ridley | A reliable Chef API client with a clean syntax

by berkshelf Ruby Version: Current License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | ridley Summary

ridley is a Ruby library. ridley has no bugs, it has no vulnerabilities and it has low support. However ridley has a Non-SPDX License. You can download it from GitHub.

A reliable Chef API client with a clean syntax.

Support

Quality

Security

License

Reuse

Support

ridley has a low active ecosystem.

It has 237 star(s) with 89 fork(s). There are 19 watchers for this library.

It had no major release in the last 6 months.

There are 21 open issues and 101 have been closed. On average issues are closed in 432 days. There are 4 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of ridley is current.

Quality

ridley has 0 bugs and 0 code smells.

Security

ridley has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

ridley code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

ridley has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

ridley releases are not available. You will need to build from source code and install.

ridley saves you 3301 person hours of effort in developing the same functionality from scratch.

It has 7088 lines of code, 356 functions and 114 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed ridley and discovered the below as its top functions. This is intended to give you an instant insight into ridley implemented functionality, and help decide if they suit your requirements.

Upload a cookbook to the Chef server .
Stream a destination to a destination host .
Validates values for validation
Download a specified file
Validates a regular expression .
Clean up the chef cookbook from the chef cookbook .
Clears all the files .
Returns the value of the given symbol and value
Loads all files from the manifest .
Get a chef configuration object

Get all kandi verified functions for this library.

ridley Key Features

No Key Features are available at this moment for ridley.

ridley Examples and Code Snippets

No Code Snippets are available at this moment for ridley.

Community Discussions

Trending Discussions on ridley

Calculate percentage in case when statement

Seed data with relations to an object with unknown ID

How to drop certain values within a multi-level index python pandas

Editing a Row Value in R

How do I print the dict to the correct format?

mongoDB join between 2 collections

Update using push operator in MongoDB, getting syntax error

Extracting specific data from nested list

Chef Berks Install (Berkshelf) Timesout contacting Artifactory repository (Faraday Timeout / Actor Crashed)

How to fix function to where it allows the next function to correctly compute?

QUESTION

Calculate percentage in case when statement

Asked 2021-Jun-06 at 18:31

I am trying to write a query where I need to calculate a percentage based on a condition in the case when statement. I have added the percentage logic but still it is not working.

My Tables

doctors

...

ANSWER

Answered 2021-Jun-06 at 18:24

One problem is the 50 / 100. This returns 0. Add a decimal point so the result is not an integer:

Source https://stackoverflow.com/questions/67862307

QUESTION

Seed data with relations to an object with unknown ID

Asked 2021-May-30 at 16:36

I have a problem with seeding data into an EF Core DB. The data consists of movies that have a Person object as a relation for their director. The relation works on the basis that a movie should have one director and each director entity in the DB has one directed movie (not ideal but besides the point). The problem arises when I try to seed the initial data in the DB. Since I'm seeding both the movies and the directors, I can't know the IDs of the entities beforehand and I need to be able to search the context for a director with a given name before creating a movie that has a relation to it.

For example:

This is the seeding of the people (directors)

...

ANSWER

Answered 2021-May-30 at 16:36

I generally don't recommend creating new GUID every time. This code will generate a different ID when deployed to different environments i.e staging and production, so you will only be left to query objects by name which creating ID column seems useless.Also you need to define primary key for each entity. So it will be better if you hardcode your GUID's like

Source https://stackoverflow.com/questions/67763154

QUESTION

How to drop certain values within a multi-level index python pandas

Asked 2020-Aug-16 at 03:54

I have something similar to the following dataframe, df:

...

ANSWER

Answered 2020-Aug-15 at 23:49

I think this should work:

Source https://stackoverflow.com/questions/63431597

QUESTION

Editing a Row Value in R

Asked 2020-Jun-20 at 08:41

I have a data frame that looks like this

...

ANSWER

Answered 2020-Jun-20 at 06:44

You're dealing with a factor column. "Calvin Ridley" isn't yet a level of the factor. After adding it you can rename the cell.

