left-pad | Ruby gem to left pad

PostgreSQL allows rows to be sorted by arrays. It compares the first value of each array, then the second value and so on (fiddle):

According to DataWeave documentation for the date(..) function, a Date can be created passing in the year, month, and day parts:

Input:

I have created several windows modal on my site which works perfectly on desktop. I would like to improve the user experience on mobile, by allowing the user to leave the modal window by clicking on the native "back" button of the mobile browser.

I've done some research on the web, and most of the time I find answers for React, or with libraries I don't use.

Do you have any idea how to make this possible in vanilla Javascript?

Thanks a lot for your help, here is the fiddle of my code

In 2016, the maintainer of the left-pad package unpublished it from NPM, leaving millions of builds broken before NPM stepped in and un-unpublished the package themselves before too much chaos could arise

https://www.theregister.com/2016/03/23/npm_left_pad_chaos/

What preventative measures have been put in place against such incidents occurring in the future? Has anything changed in how node_modules files are managed locally, bundled, etc? Did NPM change their policy on how open-source works? Is there any expected effort to move away from or modify the way open-source development works to handle issues like these?

Edit: I was looking to generate open-ended discussion but I guess StackOverflow is not the place for that, so modified my question accordingly.

I have a problem with my code, I'm trying to make my menu that contains list of items scrollable on button click (left and right buttons). The thing is after i click on right button, it works but it does not let me click it again....if i do it does nothing.So it goes once right and once left only. I want to be able to keep pressing it untill i reach the last item in the menu and vice versa.

My html code for the menu:

I am trying to convert a number to a string in awk. I would like my string to be left-padded with zeros. E.g., 3 would become "00000003". I have the following test case:

gawk 'BEGIN { CONVFMT = "%08d" ; a = 233 ; print ""a }'

233

It prints "233" not "00000233". Replacing a = 233 with a = 233.0 doesn't change anything. However, replacing a = 233 with a = 233.1 changes everything, and my one-liner correctly prints padded string:

gawk 'BEGIN { CONVFMT = "%08d" ; a = 233.1 ; print ""a }'

00000233

What am I missing ???

I have a dataframe with some NaN values in my s_x columns. If NaN values exist in them, I want them to be in the last columns.

Example: Given values in the s_x columns of [Nan, 1, Nan, 2] I want the values to shift left over the columns to result in [1, 2, NaN, NaN]

Example 2:

My current solution is very slow as I:

• iterate over the rows
• transform the s_x values into a list
• remove NaN values
• left-pad the list with NaN values
• write it back into the dataframe

How can I improve on the function below? The order of values (low to high) needs to remain the same. Every value is found only once in the s_x columns of a row.

I know that "leaving the pandas-logic" by parsing to a list and back is problematic concerning performance and was thinking of trying to do it with a lambda function, but didn't get anywhere with it.

My current code as a minimal working example:

I am trying to put a "+" sign on a button that reaches all the edges. This is a minimal example, from a Jupyter notebook, first a style:

In below code, CSS for li:after is not working in progressBarSlot. The line connecting the circles is not visible after putting it into the slot.

This is my template.