rfm | FileMaker to Ruby adapter

by lardawge Ruby Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | rfm Summary

rfm is a Ruby library. rfm has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

This library is no longer maintained. It is known to work up to Filemaker version 14. Beyond that there is no guarantee. There is currently a maintained fork that goes under a different gem name here:

Support

Quality

Security

License

Reuse

Support

rfm has a low active ecosystem.

It has 55 star(s) with 41 fork(s). There are 9 watchers for this library.

It had no major release in the last 6 months.

rfm has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of rfm is current.

Quality

rfm has no bugs reported.

Security

rfm has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

rfm is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

rfm releases are not available. You will need to build from source code and install.

Top functions reviewed by kandi - BETA

kandi has reviewed rfm and discovered the below as its top functions. This is intended to give you an instant insight into rfm implemented functionality, and help decide if they suit your requirements.

Expands the given arguments into a hash .
Find the record by id
Fetch the raw data from a URL
Parse the HTTP request .
Parses all fields related to the server
Read a single attribute from the attributes hash
convert date format
Builds a message .
Find records by id
Returns the port for the given port .

Get all kandi verified functions for this library.

rfm Key Features

No Key Features are available at this moment for rfm.

rfm Examples and Code Snippets

No Code Snippets are available at this moment for rfm.

Community Discussions

Trending Discussions on rfm

VLOOKUP TRUE ISSUE

Write way to calculate weighted average with pandas Dataframe with mean or directly multiply

Pandas How to replace values based on Conditions for Several Values

Selecting variables for random forest

Poor Accuracy Prediction with random forest in R

Variable lengths differ with random forest

Want to create a function with def, but ValueError returned

How to get a calculated scalar out of a dataframe

How to sum different categorical data of a data frame into different column

Matplotlib add color legend with value based on another variable

QUESTION

VLOOKUP TRUE ISSUE

Asked 2021-May-19 at 06:14

I am building an RFM table in excel, and want to lookup against a score table I created. Using row 3 as an example in the pic below, when I use the vlookup true function which is supposed to return a close match from the recency rankings table the vlookup is pulling in a 5 in column F, instead of a 1. I am not looking to do an exact match as that is not how this analysis is structured.

Any thoughts on why the true statement in the vlookup is not returning correct values? Any thoughts on how to fix would be appreciated.
enter image description here

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ANSWER

Answered 2021-May-19 at 06:14

When you use TRUE as the final parameter in VLOOKUP (for "approximate match"), Excel (for whatever reason) stipulates that the corresponding values in the first column of the lookup range must be in ascending order. The prompt as you're typing the formula notes this

Therefore, re-order your lookup table and then the VLOOKUP values should populate as you expect them to

Source https://stackoverflow.com/questions/67597780

QUESTION

Write way to calculate weighted average with pandas Dataframe with mean or directly multiply

Asked 2021-Apr-26 at 16:55

I have the following pandas Dataframe:

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ANSWER

Answered 2021-Apr-26 at 16:55

Prepare data:

Source https://stackoverflow.com/questions/67268752

QUESTION

Pandas How to replace values based on Conditions for Several Values

Asked 2021-Apr-26 at 15:45

I have a Dataframe with several column and below is first 3 columns in that dataframe:

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ANSWER

Answered 2021-Apr-26 at 15:37

Create a dict for mapping -

Source https://stackoverflow.com/questions/67269564

QUESTION

Selecting variables for random forest

Asked 2021-Apr-20 at 16:39

I made a representation of a random forest tree in reprtree but I have too much nodes I think:

The line I wrote : RFM = randomForest(Rating ~., data = training)

I would like to take off some variables which are not relevant, but everything I write does not work; I tried :

RFM = randomForest(Customer_type, Rating, cogs, data = training) to have only those three variables but I still have an error.

Do you know how could I 'select' my variables in the dataframe without writing Rating ~. formula? I tried to change ntree but I still have too much nodes.

