wt | small language that serves as a sample to parslet

 by   kschiess Ruby Version: Current License: MIT

kandi X-RAY | wt Summary

kandi X-RAY | wt Summary

wt is a Ruby library. wt has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A small language that will eventually compile to C.
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            kandi-support Support

              wt has a low active ecosystem.
              It has 8 star(s) with 1 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              wt has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of wt is current.

            kandi-Quality Quality

              wt has 0 bugs and 0 code smells.

            kandi-Security Security

              wt has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              wt code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              wt is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              wt releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi has reviewed wt and discovered the below as its top functions. This is intended to give you an instant insight into wt implemented functionality, and help decide if they suit your requirements.
            • Creates a new compiler .
            Get all kandi verified functions for this library.

            wt Key Features

            No Key Features are available at this moment for wt.

            wt Examples and Code Snippets

            Construct a Knapsack with the given weights .
            pythondot img1Lines of Code : 56dot img1License : Permissive (MIT License)
            copy iconCopy
            def knapsack_with_example_solution(W: int, wt: list, val: list):
                """
                Solves the integer weights knapsack problem returns one of
                the several possible optimal subsets.
            
                Parameters
                ---------
            
                W: int, the total maximum weight for   
            Construct a solution to the given dp .
            pythondot img2Lines of Code : 29dot img2License : Permissive (MIT License)
            copy iconCopy
            def _construct_solution(dp: list, wt: list, i: int, j: int, optimal_set: set):
                """
                Recursively reconstructs one of the optimal subsets given
                a filled DP table and the vector of weights
            
                Parameters
                ---------
            
                dp: list of list,   
            Create a cluster from a dictionary .
            pythondot img3Lines of Code : 9dot img3License : Permissive (MIT License)
            copy iconCopy
            def get_cluster(nodes):
                """
                Returns cluster
                format cluster:{WT(bitcode):nodes with same WT}
                """
                cluster = {}
                for key, value in nodes.items():
                    cluster.setdefault(key.count("1"), {})[key] = value
                return cluster  

            Community Discussions

            QUESTION

            How can I assign NA?
            Asked 2022-Mar-31 at 16:56

            I use the mtcars dataframe and I use the following code to assign NA to all the values of columns drat and wt <=3.

            ...

            ANSWER

            Answered 2022-Mar-31 at 16:11

            We may use if_any on the columns that are changed to NA to return a logical vector to replace values in 'qsec'

            Source https://stackoverflow.com/questions/71695761

            QUESTION

            Postgres Large table Optimal index selection for Select Query With In Clause
            Asked 2022-Mar-10 at 17:55

            We have a very large table with a total number of rows around ~4 billion and everyday throughput is around ~20-25 million.

            Below is the Sample Table definition.

            ...

            ANSWER

            Answered 2022-Mar-10 at 16:14
            CREATE INDEX table_name_desc_index ON table_name (userid,_date DESC NULLS LAST);
            

            Source https://stackoverflow.com/questions/71424827

            QUESTION

            Manually position legend in Patchwork
            Asked 2022-Mar-08 at 04:58

            I want to position a legend (common to all plots) in a blank space in a patchwork layout. From what I can find online I cannot manually position a legend using legend.position if I also use guides="collect" (but can use left, right etc.).

            I have tried to use l <- get.legend and then + inset_element(l, 0.6, 0.6, 1, 1) however it doesn't understand l. I also tried mixing in + inset_element(gridExtra::tableGrob(l)) without luck.

            My goal is to place the legend in the blank space. My actual patchwork plot is more complicated but has two blank spaces I want the legend to sit in.

            MWE

            ...

            ANSWER

            Answered 2022-Mar-08 at 04:58

            Alter your design object to include a fourth element and use guide_area() to place the guide.

            Source https://stackoverflow.com/questions/71390138

            QUESTION

            Trouble understanding veganCovEllipse covariance ellipse calculation
            Asked 2022-Feb-12 at 07:53

            I'm having issues understanding how the veganCovEllipse() function from the vegan package v 2.5-7 calculates an ellipse.

            ...

            ANSWER

            Answered 2022-Feb-12 at 07:53

            veganCovEllipse is not an exported function. This means that it is not intended for interactive use, but it is a support function only to be called from other functions in vegan. Therefore it is not documented. However, the answer is simple: it can calculate any kind of ellipse depending on the input. In vegan the function is called for instance from ordiellipse and there it can draw standard error ellipses, "confidence" ellipses (standard error multiplied by some value picked from statistical distribution), standard deviation ellipses, standard deviation ellipses multiplied by similar constants as standard errors, or enclosing ellipses that contain all points of a group, depending on the input to the function. In showvarparts function it is just re-used to draw circles. Actually veganCovEllipse does not fit anything: it just calculates the coordinates to draw what you asked it to draw, and your input defines the shape, size, orientation and location of the ellipse coordinates.

