kandi X-RAY | carmen Summary
kandi X-RAY | carmen Summary
A repository of geographic regions for Ruby.
Top functions reviewed by kandi - BETA
- Search for matching regions .
- Retrieves code for given country code .
- Loads the data from the specified path
- Loads a subset of regions .
- Flatten an array of nested arrays
- Loads the regions of the specified path .
- Returns the path to the subdirectory .
- Return a list of all regions for a given type .
- Resetches the region .
- Returns the name of the given name .
carmen Key Features
carmen Examples and Code Snippets
Trending Discussions on carmen
I have two large CSV with data that I want to compare. I used pandas therefore I have two data frames to work with easier, but the program takes too long to finish and compare all the data.
I am comparing the data sent with the received, in order to get the latency time, for that I put a double loop and the program works fine. But I want to know if there is a faster way to do this, because for my heaviest files it takes days to finish the program.
I am working with large files, the first has 68001 rows and the second has 837190 rows. But the program takes too long. Thanks in advance.
Explanation of how my code works
I am doing some performance tests of the MQTT broker, for which I created the paho clients that send and receive messages, the data sent was stored in a csv to later calculate the latency. The csv of the Publishers (users who publish) contains the publisher's client ID, the account, the timestamp, and the topic to which it is subscribed.
While the subscribers (users who receive the message) contain the timestamp when the message is received, the message received, the count (counter for the number of messages), the publisher's client ID and the topic.
Now to calculate the latency, evaluate row by row with a loop that starts at 0. That's why I used a loop for df1 (dataframe of the publishers) and the first row of the df2 (dataframe of the message receivers).
With the conditional "if" I compare the client's ID, the count number, and the topics where the messages were sent from the first row of the dataframe df1, which corresponds to the first client to send a message and I compare it with the first row of the dataframe df2, to see if the client ID, count and topic match.
If it coincides, I proceed to subtract the times to calculate the Latency, locating myself in the column corresponding to the times, and then store them in another csv, which is almost the last line you can see.
If the conditional is not fulfilled, continue and goes to the next iteration of the loop corresponding to the df2. Therefore df1 will remain in the same position until the df2 loop has finished evaluating if there are matches in all the lines of its dataframe. I hope I have explained myself well....
ANSWERAnswered 2021-May-09 at 17:24
You can use a merge: It should be faster than running loops
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
ANSWERAnswered 2021-Apr-27 at 16:44
You can do it with the
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this
c.state == val might not work.
You can use the
trim function to compare your value safely:
c.state.trim() == val.trim()
Here's a piece of the dataset I'm working on :
ANSWERAnswered 2021-Apr-02 at 10:17
Your entire approach is very inefficient. Just use a
collections.Counter object. Supposing you have a dataframe like:
I have a table like this,...
ANSWERAnswered 2021-Mar-19 at 18:13
- the first column of each dataframe is different. Appears as if it is a timestamp
- copy it to a column using
rename()it so all the data frames are consistent
ANSWERAnswered 2021-Jan-27 at 18:56
Use axes as false and set them to pos zero
I'm basically trying to get Lat and Long from entered address, but the MapboxGeocoding method returns invalid co ordinates which does not range between -90 to 90....
ANSWERAnswered 2020-Dec-04 at 05:54
I have the following JSON object
ANSWERAnswered 2020-Nov-25 at 05:39
When using Jayway's JSONPath like this I get the desired oputput:
I'm also attaching a CodePen link for the app....
ANSWERAnswered 2020-Oct-12 at 06:17
You very very close to getting it right, you just had some issues that should be catched by an IDE.
- You were not using
returninside the function
clean. If you don't do that, the value will never be passed to the outer environment.
querySelectorAllis used when you want to grab many items. You just wanted one.
- You were adding changing the
innerHTMLin a wrong place, as a second parameter of the
But don't fret over these issues, you did a good job!
how do i go about doing this? Assuming I have a .txt file with that looks like something in the first codeblock below, keeping in mind 1 name might be in the .txt file more than one time so for example Jack's hobbies are crafting as well as skateboarding....
ANSWERAnswered 2020-Sep-28 at 21:25
You may a
defaultdict with a
list as factory, if the key is not present it initialize the mapping with a
list so you can directly
No vulnerabilities reported
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
Reuse Trending Solutions
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page