reread | Source of https : //reread.io | Runtime Evironment library

 by   jollygoodcode Ruby Version: Current License: MIT

kandi X-RAY | reread Summary

kandi X-RAY | reread Summary

reread is a Ruby library typically used in Server, Runtime Evironment, Nodejs applications. reread has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

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              reread has a low active ecosystem.
              It has 77 star(s) with 4 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 1 have been closed. On average issues are closed in 20 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of reread is current.

            kandi-Quality Quality

              reread has 0 bugs and 0 code smells.

            kandi-Security Security

              reread has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              reread code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              reread is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              reread releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.
              reread saves you 875 person hours of effort in developing the same functionality from scratch.
              It has 2003 lines of code, 102 functions and 81 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            reread Key Features

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            reread Examples and Code Snippets

            No Code Snippets are available at this moment for reread.

            Community Discussions

            QUESTION

            RDD in Spark: where and how are they stored?
            Asked 2021-Jun-09 at 09:45

            I've always heard that Spark is 100x faster than classic Map Reduce frameworks like Hadoop. But recently I'm reading that this is only true if RDDs are cached, which I thought was always done but instead requires the explicit cache () method.

            I would like to understand how all produced RDDs are stored throughout the work. Suppose we have this workflow:

            1. I read a file -> I get the RDD_ONE
            2. I use the map on the RDD_ONE -> I get the RDD_TWO
            3. I use any other transformation on the RDD_TWO

            QUESTIONS:

            if I don't use cache () or persist () is every RDD stored in memory, in cache or on disk (local file system or HDFS)?

            if RDD_THREE depends on RDD_TWO and this in turn depends on RDD_ONE (lineage) if I didn't use the cache () method on RDD_THREE Spark should recalculate RDD_ONE (reread it from disk) and then RDD_TWO to get RDD_THREE?

            Thanks in advance.

            ...

            ANSWER

            Answered 2021-Jun-09 at 06:13

            In spark there are two types of operations: transformations and actions. A transformation on a dataframe will return another dataframe and an action on a dataframe will return a value.

            Transformations are lazy, so when a transformation is performed spark will add it to the DAG and execute it when an action is called.

            Suppose, you read a file into a dataframe, then perform a filter, join, aggregate, and then count. The count operation which is an action will actually kick all the previous transformation.

            If we call another action(like show) the whole operation is executed again which can be time consuming. So, if we want not to run the whole set of operation again and again we can cache the dataframe.

            Few pointers you can consider while caching:

            1. Cache only when the resulting dataframe is generated from significant transformation. If spark can regenerate the cached dataframe in few seconds then caching is not required.
            2. Cache should be performed when the dataframe is used for multiple actions. If there are only 1-2 actions on the dataframe then it is not worth saving that dataframe in memory.

            Source https://stackoverflow.com/questions/67894971

            QUESTION

            Import a JavaScript module or library into TypeScript
            Asked 2021-Jun-08 at 20:24

            Over many years I've struggled with this same issue. I cannot seem to work out how to use a JavaScript library from TypeScript, reliably.

            I seem to get it working by accident and then move on and not revisit such code for years until a extrinsic change forces a breakage, like today when I updated VS 2019.

            I've spent days reading about modules and requires and loaders, but I get more and more confused.

            Example. I want to use DayJS in a TypeScript .ts file I am writing.

            Here's the sample code.

            ...

            ANSWER

            Answered 2021-Jun-04 at 18:38

            I share many of the same frustrations! It's so hard to get Typescript working nicely with Javascript and the microsoft documentation is so obtuse!

            In your case : the path to a library is always looked for in node_modules so in that case you don't need to add the full path.

            You also never need to import a .d.ts file. You can just put the .d.ts file somewhere in your working folder and VS Code will detect it.

            If you have the .d.ts file for moment.js, you will get type completion in VS Code. You don't need to import moment.js when you load it with a

            Source https://stackoverflow.com/questions/67842286

            QUESTION

            How to upgrade Django Celery App from Elastic Beanstalk Amazon Linux 1 to Amazon Linux 2
            Asked 2021-Jun-03 at 07:23

            I am trying to upgrade a Django Application running Celery from Amazon Elastic Beanstalk Linux 1 on running Python 3.6 to Amazon Linux 2 using Python 3.8.

            I am having trouble with the Celery application.