            There are other functions in other packages that do the same: return you the points needed to plot an ellipse from your input data. For instance, the standard (recommended) package cluster makes similar calculations in non-exported functions cluster:::ellipsoidPoints with effectively the same mathematics, but in completely different way. This function is non-exported as well, and it is intended to be called from user function cluster::predict.ellipsoid. The vegan implementation is similar as in the ellipse function in the car package, where these calculations are embedded in that function and cannot be called separately from car::ellipse.

            Source https://stackoverflow.com/questions/71072250

            QUESTION

            How to correctly select dependent variable and controls in lm() in R?
            Asked 2022-Jan-30 at 20:48

            I am looking for a way to construct a function that will allow the user, given a data frame, to:

            1. Choose what variable will be the dependent variable;
            2. Choose a certain control (one only variable);
            3. Based on these choices, run several different regressions;

            Ideally, I would like something like this:

            ...

            ANSWER

            Answered 2022-Jan-15 at 00:45

            You should work with string substitution. The snippet below provides a simple overview of how you could adjust your function. It would also be good practice to pass the dataset df as an additional parameter in your function.

            Source https://stackoverflow.com/questions/70763752

            QUESTION

            How to automate legends for a new geom in ggplot2?
            Asked 2022-Jan-30 at 18:08

            I've built this new ggplot2 geom layer I'm calling geom_triangles (see https://github.com/ctesta01/ggtriangles/) that plots isosceles triangles given aesthetics including x, y, z where z is the height of the triangle and the base of the isosceles triangle has midpoint (x,y) on the graph.

            What I want is for the geom_triangles() layer to automatically provide legend components for the height and width of the triangles, but I am not sure how to do that.

            I understand based on this reference that I may need to adjust the draw_key argument in the ggproto StatTriangles object, but I'm not sure how I would do that and can't seem to find examples online of how to do it. I've been looking at the source code in ggplot2 for the draw_key functions, but I'm not sure how I would introduce multiple legend components (one for each of height and width) in a single draw_key argument in the StatTriangles ggproto.

            ...

            ANSWER

            Answered 2022-Jan-30 at 18:08

            I think you might be slightly overcomplicating things. Ideally, you'd just want a single key drawing method for the whole layer. However, because you're using a Stat to do the majority of calculations, this becomes hairy to implement. In my answer, I'm avoiding this.

            Let's say I'd want to use a geom-only implementation of such a layer. I can make the following (simplified) class/constructor pair. Below, I haven't bothered width_scale or height_scale parameters, just for simplicity.

            Class

            Source https://stackoverflow.com/questions/70916440

            QUESTION

            Pivoting to a longer format using pivot_longer
            Asked 2022-Jan-12 at 20:31

            I'm trying to pivot to a longer format using dplyr::pivot_longer, but can't seem to get it to do what I want. I can manage with reshape::melt, but I'd also like to be able to achieve the same using pivot_longer.

            The data I'm trying to reformat is a correlation matrix of the mtcars-dataset:

            ...

            ANSWER

            Answered 2022-Jan-12 at 14:31

            Does this achieve the behavior you need?

            Source https://stackoverflow.com/questions/70683285

            QUESTION

            Avoiding eval-parse or do.call
            Asked 2021-Dec-19 at 23:16

            I am trying to select a theme from ggplot2 based on some string given. For demo purposes, consider the following code:

            ...

            ANSWER

            Answered 2021-Dec-19 at 19:45

            We may use getFunction

            Source https://stackoverflow.com/questions/70414757

            QUESTION

            Running single linear regressions across multiple variables, in groups
            Asked 2021-Dec-12 at 22:18

            I'm trying to run a simple single linear regression over a large number of variables, grouped according to another variable. Using the mtcars dataset as an example, I'd like to run a separate linear regression between mpg and each other variable (mpg ~ disp, mpg ~ hp, etc.), grouped by another variable (for example, cyl).

            Running lm over each variable independently can easily be done using purrr::map (modified from this great tutorial - https://sebastiansauer.github.io/EDIT-multiple_lm_purrr_EDIT/):

            ...

            ANSWER

            Answered 2021-Dec-12 at 22:18

            IIUC, you can use group_by and group_modify, with a map inside that iterates over predictors.

            If you can isolate your predictor variables in advance, it'll make it easier, as with ivs in this solution.

            Source https://stackoverflow.com/questions/70327540

            QUESTION

            Relabelling predictors with jtools effect_plot in R
            Asked 2021-Nov-29 at 21:15

            I'm trying to edit the names of the factor levels of a predictor variable in R for an effect plot with the jtools package. I should be able to do this with the "pred.labels" argument, but the labels don't change. For example, using the mtcars data set I try to write out the predictor names ("four", "six", "eight") but there is no change in the figure.

            ...

            ANSWER

            Answered 2021-Nov-29 at 21:04

            Since jtools seems to use ggplot2 you can just change the labels like you would if you were using ggplot2

            Source https://stackoverflow.com/questions/70160886

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install wt

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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