permutation | Permutation library in Ruby

 by   flori Ruby Version: Current License: No License

kandi X-RAY | permutation Summary

kandi X-RAY | permutation Summary

permutation is a Ruby library. permutation has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Permutation library in Ruby
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              permutation has a low active ecosystem.
              It has 28 star(s) with 1 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              permutation has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of permutation is current.

            kandi-Quality Quality

              permutation has 0 bugs and 0 code smells.

            kandi-Security Security

              permutation has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              permutation code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              permutation does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              permutation releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of permutation
            Get all kandi verified functions for this library.

            permutation Key Features

            No Key Features are available at this moment for permutation.

            permutation Examples and Code Snippets

            No Code Snippets are available at this moment for permutation.

            Community Discussions

            QUESTION

            R: Trying to recreate mean-median difference gerrymander tests
            Asked 2022-Feb-09 at 23:58

            I'm trying to recreate the mean-median difference test described here: Archive of NYT article. I've downloaded House data from MIT's Election Lab, and pared it down to the 2012 Pennsylvania race. Using dplyr, I whittled it down to the relevant columns, and it now looks something like this:

            ...

            ANSWER

            Answered 2022-Feb-09 at 23:58

            I figured it out! Randomly placing voters in each district is not correct, and honestly it was pretty silly of me to do so. Instead, I had to use dplyr to create a data frame with the number of Democrat and Republican votes in each of the 435 House districts, one district per row. Then, I followed the advice on page 12 of this paper. I created samples of 18 districts sampled from this 435-row data frame, rejecting them if the mean vote share was more than 1 percent away from that of PA. The results have a much nicer 95% confidence interval, that matches the results of the original article.

            Source https://stackoverflow.com/questions/71026587

            QUESTION

            How to get sufficient entropy for shuffling cards in Java?
            Asked 2022-Jan-17 at 04:31

            I'm working on a statistics project involving cards and shuffling, and I've run across an issue with random number generation.

            From a simple bit of math there are 52! possible deck permutations, which is approximately 2^226. I believe this means that I need a random number generator with a minimum of 226 bits of entropy, and possibly more (I'm not certain of this concept so any help would be great).

            From a quick google search, the Math.random() generator in Java has a maximum of 48 bits of entropy, meaning that the vast majority of possible deck combinations would not be represented. So this does not seem to be the way to go in Java.

            I was linked to this generator but it doesn't have a java implementation yet. Also for a bit of context here is one of my shuffling algorithms (it uses the Fisher-Yates method). If you have any suggestions for better code efficiency that would be fantastic as well.

            ...

            ANSWER

            Answered 2022-Jan-15 at 01:10

            Have you looked into the recent additions that are included in JDK 17?

            https://docs.oracle.com/en/java/javase/17/core/pseudorandom-number-generators.html#GUID-08E418B9-036F-4D11-8E1C-5EB19B23D8A1

            There are plenty of algorithms available:

            https://docs.oracle.com/en/java/javase/17/docs/api/java.base/java/util/random/package-summary.html#algorithms

            For shuffling cards you likely don't need something that is cryptographically secure.

            Using Collections.shuffle should do the trick if you provide a decent RNG.

            https://docs.oracle.com/en/java/javase/17/docs/api/java.base/java/util/Collections.html#shuffle(java.util.List,java.util.Random)

            Source https://stackoverflow.com/questions/70717929

            QUESTION

            How to smooth out the trails of the particles in a p5js simulation
            Asked 2022-Jan-12 at 02:37

            I want to turn this halting, discontinuous trails in the particle on this simulation

            to something worth staring at as in this beautiful field flow in here (not my work, but I don't remember where I got it from).

            I have tried different permutations of the code in the accomplished field flow without getting anything remotely close to the smoothness in the transitions that I was aiming for. I suspect I am mishandling the updates or the placement of the black rectangle that seems to circumvent the need for a black background, which would erase the wake of the particles.

            ...

            ANSWER

            Answered 2022-Jan-11 at 17:55

            You can get trials in multiple ways. The sketch you mentioned creates the trails by adding opacity to the background with the "fill( 0, 10 )" function.

