kandi X-RAY | Rind Summary
kandi X-RAY | Rind Summary
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Top functions reviewed by kandi - BETA
- Serialize the node
- Recursively fix all children of the children .
- Filter the given node at the given path .
- Overrides the local name of the local namespace
- Returns the given node at the given index .
- deletes the text from this node
- Get the root node .
- Render the children .
- Render all children .
- Search for a given node .
Rind Key Features
Rind Examples and Code Snippets
Community Discussions
Trending Discussions on Rind
QUESTION
I am working on a Recipe App, i am able to parse the json data but am stuck on how to implement a section of each Recipe:
recipe.json
Attached is the sample section of a Recipe:
...ANSWER
Answered 2021-Apr-20 at 17:29Please read the error message carefully
Expected to decode Dictionary but found an array instead
tells you that the value for key summary
is an array so you have to write
QUESTION
My goals is to JOIN
a table multiple times on the same id
.
Here is a snipet of my database structure:
...ANSWER
Answered 2021-Mar-10 at 13:41Joining the same table twice should work just fine.
You haven't posted the entire table structure but shouldn't you be joining the kategorien table on the Id-column? Like this:
QUESTION
If I have a String with food ingredients such as (german list of ingredients in a product)
...ANSWER
Answered 2021-Jan-16 at 13:54One approach can be modify the string such that words like spices (dill, basil)
be replaced with dill, basil
Regex Demo
\(((?:\w+,\s)+\w+)\)
would match with (
followed by one or more occurence of word followed by comma and space
and then a word and lastly followed by )
and here contents inside the brackets are captured and would replace the original pharse
QUESTION
Good morning!
I am obviously pretty new to the whole programming thing, so I am working on a basic PoS application for a restaurant. I am trying to figure out how I can assign different values to the different buttons while using the same button click function. I know I could write out a new function for each button with the correct object properties pushed, but there has to be a better way. I currently just have it set for the top right port nachos button to push the information into the tab section (though right now I am drawing a blank as to why it is the only one to do this instead of all the foodbuttons pushing the pork nachos info). Any help would be greatly appreciated. Thanks again!
...ANSWER
Answered 2021-Jan-09 at 13:14Basically, I use the innerText
of each html element as keys in the object
On a side note: only Pulled Pork Nachos
, 6 Wings
and Pork Rinds
have any relation in the food variable so it will work better when you use your full variable and not JUST these 3 indexes(for an item that is non-existent in the food
variable, an alert is shown)
NOW as to what I fully did:
FIRSTLY, I made 3 variables outside the function; blankElemState
which is the tab element's innerHTML
when holding NOTHING, amount
as TOTAL tab amount and purchases
for holding the object equivalent of each purchase(because of reference logic, one can search through the food, drink and merch arrays and when a value EQUALS a value in purchases
, that's the exact item of purchase). For example of the reference logic, purchases[8]
might EQUAL food[2]
SECONDLY, I made a variable i
that holds the place in the food
array of the requested item(for drinks you can change that part to drinks.forEach
instead of food.forEach
and so forth).
NEXT, if there is nothing in the array that refers to the requested item(by user), I warn that there is nothing available for the order(which naturally should not happen).
THEN, if tabAmountSection
already has elements appended to it(not equal to blankElemState
), I clear tabAmountSection
(by making its innerHTML back to blankElemState
) so that there aren't multiple "final" purchase values and remove
buttons
QUESTION
I got a dataframe that looks like this. I want to plot for EACH "localidad" the year-mean "rinde" value for the three different "agua_inicial" options. Let´s suppose I have 14 different "LOCALIDAD", then at the end I would like to get 14 different plots (X=year, Y= "rinde") and each plots needs to show me three different curves (for the three different agua_inicial options: high, low, mid).
Im trying to find the way to build this code but it is really difficult
...ANSWER
Answered 2020-Dec-14 at 23:30Many approaches come into consideration. Just to name a few:
Using ggplot2Faceting would do exactly what you are looking for. See: https://ggplot2-book.org/facet.html
More general, group by with dplyrIt would also be possible to transform the data by oneself and to call the plotting function once for every group. For example:
QUESTION
I'm trying to use Google Sheets as a scraper to get product descriptions prices and images from a specific store. https://www.aliexpress.com/store/group/xiaomi-Aqara-Smart-home/2389096_516541380.html
I'm trying to retrieve the image URLs from this page but in the end, I'm not able to make it work.