            In Linux 1 I the following file

            ...

            ANSWER

            Answered 2021-Apr-07 at 07:16

            The supervisor is not present in Amazon Linux2 by default.You just have to rewrite this script to run celery under the supervision of systems like this

            Source https://stackoverflow.com/questions/66963932

            QUESTION

            How to delete previous version of lines before lines were rewritten in python
            Asked 2021-May-20 at 14:25

            I am trying to change some information in a textfile. Initially, the textfile looks like

            ...

            ANSWER

            Answered 2021-May-20 at 14:25

            The easiest way(that I can think is) to do is open the file

            read the file and save the lines

            and then empty the file

            Source https://stackoverflow.com/questions/67622262

            QUESTION

            R function stops after system() call
            Asked 2021-May-05 at 15:42

            I've written a very easy wrapper around GDAL in R. It utilises a prewritten statement which is passed to system, creating an output, which I then want to read into the R environment again.

            It works by creates a temporary directory in the working directory, printing out an ESRI shape file of our area of interest, and then cuts a raster by this, with some preset information.

            My problem: after successfully running the system() call and creating the output file, the function stops. It doesn't execute the next call and read the output into the R environment.

            ...

            ANSWER

            Answered 2021-May-05 at 15:42

            The function did not return anything. Here is a somewhat improved version of your function. If you want to keep the output it would make more sense to provide a full path, rather then saving it to a temp folder. I also note that you are not using the argument source_srs

            Source https://stackoverflow.com/questions/67398236

            QUESTION

            Kafka Connect Reread Entire File for KSQLDB Debugging or KSQLDB possiblity to insert all events after query creation?
            Asked 2021-May-05 at 08:41

            I start to develop with KSQLDB and alongside with Kafka-connect. Kafka-connect is awesome and everything is well and has the behaviour to not reread the records if it detects that it was already read in the past (extrem useful for production). But, for development and debugging of KSQLDB queries it is necessary to replay the data, as ksqldb will create table entries on the fly on emitted changes. If nothing is replayed the to 'test' query stays empty. Any advice how to replay a csv file with kafka connect after the file is inserted for the first time? Maybe, ksqldb has the possiblity to reread the whole topic after the table is created. Has someone the answer for a beginner?

            ...

            ANSWER

            Answered 2021-Apr-27 at 12:59

            Create the source connector with a different name, or give the CSV file a new name. Both should cause it to be re-read.

            Source https://stackoverflow.com/questions/67281808

            QUESTION

            How to share a string between two processes containing while loops?
            Asked 2021-Apr-26 at 19:33

            I've been struggling for a while trying to pass a variable between two processes,

            I have two processes, one that loops to run a PyQt5 GUI (process A), and a second running some computer vision functions on a video stream in real-time through a while loop (process B),

            I want to read a constantly updated (30 times a second) variable from B to A, latency up to ~200ms doesn't matter too much.

            Process A will make changes to the GUI based on the var passed from Process B but I'm struggling to pass that variable across,

            I've attached some skeleton code that shows my current broken attempt, I have reread the docs several times and a load of questions on here but I'm new to multiprocessing so I'm a bit stumped, I would really appreciate if someone could take a look and point me in the right direction, Thanks!

            ...

            ANSWER

            Answered 2021-Apr-26 at 19:33

            What is wrong with your program? It appears to work fine - from parameter passing point of view at least. I tweaked your code a bit (added a random choice and added sleep to the main process to avoid it exiting right away) and it seems to be doing fine:

            Source https://stackoverflow.com/questions/67271618

            QUESTION

            call empty function with address of local variable before setjmp, what for?
            Asked 2021-Apr-09 at 21:30

            I read code of C library and can not understand what is going on:

            ...

            ANSWER

            Answered 2021-Apr-09 at 21:30

            Yes, it's undefined behavior from the standpoint of standard C - or at least, the value of foo is indeterminate and can't be safely used for anything.

            C17 (n2176) 7.13.2.1 (3):

            All accessible objects have values, and all other components of the abstract machine have state, as of the time the longjmp function was called, except that the values of objects of automatic storage duration that are local to the function containing the invocation of the corresponding setjmp macro that do not have volatile-qualified type and have been changed between the setjmp invocation and longjmp call are indeterminate.