            If you want to know more about p5 functions you can always look them up here: https://p5js.org/reference/. The fill() page shows that the first argument is the color ( 0 for black ) and the second argument is the opacity ( 10 out of 255 ).

            In the sketch you mentioned, in draw(), they wrote:

            Source https://stackoverflow.com/questions/70669702

            QUESTION

            Return all matrices of a given dimension with a certain number of ones and remaining zeros
            Asked 2022-Jan-02 at 12:49

            Consider the following simplified example, with all possible 2 x 2 matrices with one 1 and the remaining 0s.

            ...

            ANSWER

            Answered 2021-Dec-31 at 17:52

            You could use the function developed here to get all possible matrices of dim 5x4, and then filter by the number of 1s using sum.

            Source https://stackoverflow.com/questions/70544466

            QUESTION

            How do i find all possible permutations of the first 1-2 letters of each word?
            Asked 2021-Dec-30 at 23:08

            I have the following data:

            ...

            ANSWER

            Answered 2021-Dec-30 at 20:32

            We'll use gtools::permutations to calculate the ... permutations of inputs, and then use expand.grid to show all combinations within them.

            First, we can do it easily on one order of the inputs with:

            Source https://stackoverflow.com/questions/70536196

            QUESTION

            Permutations without reversed sequences in Python
            Asked 2021-Nov-12 at 15:36

            I would like to generate a list of all permutations of 4 digits where :

            • All 4 digits are always present
            • Two reversed sequences are the same solution. For example. (1,2,3,4) = (4,3,2,1)

            I would like to know:

            • What do you call this kind of permutations.
            • If it is possible to generate this list in one step. Below there is an example that generates it in two steps.
            ...

            ANSWER

            Answered 2021-Nov-12 at 13:45

            To simplify your code and make it more efficient you could:

            1- use a python set as the container (checking the presence of an element is much faster)

            2- add the final output directly

            3- avoid to create a temporary list with the permutations, keep it as a generator

            Source https://stackoverflow.com/questions/69943766

            QUESTION

            How / why does behavior of SQL*Plus BREAK depend on column order?
            Asked 2021-Nov-11 at 07:49
            Background

            I'm familiar with databases but have never used Oracle in particular. In the process of trying to help someone with a homework assignment, I've hit a snag trying to understand the behavior of the BREAK command. In particular, the results of using the BREAK command seem to depend on the order of the columns in the query I'm using, which as far as I can tell is not reflected in the documentation in any way.

            Setup for examples

            I created a table where there are a couple of different colors, each with a few items of that color, like so:

            ...

            ANSWER

            Answered 2021-Nov-11 at 07:49

            The behaviour of BREAK in your example is not right. I update this post thanks to @Littlefoot, and is due to the fact that you are using a SqlDeveloper, a java tool not intended for this kind of reporting.

            I created your table and insert the records in both databases, then running the reports you did.

            Demo 12cR2

            Source https://stackoverflow.com/questions/69923625

            QUESTION

            Looking for a TypeScript type that consists of any possible combination of Template Literals Types
            Asked 2021-Nov-07 at 00:29

            For my project, I need to come up with a TypeScript type, which is this so-called CardSize.

            This type can take various forms. It can either be a static value, a responsive (breakpoint-specific) value, or a combination of either of them separated by a white space.

            The possible (singular) values are as follows:

            ...

            ANSWER

            Answered 2021-Nov-07 at 00:29

            You can definitely generate a union type of permutations/combinations of string values, recursively concatenated via template literal types. Of course, the number permutations and combinations grows quite rapidly as you increase the number of elements to permute and combine. TypeScript can only handle building unions on the order of tens of thousands of elements, and compiler performance tends to suffer when you get close to this. So this approach will only work for small numbers of elements.

            Your CardSize example will be fine because you only have two sizes and four breakpoints:

            Source https://stackoverflow.com/questions/69864634

            QUESTION

            How to determine that Java is running on Windows
            Asked 2021-Nov-01 at 16:26

            I wish to determine whether Java is running on Windows, and have seen many different suggestions which include various permutations of the System property os.name with startsWith / indexOf / contains / toLowerCase(Locale.ENGLISH) / toLowerCase(), or just File.separatorChar.

