We have daily returns from well over 100 mutual funds that we wish to convert into monthly returns. The monthly return should not be the average from each month, but the funds' return at the end of each month. The funds start and end at different points in time, and they need to remain by themself (not adding all mutual fund returns into 1 each month).

As of the picture one may see the dataframe (df) and parts of its content. The dates are in the first column and it needs to be sorted. enter image description here We would love some help to solve this problem.

I believe that it contains sufficient information be able to write the code.

DATA,dput(df5[1:50,])

"Date" "Name" "Nav"

2012-01-02 Aktiva 10 121.738

2012-01-03 Aktiva 10 121.87

2012-01-04 Aktiva 10 121.906

2012-01-05 Aktiva 10 121.89

2012-01-06 Aktiva 10 121.949

2012-01-09 Aktiva 10 122.024

2012-01-10 Aktiva 10 122.205

2012-01-11 Aktiva 10 122.219

2012-01-12 Aktiva 10 122.324

2012-01-13 Aktiva 10 122.309

2012-01-16 Aktiva 10 122.45

2012-01-17 Aktiva 10 122.433

2012-01-18 Aktiva 10 122.483

2012-01-19 Aktiva 10 122.596

2012-01-20 Aktiva 10 122.548

2012-01-23 Aktiva 10 122.653

2012-01-24 Aktiva 10 122.507

2012-01-25 Aktiva 10 122.582

2012-01-26 Aktiva 10 122.783

2012-01-27 Aktiva 10 122.804

2012-01-30 Aktiva 10 122.749

2012-01-31 Aktiva 10 122.865

2012-02-01 Aktiva 10 123.044

2012-02-02 Aktiva 10 123.184

2012-02-03 Aktiva 10 123.32

2012-02-06 Aktiva 10 123.402

2012-02-07 Aktiva 10 123.322

2012-02-08 Aktiva 10 123.342

2012-02-09 Aktiva 10 123.421

2012-02-10 Aktiva 10 123.368

2012-02-13 Aktiva 10 123.418

2012-02-14 Aktiva 10 123.389

2012-02-15 Aktiva 10 123.558

2012-02-16 Aktiva 10 123.735

2012-02-17 Aktiva 10 123.636

2012-02-20 Aktiva 10 123.68

2012-02-21 Aktiva 10 123.701

2012-02-22 Aktiva 10 123.705

2012-02-23 Aktiva 10 123.663

2012-02-24 Aktiva 10 123.723

2012-02-27 Aktiva 10 123.77

2012-02-28 Aktiva 10 123.9

2012-02-29 Aktiva 10 123.91

2012-03-01 Aktiva 10 123.95

2012-03-02 Aktiva 10 124.02

2012-03-05 Aktiva 10 123.98

2012-03-06 Aktiva 10 123.74

2012-03-07 Aktiva 10 123.79

2012-03-08 Aktiva 10 123.92

2012-03-09 Aktiva 10 124.05

dput(df[1:50,]) data looks like this:

...

ANSWER

Answered 2020-Mar-31 at 11:59

With tidyverse and lubridate you can do the following.

You can group_by month and then filter to show only the last row of data for each month. arrange is used to sort by Date just in case.

Edit: Also group_by year(Date) in this example. Results updated with new data provided.

Source https://stackoverflow.com/questions/60931864

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install ABIF

Add this line to your application's Gemfile:.

Support

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