encryptor | A simple wrapper for the standard ruby OpenSSL library | SSH Utils library

 by   attr-encrypted Ruby Version: Current License: MIT

kandi X-RAY | encryptor Summary

kandi X-RAY | encryptor Summary

encryptor is a Ruby library typically used in Utilities, SSH Utils applications. encryptor has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A simple wrapper for the standard Ruby OpenSSL library.
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            kandi-support Support

              encryptor has a low active ecosystem.
              It has 337 star(s) with 49 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 7 open issues and 12 have been closed. On average issues are closed in 233 days. There are 3 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of encryptor is current.

            kandi-Quality Quality

              encryptor has 0 bugs and 0 code smells.

            kandi-Security Security

              encryptor has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              encryptor code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              encryptor is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              encryptor releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.
              encryptor saves you 187 person hours of effort in developing the same functionality from scratch.
              It has 461 lines of code, 29 functions and 10 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed encryptor and discovered the below as its top functions. This is intended to give you an instant insight into encryptor implemented functionality, and help decide if they suit your requirements.
            • Encrypts a new options with the provided options .
            • Replace the given options with the given options .
            • Encrypts the value using the provided options .
            • Decrypts the data using the specified options .
            Get all kandi verified functions for this library.

            encryptor Key Features

            No Key Features are available at this moment for encryptor.

            encryptor Examples and Code Snippets

            No Code Snippets are available at this moment for encryptor.

            Community Discussions

            QUESTION

            Django Python: How do I decrypt an AES-CTR mode encrypted file in the Python shell?
            Asked 2022-Mar-22 at 20:33

            I'm using https://github.com/eblocha/django-encrypted-files to encrypt files uploaded to a server through a simple contact form app in Django. django-encrypted-files uses AES in CTR mode to encrypt an uploaded file via an upload handler while streaming the file to the server.

            What I'm trying to do is manually decrypt the encrypted file by downloading the file via FTP and decrypting it locally in the Python shell. I do not want or need to stream decrypt the file from the server or modify django-encrypted-files; I only want to manually download and then decrypt files locally in the Python shell.

            The problem is I can't get local Python decryption to work. The docs at Cryptography show an example of encryption and decryption using a sample text input in the Python shell. But there are no examples of encrypting/decrypting a file.

            The code below what I'm trying to use in the Python shell. The original file uploaded via Django is uploaded_file.txt. The encrypted file downloaded from the server is encrypted.txt; the file to save the decrypted text to is decrypted.txt.

            But when I try the code below, the decrypted.txt is empty. Is this an issue with writing the file? Or an issue with the iv?

            What is a working example of decrypting a AES-CTR mode file in the local Python shell?

            uploaded_file.txt: https://paste.c-net.org/MiltonElliot

            encrypted.txt: https://paste.c-net.org/ChasesPrints

            Python shell:

            ...

            ANSWER

            Answered 2022-Mar-22 at 20:33

            During encryption, IV and ciphertext are concatenated: IV || ciphertext. During decryption, a random IV is used, which is wrong. Instead, the IV of the encryption must be applied. For this, IV and ciphertext have to be separated.
            In addition, the update() and finalize() methods must be called, which perform the actual decryption.

            The following code essentially matches your code, extended by the missing parts:

            Source https://stackoverflow.com/questions/71430014

            QUESTION

            Why Smart Card answers 6982 to EXTERNAL AUTHENTICATE while all calculations are correct?
            Asked 2022-Mar-12 at 05:05

            I am trying to establish a secure channel SCP02 with a smart card using python. My smartcard is connected to the terminal using a serial port and I use pySerial to send APDUs.

            I send commands SELECT ISD, INITIALIZE UPDATE correctly, and next I try to do EXTERNAL AUTHENTICATE as the python code below:

            ...

            ANSWER

            Answered 2022-Jan-10 at 10:45

            You can use the working Test Vectors from the GlobalPlatform library and test if your executed crypto logic is really working. It could also be that your card is using some key derivation scheme, i.e. the keys you are using cannot be used directly.

            Source https://stackoverflow.com/questions/70649512

            QUESTION

            How do I calculate a key check value for AES-128-CBC?
            Asked 2022-Jan-13 at 16:47

            I'm trying to implement a function in Java to calculate the key check value for a 128 bit AES encryption key. The AES128CBCEncryptor class is implementing AES/128/CBC with ISO 9797-1 M2 padding.

            The only information I can find on the key check value algorithm for AES says "the KCV for an AES key is computed by encrypting 16 bytes, each with value '01'.". It does not specify how the IV should be constructed.