            I scanned JDK source code to see whether there was a definitive answer (see below) and a few other SO posts which suggest:

            ...

            ANSWER

            Answered 2021-Nov-01 at 16:26

            After noting the various comments and other posts, I've not found a reason not to continue using the isWindows check I currently have in my code, which is simply the first test listed:

            Source https://stackoverflow.com/questions/69513668

            QUESTION

            Shortest string that can be made in at least two ways from an array of strings
            Asked 2021-Oct-31 at 15:28

            Statement:

            Given an array of strings S. You can make a string by combining elements from the array S (you can use an element more than once)

            In some situations, there are many ways to make a certain string from the array S.

            Example:

            S = {a, ab, ba}

            Then there are 2 ways to make the string "aba":

            • "a" + "ba"
            • "ab" + "a"

            Question:

            Given an array of string S. Find the shortest string such that there are more that one way to make that string from S. If there're none, print out -1.

            P/S: I have been thinking for many days but this is the best one I've got so far:

            • Generate all permutations of the array
            • For each permutation, make a string from the array S
            • Check if that string is made before, if yes, print out the string, if not, save that string.

            But this algorithm clearly won't pass all the test cases. I can't think of any better algorithm.

            ...

            ANSWER

            Answered 2021-Oct-31 at 15:28

            Here's an O(N3) algorithm, where N is the total length of each string:

            1. For every element Si in S:
              1. Construct an NFA for the regular expression Si(S1|...|Sn)*
              2. Construct an NFA for the regular expression (S1|...|Si-1|Si+1|...|Sn)(S1|...|Sn)*
              3. Construct an NFA that is the intersection of the NFA in step 1.1 and step 1.2
              4. Find the shortest string accepted by the NFA in step 1.3
            2. Return the shortest string among the strings in step 1.4

            The above algorithm can be improved to O(N2logN):

            1. Construct an NFA for the regular expression (S1|...|Sn)*
            2. Construct cross-product of two copies of the NFA in step 1.
            3. For each state in the NFA in step 2, find the shortest string accepted by the NFA from that state.
            4. Let 𝒮 = {S}.
            5. While 𝒮 is not empty:
              1. Take an element T from 𝒮.
              2. Partition T into P and Q somewhat evenly.
              3. Construct an NFA for the regular expression (P1|...|Pp)(S1|...|Sn)*, reusing the NFA in step 1.
              4. Construct an NFA for the regular expression (Q1|...|Qq)(S1|...|Sn)*, reusing the NFA in step 1.
              5. Construct cross-product of the NFA in step 5.3 and step 5.4, reusing the NFA in step 2.
              6. Find the shortest string accepted by the NFA in step 5.5, reusing the result of step 3.
              7. If P has more than 1 element, put P into 𝒮.
              8. If Q has more than 1 element, put Q into 𝒮.
            6. Return the shortest string among the strings in step 5.6

            Edit: The following is an O(N2) algorithm, improved from the top answer:

            1. Let T be every suffix of every string of S.
            2. Build a trie out of T.
            3. Let G be a weighted directed graph. The vertices are the elements of T, and the edges are: for each string Si in S and Tj in T, if Si = Tj + D or Tj = Si + D (using the trie in step 2 to find all such pairs), add an edge from D to Tj weighted length of Si.
            4. Find the distance from the empty string to every vertex in G.
            5. For each string Si, Sj in S, if Si != Sj and Si = Sj + D (using the trie in step 2 to find all such pairs), find the distance from the empty string to D (using step 4).
            6. The length of the answer is half of the shortest distance among all distances in step 5. (It's trivial to find the actual answer but I'm too lazy to describe it :p)

            Source https://stackoverflow.com/questions/69693500

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install permutation

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/flori/permutation.git

          • CLI

            gh repo clone flori/permutation

          • sshUrl

            git@github.com:flori/permutation.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link