...ANSWER
Answered 2020-Aug-10 at 19:21That page is loaded dynamically using javascript, and the sample html in your question is a result of that. Absent some trickery (you can search around for scripts to handle dynamically loaded pages), GS can't retrieve that data.
Fortunately, not ALL data is loaded like that. If you disable JS on that page, you will get most of the same data, including the info; only this time - it looks like this:
QUESTION
I have the given lists:
...ANSWER
Answered 2020-Jun-29 at 14:42You could just check that `bottom <= top" to get unique combinations:
QUESTION
I have to solve a task for university. I have 4 given lists and I have to count the possible variations of burgers that can be made under some restrictions.
...ANSWER
Answered 2020-Jun-28 at 17:38First, in this case you probably shouldn't be using list comprehension. List comprehension is for smaller things, and this is far too messy. This is probably the best way to do it (using for loops). In the code below, count will be the total number and choices are all possible burgers.
QUESTION
I have a 3D numpy array boolean mask which has been segmented from a MRI brain volume.
Brain voxels = True. Everything else = False.
What I would like to do is to enlarge this mask such that it would encompass the surrounding tissues in the MRI volume, not just the segmented organ, perhaps a 10mm rind of non-brain all around the brain.
I tried using a 2D dilation using the skimage.morphology.dilation with a diamond filter. While this is nice and fast for a single image, I need to repeat this in multiple slices through the volume and in at least 2 planes to come even close to uniformly dilating the 3D mask.
I largely took my code from here: https://scipy-lectures.org/packages/scikit-image/index.html
typical volume shape = 512, 512, 270
...ANSWER
Answered 2020-Jun-17 at 04:49This question actually has a bit of subtlety, which I'll try to unpack.
The first thing to note is that most scikit-image functions actually work totally fine in 3D, including binary_dilation
! So you should in an ideal world be able to do:
QUESTION
I am trying to solve a linear programming problem. Following are specs of the problem:
I have a network flow problem that's been converted to a linear programming problem. So, all the flow constraints, such as capacity, flow conservation etc., will have to be enforced. My objective is to minimize cost.
Decision Variables - I have built two 8x8 matrices by defining a dictionary and adding decision variable at each of those 128 locations.
Constraints - there are in total 24 constraints, namely: 1) The flow starts at the source. 2 constraints for both 8x8 matrices. 2) The flow ends at the sink. 2 constraints for both 8x8 matrices. 3) There are 12 constraints for flow conservation, 8 each for both matrices. 4) There are 2 constraints to respect the capacity constraint, 1 for each matrix. 5) There are 6 constraints to avoid duplication
All the variables are required to be binary.
Objective - There are certain variables from those 8x8 matrices whose sum is required to be minimized.
Again, all the variables have to be binary.
I have been able to code the solution in Google ORTOOLS and solution converges and shows minimum value. But, when I look at the variables, there are variables that have non-binary values. Also, the solution is wrong (I have an existing solution running in excel which is correct and is different).
I'd appreciate if someone could point me in the right direction. Following is the code which is written in Python 36.
...ANSWER
Answered 2020-Mar-30 at 12:17See: https://groups.google.com/forum/#!msg/or-tools-discuss/p5qVzZWIeIg/g77egaD-AAAJ
Glop is a pure LP. It will only solve the relaxation of the mip problem. So it is normal that the error checker tells you that the solution is not integral.
You can change GLOP_LINEAR_PROGRAMMING to BOP_INTEGER_PROGRAMMING if you program is purely boolean. Or you can stay with CBC
That's why you should use either:
pywraplp.Solver.CBC_MIXED_INTEGER_PROGRAMMING
pywraplp.Solver.BOP_INTEGER_PROGRAMMING
pywraplp.Solver.SAT_INTEGER_PROGRAMMING
instead of pywraplp.Solver.GLOP_LINEAR_PROGRAMMING
.
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