cfoo | CloudFormation master | AWS library
kandi X-RAY | cfoo Summary
kandi X-RAY | cfoo Summary
Cfoo (pronounced "sifu") lets you write your CloudFormation templates in YAML, and makes it easier with some helpers.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Overrides the list of type definitions
- Finds a string matching the coordinates of a given file .
- Parse the given file name and raise an error
- Evaluates the c - yaml file
- Parse the project map
- Loads the YAML file
- Returns true if this domain is equal .
cfoo Key Features
cfoo Examples and Code Snippets
Community Discussions
Trending Discussions on cfoo
QUESTION
I need to initialize large conversion table as data member in my class:
...ANSWER
Answered 2021-Jan-21 at 12:02Let table_t be the type of member_large_table. Then you can do the following:
QUESTION
I want to raise an exception in C++ class constructor if some parameters are invalid, e.g., do PyErr_SetString(PyExc_ValueError, "Error occurred"). Unfortunately, it does not propagate correctly, and I get SystemError: returned a result with an error set instead. Is it even possible to make it work inside a constructor?
Several concerns:
- All of the logic should be in the C++ class without spreading into
.pyxfiles. - Validation should happen inside the constructor, so that it is not needed to call separate
init()method after object creation. - It should be possible to raise not only some standard exceptions, but any custom.
setup.py
...ANSWER
Answered 2020-Nov-11 at 18:14First, be aware that this has the potential to go a quite wrong. Python scoping rules are different from C++ scoping rules, and Cython largely follows Python scoping rules. Consider
QUESTION
I have a member function pointer and I'm trying to invoke the function in one of the member function. The function pointer is set using a lambda.
...ANSWER
Answered 2020-Sep-28 at 23:57Your issue is that an std::function is not a member function,so you don't need to pass this or use the pointer-to-member syntax.
QUESTION
I have a protocol FooProtocol. and a class Bar. Inside a class an Array var mess: [Foo?]? to keep [foo1, foo2, nil, foo3...] or nil
And I try to make extension for this array to count new Foo object. I prefer to have protocols, because Foos could be very different objects delivered from outer world.
ANSWER
Answered 2020-Jun-24 at 13:06From my understanding, it should work as you did, but one never knows what happens in the swift compiler world (and especially it's error messages).
Anyway, you can circumvent digging deeper into Wrapped.Element.Wrapped by specifyig the Wrapped.Element more precisely to be an Optional:
QUESTION
I have a Python class AbstractFoo which uses @abc.abstractmethod to define 2 abstract methods.
For more performance the bulk of the work is implemented in C as a Python extension class CFoo, so what I wanted to do is to inherit that extension class from AbstractFoo.
However I haven't found a way to do this and went a different route: Implement it as a "normal" class in C and have a class ConcreteFoo(AbstractFoo, CFoo) which inherits from the abstract Python and the extension class.
However now the "protection" from the ABC didn't kick in: No error was thrown even when the methods were missing. I found a solution in https://stackoverflow.com/a/20440259/1930508 and added a new new method instead of PyType_GenericNew (ignore the ref counts of the empty_* parts for now):
ANSWER
Answered 2020-May-25 at 07:43You have to make CFoo the first base class. This has little to do with the C-API and applies to a pure Python version too: if you define
QUESTION
I'm considering transitioning from snprintf and its ilk to fmtlib. Imagine this fictional code:
...ANSWER
Answered 2020-Apr-02 at 07:03The closest function there is to swprintf_s() in fmtlib is fmt::format_to_n(). However, it returns the number of characters that would have been written, so you have to take some care using it. Here is how it would look:
QUESTION
I created an AbstractFoo reference class and several subclasses, now I want to get all the names of the subclasses (AFoo, BFoo, CFoo). It seems this is possible using the subclasses slot of an S4 class, but I'd like to get the same sort of thing for a reference class.
For instance my code might be:
...ANSWER
Answered 2019-Oct-31 at 23:14foo = function(nm){
objs = ls(envir = .GlobalEnv)
tmp = setNames(lapply(objs, function(objName){
thisObj = get(objName)
if (class(thisObj) == "refObjectGenerator" & objName != nm){
is(thisObj(), nm)
}
}), objs)
tmp = unlist(tmp)
names(tmp)[tmp]
}
foo("AbstractFoo")
#[1] "AFoo" "BFoo" "CFoo"
QUESTION
When and why should we use the 'struct' keyword when declaring a class pointer variable in C++?
I've seen this in embedded environments so I suspect that this is some kind of hold over from C. I've seen plenty of explanations on when to use the 'struct' keyword when declaring a struct object as it relates to namespaces in C (here), but I wasn't able to find anyone talking about why one might use it when declaring a class pointer variable.
Example, in CFoo.h:
...ANSWER
Answered 2019-Aug-21 at 16:26There's rarely a reason to do this: it's a fallover from C and in this case the programmer is simply being sentimental - perhaps it's there as a quest for readability. That said, it can be used in place of forward declarations.
In some instances you might need to disambiguate, but that's not the case here. One example where disambiguation would be necessary is
QUESTION
I want to put couple of function into my .bashrc.
The functions may execute for a long time so I'd like to be able to kill them with CTRL+C and print some information when this happens. I can capture CTRL+C by trapping SIGINT but I'm not sure what is the correct way to set different trap handlers for different functions inside the same script (.bashrc).
I came up with this solution which seems to work:
...ANSWER
Answered 2018-Dec-20 at 01:18Yes, the trap is resetting things globally. It would probably be good to reset it to its original value when the function ends. Something like:
QUESTION
When I have a public interface
...ANSWER
Answered 2018-Dec-07 at 10:43The modifier must be public because the interface is public.
While that would have been a way of determining it: that isn't what the compiler wants. For implicit interface implementation (regardless of the visibility of the interface type), a member must be declared as public, no "ifs", "buts" or "maybes" (the implementing type, however, can be any visibility level)
Absolutely the language designers could have looked at more complex rules, but: since there is also an option for explicit interface implementation, they presumably didn't feel that it was necessary to do so.
Specifically, this is §18.6.5 ("Interface mapping") in the specification (v5) - emphasis mine ("I"=interface type, "M"=member, "S"=implementing type):
- If S contains a declaration of an explicit interface member implementation that matches I and M, then this member is the implementation of I.M.
- Otherwise, if S contains a declaration of a non-static public member that matches M, then this member is the implementation of I.M. If more than one member matches, it is unspecified which member is the implementation of I.M. This situation can only occur if S is a constructed type where the two members as declared in the generic type have different signatures, but the type arguments make their signatures identical.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install cfoo
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
