sentence_splitter | Sinatra service that uses OpenNLP JRuby | Command Line Interface library

by caleb Ruby Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | sentence_splitter Summary

sentence_splitter is a Ruby library typically used in Utilities, Command Line Interface applications. sentence_splitter has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

This is a simple Sinatra web service that uses JRuby and (OpenNLP)[to split input into sentences.

Support

Quality

Security

License

Reuse

Support

sentence_splitter has a low active ecosystem.

It has 4 star(s) with 1 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

sentence_splitter has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of sentence_splitter is current.

Quality

sentence_splitter has no bugs reported.

Security

sentence_splitter has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

sentence_splitter does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

sentence_splitter releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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sentence_splitter Key Features

No Key Features are available at this moment for sentence_splitter.

sentence_splitter Examples and Code Snippets

No Code Snippets are available at this moment for sentence_splitter.

Community Discussions

Trending Discussions on sentence_splitter

Combining a list into a string

QUESTION

Combining a list into a string

Asked 2019-May-01 at 12:25

I am working on some code that should alter a string to create a new line when certain requirements are met. However, since I alter the string to be a list it prints as a list in the end, and I do not know how to turn the list into a string or analyse the string by leaving it as a string. Furthermore I would also greatly appreciate if someone could explain why the addition of "\n" does not actually create a line break.

I have tried str(variable) to turn the list into a string, however this doesn't seem to work. Furthermore, I have tried changing appending methods to see if that would actually insert a line break; variable.append, +=, but these all don't seem to work. I am new to Python and programming and am struggling.

...

ANSWER

Answered 2019-May-01 at 12:13

sent = ""
for i in sentence.split(" "):
    sent = sent + " " + i
    if i[-1] in ['.', '!']:
        sent = sent + "\n"

print(sent)

Source https://stackoverflow.com/questions/55935938

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install sentence_splitter

sentence_detector requires the the json_jruby, and sinatra gems. Everythign else is included. Just run it like you would any other Sinatra app (with Passenger, or rackup).

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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