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ANSWER

Answered 2021-Apr-16 at 09:30

randomForest accepts a formula object. Try :

Source https://stackoverflow.com/questions/67122444

QUESTION

Poor Accuracy Prediction with random forest in R

Asked 2021-Apr-18 at 10:45

I'm a newbie in R, I'm trying to predict a Customer Type (member or normal customer in the store) in relation to different variables (Gender, total spent, rating, ...) with 1000 customers information in my dataframe. I created an algorithm with a random forest but the accuracy is around 49% (OOB error rate). I tried to use Importance(RFM) in order to get higher accuracy by not including not relevant variables but I end up with around a 51% accuracy... Does it mean there is no connection between all the features or is there a way to tune it to get higher accuracy ? Thank you so much.

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ANSWER

Answered 2021-Apr-18 at 10:45

Without your data or a reproducible example, it is hard to really improve your model. I can suggest to you some procedures and packages that can help you a lot in this kind of task. Have a look at the caret package, which is designed precisely for model tuning. The package is really well documented with lots of useful examples. Here I can show the general workflow to work with caret:

Source https://stackoverflow.com/questions/67139600

QUESTION

Variable lengths differ with random forest

Asked 2021-Apr-14 at 18:23

I'm really new to R and I want to make a random forest. However I keep getting the same error-

Error in model.frame.default, lengths of variables differ.

I know this issue has been solved in another topic by constructing a formula from strings with as. formula but I have really no idea how to do it. Can you help me please? Thank you.

...

ANSWER

Answered 2021-Apr-14 at 18:23

Well what your error is, is that your independent variable is Rating from the df dataframe, but you selected data = training. This means that your random forest should take data from 2 different dataframes, which isn't possible. I guess that randomForest(Rating ~ Customer_type, data = training) would work.

Source https://stackoverflow.com/questions/67096865

QUESTION

Want to create a function with def, but ValueError returned

Asked 2021-Apr-13 at 06:15

What I wanna do

I want to do RFM analytics for purchase data of a e-commerce site.

I processed the data into RFM format, so I want to rank every ID depending on the values of each column (Money, Recency and Frequency).

However, I got the error message as below.

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ANSWER

Answered 2021-Apr-13 at 06:15

If working with scalars use and instead & with remove last level of MultiIndex by MultiIndex.droplevel.

So use:

Source https://stackoverflow.com/questions/67069271

QUESTION

How to get a calculated scalar out of a dataframe

Asked 2021-Mar-24 at 16:13

I have a dataframe as shown below. I want to group and return the count of Campeão registers, so that I can have this scalar into a output text for users.

I'm using this code to display a table with each correspondent value

a = df['Macro RFM'].value_counts().reset_index()

st.dataframe(a)

How can I get the result for each class (Macro RFM)? I mean, I want to output something like that: st.write(f'We got {X} champions')

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ANSWER

Answered 2021-Mar-24 at 16:13

What about:

Source https://stackoverflow.com/questions/66784299

QUESTION

How to sum different categorical data of a data frame into different column

Asked 2021-Mar-22 at 16:19

I want to add "R", "F" and "M" into a single column. suppose if any record has R = 1, F = 1 and M = 1 then I want 3. But when I am doing

...

ANSWER

Answered 2021-Mar-22 at 16:08

What about this:

Source https://stackoverflow.com/questions/66749672

QUESTION

Matplotlib add color legend with value based on another variable

Asked 2020-Nov-20 at 11:23

I want to add color legend like this:

...

ANSWER

Answered 2020-Nov-20 at 11:23

Seaborn's scatterplot would automatically create a legend. The hue= tells which column to use for coloring, the palette= parameter tells the colors to use (either a list or a colormap). For non-numeric data, hue_order= can fix a certain ordering.

Here is an example with toy data:

Source https://stackoverflow.com/questions/64927737

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install rfm

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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