            Here is what I have thus far, but it's not generating the expected result:

            ...

            ANSWER

            Answered 2022-Jan-13 at 16:47

            For a Key Check Value (KCV) one generally uses single block encryption, without any mode such as ECB or CBC. As only a constant value of 16 bytes is used, there is no need for padding either.

            If you just have a CBC class that performs ISO 9797-1 M2 padding then you could encrypt the static value of 01010101010101010101010101010101 (hex encoding of 16 bytes), using an all-zero IV and taking the first 16 bytes from the result (removing 16 bytes of ciphertext at the end that is just encryption of the mandatory padding).

            As you can see in the image below, because the IV is all zero, the XOR with the plaintext leaves the input intact, basically making the first ciphertext identical to direct encryption with the block cipher.

            By WhiteTimberwolf (SVG version) - PNG version, Public Domain, https://commons.wikimedia.org/w/index.php?curid=26434096

            However, as you are using Java, it makes more sense to use a Cipher object using algorithm "AES/ECB/NoPadding" and use that to encrypt the value of 01010101010101010101010101010101 directly. ECB doesn't take an IV, so that problem is avoided. Also, no padding needs to be considered when "NoPadding" is specified.

            If you need fewer bytes: those are usually taken from the left (lowest index) of the result.

            Beware that these kinds of KCV's are somewhat dangerous as they show the ciphertext of one particular plaintext block. In the worst instances, this could lead to an adversary decrypting one ciphertext block, or for an authenticated scheme to lose its integrity/authentication properties.

            Commonly KCV's are over an all-zero plaintext block. Using an all one-valued block makes the chance that this happens smaller, but that chance is still significant.

            Source https://stackoverflow.com/questions/70683993

            QUESTION

            Migrate to arm64 on AWS Lambda show error: Unable to import module 'encryptor-lambda'
            Asked 2022-Jan-13 at 16:37

            I have a lambda function runs on Python 3.7 with architecture x86_64 before. Now I would like to migrate it to arm64 to use the Graviton processor and upgrade to Python 3.9 as well.

            While I success to create the Python 3.9 virtual environment layer with the dependencies that I need, which is aws-encryption-sdk, when I change the architecture of my lambda function to arm64 and runtime to Python 3.9, below error shows after I test my code:

            ...

            ANSWER

            Answered 2022-Jan-10 at 15:27

            Libraries like aws-encryption-sdk-python sometimes contain code/dependencies that are not pure Python and need to be compiled. When code needs to be "compiled" it is usually compiled for a target architecture (like ARM or x86) to run properly.

            You can not run code compiled for one architecture on different architecture. So I suspect that is the reason for your error.

            Looking at the error message I suspect it is the cryptography library causing this issue.

            The library uses Rust. If you check your error, you will see that the shared library for the Rust binding is the causing your error (_rust.abi3.so). According to the documentation of the library, the ARM architecture is supported.

            Therefore, I suspect that the way you are packaging your Lambda deployment package and it's dependencies is the issue. You are probably doing that on a computer with x86 architecture. Package manager like pip usually detect the OS and architecture they are run on and download dependencies for those OS's and architectures.

            So I guess you have two options:

            1. Run your build/deployment on an ARM machine
            2. Somehow manage to "cross compile" with tools like crossenv

            Both options are not really great.

            Unfortunately, this is one of those areas where Python Lambdas can become very cumbersome to develop/deploy. Every time a depdency uses a non-Python extension (like a C extension), packaging/deployment becomes a problem.

            Maybe someone else has a great tool to recommend.

            Source https://stackoverflow.com/questions/70649979

            QUESTION

            Problem Updating to .Net 6 - Encrypting String
            Asked 2021-Dec-20 at 23:09

            I'm using a string Encryption/Decryption class similar to the one provided here as a solution.

            This worked well for me in .Net 5.
            Now I wanted to update my project to .Net 6.

            When using .Net 6, the decrypted string does get cut off a certain point depending on the length of the input string.

            ▶️ To make it easy to debug/reproduce my issue, I created a public repro Repository here.

            • The encryption code is on purpose in a Standard 2.0 Project.
            • Referencing this project are both a .Net 6 as well as a .Net 5 Console project.

            Both are calling the encryption methods with the exact same input of "12345678901234567890" with the path phrase of "nzv86ri4H2qYHqc&m6rL".

            .Net 5 output: "12345678901234567890"
            .Net 6 output: "1234567890123456"

            The difference in length is 4.

            I also looked at the breaking changes for .Net 6, but could not find something which guided me to a solution.

            I'm glad for any suggestions regarding my issue, thanks!

