MiniForm | Sugar around ActiveModel : :Model | Form library
kandi X-RAY | MiniForm Summary
kandi X-RAY | MiniForm Summary
Helpers for dealing with form objects and nested forms.
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Top functions reviewed by kandi - BETA
- Iterates through the validation errors .
- Updates the model .
- Sets the attributes of the attribute .
- Execute a block in this block .
- Updates the attributes of an object .
- Saves model attributes
- Determine whether the object is valid
MiniForm Key Features
MiniForm Examples and Code Snippets
Community Discussions
Trending Discussions on MiniForm
QUESTION
I have a calendar where when I click on day it shows a form to enter in order it can place on the calendar. However, that form is coming from a framework that I don't have access too. My concern is can I create my own form when I click on day on the calendar in jQuery/javascript? please advise/help. thank you so much!
An example: https://www.calendar.com/wp-content/uploads/2018/04/create-event-website-miniform.png
here is my jQuery code:
...ANSWER
Answered 2020-Apr-04 at 00:16Yes you can define a click event on clicking on days and then prevent the default behavior and do what you want. Find a querySelector that can be used to select days. I consider that all days have dayClass
class.
QUESTION
I have a form and i wanted specific elements of the form which I got and stored the values in an array.
...ANSWER
Answered 2017-Jul-23 at 19:05You could just send the entire form using formdata()
. Is there a reason you don't?
Anyway, it doesn't work because you are not creating a json object, but a normal array. There's a difference. You can actually just put the json directly into the ajax call and you don't have to stringify it.
QUESTION
I have data in an array which is supposed to be sent to a php file using ajax. I have tried to use console.log to display the array being sent and also to display a message if the data was successfully sent.However no message is being displayed on my console.Could someone please tell me what is wrong with my code.
...ANSWER
Answered 2017-Jul-24 at 20:22Most likely what is happening is that you are not retuning an actual success message and that is why it is not being logged. Instead of the success
function in your AJAX call, change it to always
and see if you get the results back. You will also need to add a parameter to your always
function which will be your response, like so:
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