encryption | simple wrapper for the OpenSSL Cipher library | Encryption library
kandi X-RAY | encryption Summary
kandi X-RAY | encryption Summary
[Build Status] A simple to use wrapper of the Ruby OpenSSL Cipher library for Ruby and Rails applications. This gem provides an easy to use interface for symmetrical and asymmetrical encryption using RSA.
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Top functions reviewed by kandi - BETA
- Creates a new encryption object .
- Initializes the cipher .
- Serialize the key to a PEM file
- Delegates to the configuration
- Decrypt a string
- Encrypts a string using the provided encoding .
- Determine if the name is defined .
- Replace the options with the given options
- Returns the public key for the public key
- Returns a private private key
encryption Key Features
encryption Examples and Code Snippets
Community Discussions
Trending Discussions on encryption
QUESTION
I'm trying to figure out how to create a timeout for the handshake process in a TLS connection in a QTcpServer.
I tried something like this in the overriden incomingConnection function:
ANSWER
Answered 2021-Jun-15 at 10:02I ended implementing the TLS handshake timeout this way:
QUESTION
I don't really know where the error is, for me, it's still a mystery. But I'm using Laravel 8 to produce a project, it was working perfectly and randomly started to return this error and all projects started to return this error too. I believe it's something with Redis, as I'm using it to store the system cache. When I go to access my endpoint in postman it returns the following error:
...ANSWER
Answered 2021-Jun-12 at 01:50Your problem is that you have set SESSION_CONNECTION=session, but your SESSION_DRIVER=default, so you have to use SESSION_DRIVER=database in your .env. See the config/session.php:
QUESTION
I am trying encrypting in JS front end and decrypt in python backend using AES GCM cryptographic algorithm. I am using Web cryptography api for JS front end and python cryptography library for python backend as cryptographic library. I have fixed the IV for now in both side. I have implemented encryption-decryption code in both side, they work on each side. But I think the padding is done differently, can't seem to figure out how the padding is done in web cryptography api. Here is the encryption and decryption for the python backend:
...ANSWER
Answered 2021-Jun-14 at 18:01GCM is a stream cipher mode and therefore does not require padding. During encryption, an authentication tag is implicitly generated, which is used for authentication during decryption. Also, an IV/nonce of 12 bytes is recommended for GCM.
The posted Python code unnecessarily pads and doesn't take the authentication tag into account, unlike the JavaScript code, which may be the main reason for the different ciphertexts. Whether this is the only reason and whether the JavaScript code implements GCM correctly, is difficult to say, since the getMessageEncoding() method was not posted, so testing this was not possible.
Also, both codes apply a 16 bytes IV/nonce instead of the recommended 12 bytes IV/nonce.
Cryptography offers two possible implementations for GCM. One implementation uses the architecture of the non-authenticating modes like CBC. The posted Python code applies this design, but does not take authentication into account and therefore implements GCM incompletely. A correct example for this design can be found here.
Cryptography generally recommends the other approach for GCM (s. the Danger note), namely the AESGCM class, which performs implicit authentication so that this cannot be accidentally forgotten or incorrectly implemented.
The following implementation uses the AESGCM class (and also takes into account the optional additional authenticated data):
QUESTION
I am new to SwiftUI (iOS App Ver 14.x) as I normally use Xamarin.
In this case I need to have the application specifically written in SwiftUI. (I am aware that some stuff still needs UIKit).
I have got my head around it though I am generally speaking struggling to get to grips with where and how to store stuff.
For example (greatly simplified) let us say I want the following:
All in the same view.
Two form fields:
First Name: … Last Name: …
A Button that says, “Add Photo”.
A Button that says, “Save Locally” (N/a but just for info, to be later uploaded to a web service that isn't always available at some point).
Now doing all the standard stuff this is pretty straight forward.
BUT.
I want to encrypt the form input (once converted to JSON, note I can convert to JSON easy enough).
I also want to encrypt the image before it is stored. (the real app has more than one image).
The stuff will be encrypted in the real app using asymmetric encryption (which I understand well, again this is not so relevant here).
But for the sake of example, I am happy to just ‘encrypt’ the JSON and picture as two separate files using something simple just to show the idea. XOR it or something simple to show.
My question is where is the best places code wise to do this with some basic examples if possible. I know this is a little subjective but just something simple and obvious. Click button, run this func, do this type of thing etc.