            That's precisely the situation here: foo has automatic storage duration and is local to the function where setjmp is invoked, it's not volatile-qualified, and it is changed between setjmp and longjmp.

            The authors of the code were probably thinking that passing &foo to lib_var would ensure that it is allocated in memory, not in a register, and that since the compiler couldn't know whether lib_var would modify foo, it couldn't constant-propagate the value NULL into the else block. But as you say, LTO or various other optimizations could break this. It's possible the authors intended only to support a particular compiler that they knew didn't do any such thing, or that provided some stronger guarantees beyond what the standard says, but it's also possible they were just confused.

            The correct fix would be to declare foo as volatile, i.e. struct Foo * volatile foo = NULL;.

            Source https://stackoverflow.com/questions/67028271

            QUESTION

            Can SMB2 CHANGE_NOTIFY be used to keep an accurate snapshot of a remote directory listing?
            Asked 2021-Mar-26 at 17:36

            SMB2 CHANGE_NOTIFY looks promising, as if it could deliver enough information on subdirectory or subtree updates from the server, so we can keep our listing of remote directory up-to-date by handling the response.

            However, it's not a subscription to an event stream, just a one-off command receiving one response, so I suspect that it can be used only as a mere hint to invalidate our cache and reread the directory. When we receive a response, there could be any additional changes before we send another CHANGE_NOTIFY request, and we'll miss the details of these changes.

            Is there any way around this problem? Or is rereading directory on learning that it's updated a necessary step?

            I want to understand possible solutions on the protocol level (you can imagine I'm using a customized client that I can make do what I want, with some common servers like Windows or smbd3).

            ...

            ANSWER

            Answered 2021-Mar-26 at 17:36

            Strictly speaking, not even re-reading the directory listing should save you, since the directory can change between re-reading the listing and submitting another CHANGE_NOTIFY request. The race condition just moves to a different spot.

            Except there is no race condition.

            This took a little digging, but it’s all there in the specification. In MS-SMB2 v20200826 §3.3.5.19 ‘Receiving an SMB2 CHANGE_NOTIFY Request’, it is stated:

            The server MUST process a change notification request in the object store as specified by the algorithm in section 3.3.1.3.

            In §3.3.1.3 ‘Algorithm for Change Notifications in an Object Store’, we have:

            The server MUST implement an algorithm that monitors for changes on an object store. The effect of this algorithm MUST be identical to that used to offer the behavior specified in [MS-CIFS] sections 3.2.4.39 and 3.3.5.59.4.

            And in MS-CIFS v20201001 §3.3.5.59.4 ‘Receiving an NT_TRANSACT_NOTIFY_CHANGE Request’ there is this:

            If the client has not issued any NT_TRANSACT_NOTIFY_CHANGE Requests on this FID previously, the server SHOULD allocate an empty change notification buffer and associate it with the open directory. The size of the buffer SHOULD be at least equal to the MaxParameterCount field in the SMB_COM_NT_TRANSACT Request (section 2.2.4.62.1) used to transport the NT_TRANSACT_NOTIFY_CHANGE Request. If the client previously issued an NT_TRANSACT_NOTIFY_CHANGE Request on this FID, the server SHOULD already have a change notification buffer associated with the FID. The change notification buffer is used to collect directory change information in between NT_TRANSACT_NOTIFY_CHANGE (section 2.2.7.4) calls that reference the same FID.

            Emphasis mine. This agrees with how Samba implements it (the fsp structure persists between individual requests). I wouldn’t expect Microsoft to do worse than that by not keeping the promise they made in their own specification.

            Source https://stackoverflow.com/questions/66712960

            QUESTION

            Python list not sorting when called from inside a bash script
            Asked 2021-Mar-19 at 16:30

            I am trying to print a custom help message for a bash script. Inside the script, I call a function that then uses python to parse the script, find the functions and the function help string, and then print them. This all works. But, when I try to sort the list of tuples that contains the function name and help string, the sort seems to be ignored. Similar code works as expected in a pure python environment.

            Edit: Just noticed I tried the sort two different ways. AFAIK either should have sorted the list, but neither worked.

            Edit again: see the accepted answer below for code that actually works. I need to remember to reread my problem code in the morning ;)

            ...

            ANSWER

            Answered 2021-Mar-19 at 16:30

            You need to get all the functions, then sort and print :

            Source https://stackoverflow.com/questions/66709400

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