kandi X-RAY | lis Summary
kandi X-RAY | lis Summary
A simple interface to medical laboratory instruments. It implements a rough subset of ASTM E1394-97 (or, possibly CLSI LIS02-A2). It listens for test requests and results and forwards them via HTTP. It is intended to interface with the worklist_manager web application. Developed for and tested with DPC Immulite I2500 (user manual) using the LIS specification version 600129-H (not available online, but a similar version might be available).
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Top functions reviewed by kandi - BETA
- Defines a method for the field in a name .
- send messages to the patient
- Get the attributes of a specific record .
- End the current process .
- Parses the specified string .
- Gets the class for the given type
- Handles the incoming message received .
- string representation of a message
- Called when the request is received .
- Called when the message is received
lis Key Features
lis Examples and Code Snippets
Lines of Code : 32License : Permissive (MIT License)
Copyprivate static int LIS(int[] array) {
int N = array.length;
if (N == 0) {
return 0;
}
int[] tail = new int[N];
// always points empty slot in tail
int length = 1;
tail[0] = array[ public int lengthOfLIS(int[] nums) {
if(nums == null || nums.length < 1) {
return 0;
}
int[] dp = new int[nums.length];
dp[0] = 1;
int max = 1;
for(int i = 1; i < dp.length; static int liss(int a[],int n)
{
int lis[n];
int i,j,max = 0;
for ( i = 0; i < n; i++ )
lis[i] = 1;
for ( i = 1; i < n; i++ )
for ( j = 0; j < i; j++ )
if ( a[i] > a[j] && lis[i] < lis[j] + 1)
Community Discussions
Trending Discussions on lis
QUESTION
In short, this is the plan: I want to remove the smallest value from a Python list. My approach to that was creating a new list trimmed , which is basically a copy of the original one but with a condition like:
add it to trimmed only if the value is not equal to min(). Like this:
...ANSWER
Answered 2021-Jun-14 at 20:18It's because your if i != min(lis) checks the minimum value against the index variable i instead of the value itself x. enumerate gives back (index, val) pairs i.e, (i, x) here. It happened that min(lis) was 2, so whenever i hits 2, that value will be trimmed, hence you saw 6 disappearing (which was at 2nd index). Fix is to compare against x:
QUESTION
I know that it is possible to modify a list inside a function by using assignment as followslis[:] = new_list, however the question is, is it possible to modify a deque inside a function as it is also an iterable?
Of course without using return inside the function.
It not possible to use 'deq[:] = new_deq ' as it gives the following error: TypeError: sequence index must be integer, not 'slice'
ANSWER
Answered 2021-Jun-10 at 21:47deque does not support a slice as an index, so to achieve the effect of lis[:] = new_list with a deque, you can clear it first before extending it:
QUESTION
The project: for a list of meta-data of wordpress-plugins: - approx 50 plugins are of interest! but the challenge is: i want to fetch meta-data of all the existing plugins. What i subsequently want to filter out after the fetch is - those plugins that have the newest timestamp - that are updated (most) recently. It is all aobut acutality... so the base-url to start is this:
...ANSWER
Answered 2021-Jun-09 at 20:19The page is rather well organized so scraping it should be pretty straight forward. All you need to do is get the plugin card and then simply extract the necessary parts.
Here's my take on it.
QUESTION
I cut each string in my list in half. I would like to print each half separately, however, when I go to print the first half of the string "have" which is "ha," it prints every first letter in each of my halves. Does anyone know the reason for this?
...ANSWER
Answered 2021-Jun-12 at 15:38first[0] will print the first letter in the first half of your string.
So if you have have and you cut this in half first = ha-second = ve.
first[0] will give you h. So I assume you want to print ha - ve
QUESTION
I am using a code written by Victor Velasquez to extract data from raster files which contain dayly precipitation data since 1981. When I run the code, I get this error that some index is out of bounds. I did a little research and found that this is common and there are a lot of similar questions here, but I haven´t been able to find the specific solution for this case.
The error:
...ANSWER
Answered 2021-Jun-09 at 13:29It looks like the file you are reading does not contain the geospatial point you are trying to find data for. (If this is incorrect please let me know).
You can add a statement to catch if a point is contained in the data:
QUESTION
I want to create code for finding LIS. My code doesn't work very well. For example if the input is '(1 3 5 10 9 6 7), output should be '(1 3 5 6 7) but my program return '(1 3 5 10). What am I doing wrong? Have I code binary tree and then find the higher height? Or can I code this program in easiest way?
...ANSWER
Answered 2021-Jun-08 at 21:38Before we begin, a question. Do you consider '(1 1) to be an increasing sequence? For now, I will assume you do not.
First, note that we can simplify find-longest as follows:
QUESTION
I would like to threshold an image, but instead of the output being black and white I would like it to be white and some other color. I was able to achieve this using a nested for-loop however this is slow and I was wondering if anyone knows any method of doing this efficiently using CV2 functionality.
...ANSWER
Answered 2021-Jun-03 at 13:10So the green channel is always 255 and the red and blue channels are just the threshold values?
So you are looking at something like this
QUESTION
I have big dataset with the following format:
...ANSWER
Answered 2021-Jun-03 at 03:40You can try the following code -
QUESTION
I'm going through an exercise to grab the 'leaves' of a nested list in scheme (from SICP). Here is the exercise input-output:
...ANSWER
Answered 2021-May-31 at 13:17The reason there are three cases is that you are importing some scalar / vector distinction from some other language: Scheme doesn't have it and it is not helpful. Instead a list is a recursively-defined object: a list is either the empty list, or it is a pair of something and a list. That means there are two distinctions to make, not one: is an object a pair, and is an object the empty list:
QUESTION
I need some guidance on below use case. I have one stack that has 30 aws target groups to create. So I am using a module with for_each with diff paramters and creating 30 Target groups. Now Later I need to create 30 listener forwarding rules where I have to pass output of above target group's arn. I am getting error that string required. I am sure output is a string and it works when I call module multiple time without for_each.
...ANSWER
Answered 2021-May-30 at 11:05You missed referencing individual keys in the map instead you referenced map all together for both tg_arn & forwarding_path.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install lis
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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