Where do I store stuff (which I am finding a bit all over the place)? This is my main source of confusion being honest.
My understanding is that you would use a FileManager object and the documents directory (though I am not sure if this is best practice, or even the right place.
The requirement from a client is that nothing is stored unencrypted for compliance reasons (completely ignoring anything Apple have in place good or bad).
...ANSWER
Answered 2021-Jun-14 at 06:58Yes you can just store it in the documents folder by using file manager:
FileManager.url(for: .documentDirectory, in: .userDomainMask, appropriateFor: nil, create: false)[0]
As for encryption, if you encrypt the data before writing them to disk then they are encrypted...
One issue is that the encryption key has to be stored securely as well. For this, I usually generate the key when it is first used and store in keychain. Hard-coding the key in the code is not as secure because it makes the key identical for all users, and the binary can (not sure how easy) be reverse-engineered. We have to trust Apple's keychain to be secure. Some checks for jailbreaking may also help hear.
Also note that unlike other app data (UserDefaults, files etc), keychain is NOT cleared when the app is reinstalled!!! This can be a major source of headache. If desired, you can work around this by running a a chunk of code to clear the keychain when the app runs the first time after installation (by keeping a flag in UserDefaults, for example, which is cleared when app is reinstalled).
QUESTION
Error:
...ANSWER
Answered 2021-Mar-19 at 15:15It's this typo:
QUESTION
trying to mount EFS to ECS Fargate but getting below error while task is being executed. it looks as though it is an IAM issue but crosschecked all the roles and unable to identify the issue. Checked security groups as well.i allowed 2049 port and attached ecs security group to it.
"ResourceInitializationError: failed to invoke EFS utils commands to set up EFS volumes: stderr: b'mount.nfs4: access denied by server while mounting 127.0.0.1:/' : unsuccessful EFS utils command execution; code: 32"
Terraform 0.12 and Fargate 1.4.0
...ANSWER
Answered 2021-Jun-09 at 15:01I had a related problem because the directory has not yet been created, there is a property in root_directory that allows creating the directory with proper permissions.
In the example I use root, but you can set another gid.
QUESTION
I am trying to use kafka rest proxy for AWS MSK cluster.
MSK Encryption details:
Within the cluster
TLS encryption: Enabled
Between clients and brokers
TLS encryption: Enabled
Plaintext: Not enabled
I have created topic "TestTopic" on MSK and then I have created another EC2 instance in the same VPC as MSK to work as Rest proxy. Here are details from kafka-rest.properties:
...ANSWER
Answered 2021-Jun-13 at 10:23Finally the issue was fixed. I am updating the fix here so that it can be beneficial for someone:
kafka-rest.properties file should have below text:
QUESTION
I am new to Oracle SQL,
And have following requirement,
There is a customer table with following columns,
...ANSWER
Answered 2021-Jun-13 at 08:07Manage to do the task, Craeting Package therdata_encrypt_decrypt
QUESTION
So I tried to read the file and encrypt its content with cryptography.fernet but sometimes the file contains characters that can't be encrypted by whatever algorithm is being used in this library. I also tried a library called pyAesCrypt which has this function: pyAesCrypt.encryptFile("data.txt", "data.txt.aes", password). But it also can't encrypt some file types like gifs.
I don't know much about the encryption algorithm happening in the background, but is there any way I can encrypt all files no matter what characters they contain? Or maybe encode them first to get rid of these characters then encrypt them? I'm just giving ideas based on the small knowledge I have about this topic.
The code I tried with Fernet library:
...ANSWER
Answered 2021-Jun-12 at 08:03you must open file in binary mode for reading and writing. since encrypt method expect bytes as a parameter, this way you can encrypt any file no matter it's type.
QUESTION
I'm new to PGP encryption and I'm trying to understand a problem I'm having. I have this public key (taken from some examples online)
...ANSWER
Answered 2021-Jun-11 at 17:35The error message explicitly tells you that the key that fails doesn't describe itself as suitable for encrypted storage or communications.
Per the signature subpacket specification, we know that this information lives in a subpacket of type 27.
Per the detailed specification on that subpacket, we know that the desired flags are 0x04 and 0x08, respectively.
To compare these keys, you can use gpg --list-packets --verbose.
For the first, non-working key, we get:
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