sponges | Ruby object into a daemon
kandi X-RAY | sponges Summary
kandi X-RAY | sponges Summary
When I build workers, I want them to be much like an army of Sponge Bobs: always stressed, and eager to work. sponges helps you with building this army of sponges, controlling them, and well, eventually killing them gracefully. Hum, making them stressed and eager to work would still be your job. :).
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Top functions reviewed by kandi - BETA
- Stop the runner .
- Executes a child process
- Kill workers
- Raises a worker
- Create a new runner .
- Handles the child pool
- Returns the list of response headers .
- Handles the connection .
- Get the process information
- Initialize the runner .
sponges Key Features
sponges Examples and Code Snippets
Community Discussions
Trending Discussions on sponges
QUESTION
I want to scrape a website which has a list of products and each product has a specific page with more data. I wanted to do it using MAP ASYNC + PROMISE.ALL instead of FOR-OF, however I couldn't make it Work properly.
Working sample with for-of:
...ANSWER
Answered 2021-Mar-22 at 18:31The problem is that your code is going in (pseudo) parallel. So they are stepping into each other. You can fixing it by creating a new page on each call:
QUESTION
I'm trying to make a Zapier zap to get a JSON from Olark.
This is the sample JSON Olark sends...
...ANSWER
Answered 2020-May-09 at 18:54There sure is! What you're seeing is percent encoding. Node.js can decode that, but to get valid json, you'll also need to replace the + characters with spaces.
Try this:
QUESTION
I just built my first AWS Apache Server and uploaded my website from my school project. The site works in Dreamweaver. However on my Apache server only some of the images appear. They all have the same path and are contained in the same folder /var/www/html/images. Some appear as intended, others are a broken link. Any ideas why it's not working? To get css to load I had to move my css folder. With the images some work fine while others do not. They are roughly the same size files. This is the code for one of the non working images:
...ANSWER
Answered 2020-Feb-26 at 00:25I found that the file extension on some of the pictures was capitalized. These pictures wouldn't load until I changed .JPG to .jpg.
QUESTION
I have this kind of text:
...ANSWER
Answered 2018-May-01 at 10:23When you create your dtm the dictionary is trying to map itself against single words and will return 0. No match found. You need to use a bigram tokenizer in your DocumentTermMatrix call. See example below.
QUESTION
I am trying to loop through a nested array but not able to display. I am new to Javascript any help would be appreciated. Thank you
...ANSWER
Answered 2017-Nov-19 at 17:19You need to access the list items using []. Also at the moment you will only ever display the last array, to display all arrays you can use += and instead of using innerHTML you can use textContent since you're simply displaying text with no HTML.
QUESTION
I want to for given number in this case top_result, second_result, third_result loop over xml file and if that number is in the xml file it will return class name="" number="" description="" for that given number.
I'm doing something like this
...ANSWER
Answered 2017-Aug-27 at 07:42In cycle for el in root: you iterate over 'class' tags, so you need to get and check their 'number' attribute values, like this: id_ = int(el.attrib['number']).
Resulting code example:
QUESTION
The following html code is for a navbar. I have some commented out code here that I want to be a submenu for the "Adhesives" menu item. I placed that submenu list between the "a" tag of "Adhesives". I'm not sure if that is correct placement for that list to be a submenu. What is the CSS to make that list a submenu of "Adhesives"? Also, I know that I'm not using class=.... in the tags. If I stay with the convention I'm using here (without class=....) what would the css be? If I were to use class=.... in the tags how would that change the css?
...ANSWER
Answered 2017-May-10 at 19:52You just want to nest the submenu in an li, not in the a. Then you need to change your selector for showing nested ul's to use the direct decendent selector li:hover > ul { display: block; } so that you don't show all submenus in an li when you hover over one. Then if you want it to expand out to the right, use left: calc(100% - 12px); top: 0; on the double nested menus, and calc() is to account for the horizontal margin you have on the links in an li.
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