            Encryption Class

            ...

            ANSWER

            Answered 2021-Nov-10 at 10:25

            The reason is this breaking change:

            DeflateStream, GZipStream, and CryptoStream diverged from typical Stream.Read and Stream.ReadAsync behavior in two ways:

            They didn't complete the read operation until either the buffer passed to the read operation was completely filled or the end of the stream was reached.

            And the new behaviour is:

            Starting in .NET 6, when Stream.Read or Stream.ReadAsync is called on one of the affected stream types with a buffer of length N, the operation completes when:

            At least one byte has been read from the stream, or The underlying stream they wrap returns 0 from a call to its read, indicating no more data is available.

            In your case you are affected because of this code in Decrypt method:

            Source https://stackoverflow.com/questions/69911084

            QUESTION

            Why RijndaelManaged raises the following exception: Padding is invalid and cannot be removed?
            Asked 2021-Nov-25 at 21:22

            In a .NET4/C# application, I have the following encryption methods:

            ...

            ANSWER

            Answered 2021-Nov-25 at 21:22

            You are decrypting the data incorrectly. Try this:

            Source https://stackoverflow.com/questions/70104121

            QUESTION

            custom type always change the record, leaving it dirty
            Asked 2021-Nov-22 at 15:48

            I have the following custom type:

            ...

            ANSWER

            Answered 2021-Nov-22 at 15:48

            for future reference: I forgot to implement changed_in_place?

            Source https://stackoverflow.com/questions/70056123

            QUESTION

            AES Encryption in Java porting to Python
            Asked 2021-Nov-20 at 14:13

            DISCLAIMER: This is INSECURE encryption that I've inherited and everyone involved knows that. What I'm trying to do here is a first step in getting off this legacy system that has even bigger problems that this.

            I have an existing system in Java that I am attempting to port to Python that performs an AES encryption as such:

            ...

            ANSWER

            Answered 2021-Nov-20 at 00:45

            You need everything to be the exact same between both versions. This is not currently true; fix that.

            Your java code uses:

            • AES at block size 128, because that's just how AES rolls. Nothing to configure.
            • AES key size of 128, 192, or 256 bits.
            • The key.
            • The Mode of Operation. Your java code uses ECB (which is insecure). You've told your python code to use GCM. That's, obviously, not going to work. You need to specify ECB there, too.
            • Given that it's ECB, there is no IV.
            • The padding mode. Java code is doing PKCS5Padding here.
            • Crypto is fundamentally byte based but you're trying to encrypt strings, which aren't. That means the string is being converted to bytes, and that means a charset encoding is used. You didn't specify in your java code which means you get 'platform default'. Horrible idea, but if you can't change the java side, figure out what that is, and use the same encoding in your python code.
            • Finally, your java code base64's the result.

            For most of these, I simply can't tell you; the code you pasted is insufficient. For example, AES key size and whether the keys are actually identical? I have no idea - you tell me. How did you make that SecretKey key object?

            I'm not as familiar with python but it sure looks like you base64-encode it, and then decode it again. That's.. no, don't do that. Your java code encodes and that's that. Your python code should base64 encode and that's that.

            I'm pretty sure python also defaults to PKCS5Padding.

            That leaves the encoding mode which you 100% mismatched between java and python give what little code you pasted, and the way you construct the keys. If the text you're encrypting isn't straight ASCII, it's somewhat likely charset encoding is also causing a difference.

            It's crypto. One tiny difference and the outputs will be quite different.

            Source https://stackoverflow.com/questions/70041796

            QUESTION

            How to decrypt a AES encrypted data of C# in Python?
            Asked 2021-Nov-09 at 19:38

            I am trying to encrypt a text in C# and then trying to decrypt the data in Python but I am unable to decrypt the C# encrypted data in python. I think maybe I am unable to get the same IV as I am using in C#. I don't know where I am getting wrong.

            ...

            ANSWER

            Answered 2021-Nov-09 at 19:38

            In the C# code, the key is the ASCII encoding of key, but in the Python code it is the SHA-256 hash of key.

            So that the Python code produces the same ciphertext, simply replace:

            Source https://stackoverflow.com/questions/69903701

            QUESTION

            Converting Java AES CBC Encryption to C#
            Asked 2021-Oct-11 at 11:23

            I am trying to convert the following Java encryption snippet to C#

            ...

            ANSWER

            Answered 2021-Oct-11 at 11:23

            The reason is you are using StreamWriter, which is intended to write text into the stream, but then you write raw bytes there:

            Source https://stackoverflow.com/questions/69524957

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install encryptor

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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