Source https://stackoverflow.com/questions/62482201

QUESTION

How do I print the dict to the correct format?

Asked 2020-May-29 at 15:15

I previously used course_rolls(records) to make the data to a dictionary below:

...

ANSWER

Answered 2020-May-29 at 15:15

The code you provided is very complicated to follow. You should try to use less for loops - it makes the code harder to read, and takes longer to execute (if you were performing something of larger scale). Take a look at my solution below, it prints the result as you would expect and is much easier to read and understand.

Here is the refactored code (note, since you didn't provide the course_roll function, I changed course_roll(records) for the variable course_rolls_records, so I could run it locally.):

Source https://stackoverflow.com/questions/62087918

QUESTION

mongoDB join between 2 collections

Asked 2020-Apr-28 at 20:33

I'm trying to join two to collection. First is a list of film :

...

ANSWER

Answered 2020-Apr-28 at 20:07

I'm not sure what 'jointure' is supposed to be.

If you have actors and movies collections with the documents you show in that example, a simple $lookup should suffice:

Source https://stackoverflow.com/questions/61465692

QUESTION

Update using push operator in MongoDB, getting syntax error

Asked 2020-Feb-03 at 03:12

I am new to MongoDB and currently I am learning it. But at a point I got syntax error and I unable to find out that error. So, I need your help.

Code:

...

ANSWER

Answered 2020-Feb-03 at 03:10

You cannot use colon after variable name in JavaScript, there should be:

Source https://stackoverflow.com/questions/60032648

QUESTION

Extracting specific data from nested list

Asked 2020-Jan-02 at 08:31

I am trying web scraping of movies of 2019 from IMDB. I am extracting the Director's name from a nested list. Now, the issue is the name of the Directors are not given for all the movies but for selected few, hence I need to extract the Director's name where ever the term 'Director:\n' appears.

The nested list is as follows:

...

ANSWER

Answered 2020-Jan-02 at 07:27

Here is a base R solution, where you can use use the method grep+gsub, or the method regmatches + gregexpr.

Assuming you data is a list lst, then you can try the following code to extract the director's name:

Source https://stackoverflow.com/questions/59559449

QUESTION

Chef Berks Install (Berkshelf) Timesout contacting Artifactory repository (Faraday Timeout / Actor Crashed)

Asked 2019-Aug-29 at 16:44

Artifactory 5.8.4 Professional

Chef Development Kit Version: 1.1.16

chef-client version: 12.17.44

delivery version: master (83358fb62c0f711c70ad5a81030a6cae4017f103)

berks version: 5.2.0

kitchen version: 1.14.2

In Artifactory, I have this repository (virtual): avirtual-repo

Berksfile contains:

...

ANSWER

Answered 2019-Aug-29 at 16:44

One simple simple solution is to restart Artifactory service on the machine.

Try this solution: To change the source file for the gem and bump the values. Save it, retry berks install to see. Restart Chef if required.

For ex:: Change values in the following file, line containing options and values i.e. retry to 3, retry_interval to 1 or 2, open_timeout to 60 and timeout to 60.

Source https://stackoverflow.com/questions/55029165

QUESTION

How to fix function to where it allows the next function to correctly compute?

Asked 2019-Aug-15 at 12:13

hope everyone is doing well. I am new to JavaScript and trying to do a little exercise but having trouble. When I load the page, and click the Blue button, the orange text and red text disappear like I want to, but if I click the Red button after. All of it disappears. I am trying to create something where if I click on one of the colors, the colors that isn't clicked on disappear and only the colored text remains. I want to be able to do it endlessly.

I've tried various websites but haven't been able to get the help I want.

JavaScript

...

ANSWER

Answered 2019-Aug-14 at 22:11

As explained in srk's answer above, you need to reset the display property each time.

In addition, i would suggest that you create a general function like bellow:

Source https://stackoverflow.com/questions/57502470

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install ridley

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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