wagons | Wagons are extensions to your application train
kandi X-RAY | wagons Summary
kandi X-RAY | wagons Summary
Wagons are extensions to your application train running on Rails
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Returns an array containing all available versions of the gem spec .
- Gets a wagon class .
- Install the wagon .
- Checks that the dependencies are satisfied .
- Checks if the gem specifications are satisfied .
- Delete an item from the array
- Append the array of all wagons .
wagons Key Features
wagons Examples and Code Snippets
Community Discussions
Trending Discussions on wagons
QUESTION
Input description
The first line of my input contains two numbers: π and π, denoting respectively the number of containers (2 β€ π β€ 20,000)
and the number of deliveries (not more than 100,000
)
In the following π lines there are pairs of numbers: π€ and π§, where π€ is the number of wagons in the delivery
(no more than 20,000
) and π§ is the number of gravel in each wagon (no more than 20,000
).
The total number of wagons from all deliveries will not exceed 1,000,000
.
There will be no situation in any of the inputs where the container will contain more
than 1,000,000,000
gravel.
Problem statement
Wagons are emptied one at a time, evenly into two consecutive containers. These are the rules for determining which two adjacent containers are chosen (where containers[]
denotes a list of the n
current container sizes):
- Among all pairs
(containers[i], containers[i+1])
with0 <= i < n - 1
, choose the pair which minimizesmin(containers[i], containers[i+1])
- If there is a tie, choose among the tied pairs, the pair which minimizes
max(containers[i], containers[i+1])
(i.e. minimizes the second smallest element in the pair) - If there is still a tie, choose the pair
(containers[i], containers[i+1])
with minimum indexi
among the tied pairs.
The gravel is distributed equally into the pair. If there is an odd number of gravel in a wagon, the container with the smaller ID gains the surplus (1 pebble).
At first, all containers are empty.
For example:
...ANSWER
Answered 2022-Mar-06 at 03:59You can solve this much more efficiently by using a min-heap (i.e. priority queue), such as the one provided in Python's standard library. The main purpose of a heap is for efficiently tracking the minimum element of a collection, removing that minimum, and adding new elements, which accurately reflects your problem.
Currently, the line:
QUESTION
I have an optimization problem of wagons repairs.
...ANSWER
Answered 2022-Feb-25 at 10:36You can first get the possible ones like this:
QUESTION
The bridge's length and load-carrying capacity are known. Each of the train's wagons has a given length and weight. Program must determine whether the train can safely cross the bridge, i.e. whether the total weight of wagons that will simultaneously be on the bridge exceeds the bridge's carrying capacity. To be safe, if any part of a wagon is on the bridge, we will count the entire weight of that wagon in computing the total weight at that moment.
Input format:
The first input line contains two integers: the length of the bridge and its carrying capacity.
The following input line(s) contain a sequence of pairs indicating the length and weight of each wagon in sequence. Each wagon's length and weight will always appear on the same line. Each input line will be at most 200 characters long.
Output:
If the train can safely cross the bridge, write the number -1. Otherwise, write the number of the first wagon that will cause the weight to exceed the bridge's carrying capacity. Wagons are numbered from 1.
Sample input #1:
10 100
10 90 10 10 9 80 1 10 9 10 9 80
5 10 5 10
1 10 1 10 1 10 1 10 1 40
Output:
-1
Sample input #2:
7 20
3 4 3 5
3 5 3 7
3 7 3 7
3 6
Output:
4
Some more examples:
Input:
5 10
5 5 5 5 5 5 5 5 5 5 5 100 5 100 5 100
Output:
6
My code is
...ANSWER
Answered 2021-Dec-25 at 16:05I haven't proved my solution. There might be some redundant code.
My code will return the index (0 based indexing) of 1st wagon which will cause the issue if you want the last just update the recursion:
- my code will return -1 if bridge is not destroyed.
- my code will return (index,'s') means the partial wagon at start will cause the destruction
- my code will return (index,'e') means the partial wagon at end will cause the destruction
- my code will return (index,'f') means the full wagon at start will cause the destruction
My code :
QUESTION
Has anyone faced this ... Was working fine a week ago.
Steps I tried:
- Re-installed the installer
- Re-installed Visual Studio 2019 Enterprise
- Ran several repairs from the installer
- Clean install.NET 3.1 Framework / .NET 5.0 Framework / VS Framework (basically all the frameworks)
- Delete obj & bin folders and build
- Deleted and installed all packages (installer was failing due to Debuger/Remote package being corrupted)
It fails the build every time there I'm trying to get a list by direct index as in the picture below e.g. wagons[i]
This is where it says it fails:
...ANSWER
Answered 2021-Jun-27 at 15:28So after all a simple check for a windows update, updating and installing with a restart fixed it. As far as I could judge the C# compiler csc.exe
file was misbehaving.
Could be worth a try if anyone else experiences a similar glitch
QUESTION
I use the Bezier Path Creator from the package manager to let a train ride on a predefined path. (https://assetstore.unity.com/packages/tools/utilities/b-zier-path-creator-136082)
Currently, I have the following code on one train unit:
...ANSWER
Answered 2021-Apr-08 at 17:25I would handle this by handling the front and back bogie of each car instead of the center of each car. And if you can assume that the track is relatively straight and that each car is going the same speed (these are the same assumption unless you want to model spring forces at each car coupling), this should work:
QUESTION
I recently started using gradle and trying to publish a multi module project to AWS Artifact. My build file for submodules looks like below
- Module: core
ANSWER
Answered 2021-Mar-23 at 07:54Regarding your main application build file:
Try including the publishing{} block inside of an allprojects{} block or add it to the above subprojects{} block as well. Currently the publishing-specification is only applied on root-project level.
QUESTION
Im trying to write a iterative method to get the last wagon of a train sequence. But i'm getting stuck on how to do this. Can anyone help me in the right direction?
The method:
...ANSWER
Answered 2020-Oct-26 at 18:41You need a loop that checks if there is a nextWagon, aka currentWagon.nextWagon != null. If there isn't return the currentWagon. If there is, assign the nextWagon as currentWagon and run the check again.
here is some pseudo code
QUESTION
I have this simple html file that just contains a table.
...ANSWER
Answered 2020-Sep-26 at 13:06Use clone()
to make copies if that is what you are wanting to do .
When you append an element it can only exist once and append does not make a copy of it
QUESTION
My Google font's italic face is really subtle so I'm trying to add additional slant using the CSS transform: skew
element. I have the text wrapped in a span, but in order to allow the transform property to work, I'm also using display: inline-block
. However, when using this method within a list item, it forces half the list item down onto a new line. Does anyone know how to prevent this?
Screenshot of list item with forced line break:
...ANSWER
Answered 2020-Jul-22 at 20:21One approach to achieve this effect is to use javascript to apply a to every individual character in your original
(which, in the working example below, I have renamed
).
This prevents your inline-block
becoming so wide that the rest of the bibliography entry can only follow it by starting on a new line.
Working Example:
QUESTION
I have the following java class with constructor and getters and setters.
...ANSWER
Answered 2020-Jul-22 at 12:27You are not iterating over Wagons because when you call wag8.add(train.getFreight())
, now your list has only one Wagon
. My suggestion is to write a method named 'hasNext()' in your Wagon
class so that you can know if there is another Wagon
connected to the current wagon. Something like this:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install wagons
On a UNIX-like operating system, using your systemβs package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page