carmen | A repository of geographic regions for Ruby
kandi X-RAY | carmen Summary
kandi X-RAY | carmen Summary
A repository of geographic regions for Ruby.
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Top functions reviewed by kandi - BETA
- Search for matching regions .
- Retrieves code for given country code .
- Loads the data from the specified path
- Loads a subset of regions .
- Flatten an array of nested arrays
- Loads the regions of the specified path .
- Returns the path to the subdirectory .
- Return a list of all regions for a given type .
- Resetches the region .
- Returns the name of the given name .
carmen Key Features
carmen Examples and Code Snippets
Community Discussions
Trending Discussions on carmen
QUESTION
I have two large CSV with data that I want to compare. I used pandas therefore I have two data frames to work with easier, but the program takes too long to finish and compare all the data.
I am comparing the data sent with the received, in order to get the latency time, for that I put a double loop and the program works fine. But I want to know if there is a faster way to do this, because for my heaviest files it takes days to finish the program.
I am working with large files, the first has 68001 rows and the second has 837190 rows. But the program takes too long. Thanks in advance.
Explanation of how my code works
I am doing some performance tests of the MQTT broker, for which I created the paho clients that send and receive messages, the data sent was stored in a csv to later calculate the latency. The csv of the Publishers (users who publish) contains the publisher's client ID, the account, the timestamp, and the topic to which it is subscribed.
While the subscribers (users who receive the message) contain the timestamp when the message is received, the message received, the count (counter for the number of messages), the publisher's client ID and the topic.
Now to calculate the latency, evaluate row by row with a loop that starts at 0. That's why I used a loop for df1 (dataframe of the publishers) and the first row of the df2 (dataframe of the message receivers).
With the conditional "if" I compare the client's ID, the count number, and the topics where the messages were sent from the first row of the dataframe df1, which corresponds to the first client to send a message and I compare it with the first row of the dataframe df2, to see if the client ID, count and topic match.
If it coincides, I proceed to subtract the times to calculate the Latency, locating myself in the column corresponding to the times, and then store them in another csv, which is almost the last line you can see.
If the conditional is not fulfilled, continue and goes to the next iteration of the loop corresponding to the df2. Therefore df1 will remain in the same position until the df2 loop has finished evaluating if there are matches in all the lines of its dataframe. I hope I have explained myself well.
...ANSWER
Answered 2021-May-09 at 17:24You can use a merge: It should be faster than running loops
QUESTION
following are my files for html, .ts and json . As json data was very extensive therefore i have just added a few states and their cities. my 1st dropdown is showing all states. Now I want to match my 1st dropdown's selected value of state with a key "state" in "cities" object in my json file so i can populate 2nd dropdown with cities relevant to that state. and I want to do this in function "getCitiesForSelectedState". please help me find solution for this.
//.ts file
...ANSWER
Answered 2021-Apr-27 at 16:44You can do it with the $event
parameter.
Make sure to compare your values safely.
If your value is not in the right type or has spaces or unwanted chars, this c.state == val
might not work.
You can use the trim
function to compare your value safely:
c.state.trim() == val.trim()
HTML
QUESTION
Here's a piece of the dataset I'm working on :
ANSWER
Answered 2021-Apr-02 at 10:17Your entire approach is very inefficient. Just use a collections.Counter
object. Supposing you have a dataframe like:
QUESTION
I have a table like this,
...ANSWER
Answered 2021-Mar-19 at 18:13- the first column of each dataframe is different. Appears as if it is a timestamp
- copy it to a column using
assign()
rename()
it so all the data frames are consistent
QUESTION
ANSWER
Answered 2021-Jan-27 at 18:56Use axes as false and set them to pos zero
QUESTION
I'm basically trying to get Lat and Long from entered address, but the MapboxGeocoding method returns invalid co ordinates which does not range between -90 to 90.
...ANSWER
Answered 2020-Dec-04 at 05:54I believe
QUESTION
I have the following JSON object r2
,
ANSWER
Answered 2020-Nov-25 at 05:39When using Jayway's JSONPath like this I get the desired oputput:
QUESTION
I'm made a Palindrome app that takes a word input and flips to say if it's a palindrome or not. However, after inputting a word it's not flipping the card to reveal if it's a palindrome or not. I was using following the Multi-faced Flip Card with a Click by Maria del Carmen Santiago, particularly the CSS and JavaScript sections as a guide. Could someone please help me figure out what it is I'm doing wrong?
I'm also attaching a CodePen link for the app.
...ANSWER
Answered 2020-Oct-12 at 06:17You very very close to getting it right, you just had some issues that should be catched by an IDE.
- Typo:
toLowerCase
instead oftoLowercase
. - You were not using
return
inside the functionclean
. If you don't do that, the value will never be passed to the outer environment. - Typo:
cleanInput
instead ofCleanInput
. querySelectorAll
is used when you want to grab many items. You just wanted one.- You were adding changing the
innerHTML
in a wrong place, as a second parameter of theclassList.add
method.
But don't fret over these issues, you did a good job!
QUESTION
how do i go about doing this? Assuming I have a .txt file with that looks like something in the first codeblock below, keeping in mind 1 name might be in the .txt file more than one time so for example Jack's hobbies are crafting as well as skateboarding.
...ANSWER
Answered 2020-Sep-28 at 21:25You may a defaultdict
with a list
as factory, if the key is not present it initialize the mapping with a list
so you can directly append
QUESTION
ANSWER
Answered 2020-Sep-21 at 08:28Try this:
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