risp | LISP interpreter in Ruby with macros and interop | Transpiler library
kandi X-RAY | risp Summary
kandi X-RAY | risp Summary
Risp is a LISP implementation written in Ruby. The syntax is reminescent of Clojure, and it interoperates with Ruby.
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- Initialize the name .
- Evaluates the code .
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Community Discussions
Trending Discussions on risp
QUESTION
I do a POST api request to /api/mycode.js where inside I'm tryin to:
- do an external API call (using body.value)
- save to db if response is ok
- res.send either "ok", "error", etc back to the original POST request, where I handle it based on the string
I tried using an async function
inside the .then
but it doesn't seem to work, this is mycode.js:
ANSWER
Answered 2021-Feb-23 at 21:12You need to call it via await saveToDb()
or saveToDb().then()
and not just saveToDb()
because this is async
declared function that in case of just calling returns Promise
that should be await
ed.
Also instead of using fetch().then()
you can use await fetch()
in try...catch
block that will make code more clear.
QUESTION
I'm trying to connect to CheckPoint APIs with some c# code, i type in all the data(username and password in json format and compile the Uri) and when i do the call it just ends the execution without exceptions
Here's the code
...ANSWER
Answered 2021-Jan-18 at 17:07I would suggest using Newtonsoft.Json to serialize your strings data into a JSON correctly, it's 100% better. About the premature end, I think the method that is calling the 'CPAPICall' is not doing it in an asynchronous way, so check if this method was created asynchronously and have the await operator before the 'CPAPICall' on the same line.
QUESTION
i'm new at coding, I would like an example on how could I make transform these lines to one or more functions... I'm doing my first experiment with Constructor, and I think these lines shouldn't be in my Main(?). Thank you!
...ANSWER
Answered 2020-May-18 at 20:25You can make a function to take an object of your class and return it after filling it with user-given information like this:
QUESTION
I'm new to structs. I'm making a program in which I wanna build a list of players with structs . This is what I wrote 'til now. It's in Italian. But basically the program works fine when I insert just one player. It doesn't when I want to add more than one.
...ANSWER
Answered 2019-Dec-20 at 18:00I checked your code and i found some issues, when you use scanf()
this function read every character from the input until it found a white-space but doesn't read the line-break, so, you need to clean the input or just put a white-space before the formatting string: scanf(" %d", &somVariable);
. You need to assign memory to the structure role
which is inside of the structure player
, so in your function define_role
there won't a segmentation fault, also you need to add a value to your ```cont``variable. I put the code with this corrections and i added a while to add more players.
EDITED
I read your comment, i didn't notice that make_pl(&giocatore[cont-1]);
you treat gicatore
as an array but it's a pointer of player structure, so when you try to add a second player the program ends with an error. So the solution is create an array, or a linked list, to save the player that you add. The main problem with the array is that you can add only a specific number of players if you try to pass that limit the program will end with an error, so i recommend you use a linked list.
I set scanf("%d",&ruolo->lato[index])
in 0 because lato is an array of one int in your struct role, you could declare a int instead an array of only one int, so to acces the first element of an array you need to set the index in 0, if you write, for example, 120 this number it will save in lato[0]
QUESTION
I am programming a client/server application where the client, simply sends a string to the server and the server resends the same one. I run all like this: ./server localhost 8000 ./client localhost 8000 StringToSend
Server.c
...ANSWER
Answered 2019-Nov-26 at 18:02You have to revise the memory allocation/read/write
Current code assume maximum buffer size of 100 character. Then issue a read for the size of the pointer (4 or 8 bytes). Then it write, unconditionally, 4 or 8 bytes to the client back.
QUESTION
The intent is to put the cursor at some position on the screen (around the center of the screen), enter some initial text, and prompt the user to enter more text to be saved in a variable, while leaving him the normal readline
line editing capabilities.
My initial attemp was to:
- center the cursor vertically
echo
/printf
ing some whitespace, - center the cursor horizontally again through
echo
/printf
, - issue
read -i "editable pre-text" -e answer
.
However I noticed the behavior described below, and crafted the following exemplifying two lines-code to demonstrate it.
When executing the following script
...ANSWER
Answered 2019-Oct-13 at 07:00As mentioned in a comment, you should use read
's -p
option to print the prompt, rather than trying to set it up before the read
command.
The -e
option asks read
to use the readline
library to handle the input, allowing a wider range of line-editing characters. However, in order to implement these behaviours, readline
needs to be able to redraw the current line, and that's not possible if there is anything on the current line when the read starts. It's not possible because Unix provides no mechanism for an application to look at what's being displayed on the console. So under some circumstances, readline
will simply clear the line. Using the -p
option allows readline
to output the prompt, and it can then know what the line currently looks like.
QUESTION
I was trying to do some homework to keep up during holidays and i got stuck in this error
I've tried to compile both with GDB and Dev-C++ but neither of those could do that for different reasons
...ANSWER
Answered 2019-Aug-08 at 11:16You open the file but do not save the file pointer. So you end up writing into an uninitialized file descriptor. Nice way to generate unique crashes! It should be:
QUESTION
I just want to retrieve data from an external API and then show this data. The problem I think is the fact that I get this data "too late", I mean in my code I try to visualize this data before those data are ready. This is probably due to the fact that HttpClient.get() is asynchronous.
1) Service:
...ANSWER
Answered 2019-Apr-25 at 23:29Change this
QUESTION
I started learning programming a few days ago, and here i am with my first problems. I'm learning something about batch, but there is something in my code that is wrong, can you help me with this?
Specifically, the "goto" command it's not a go to. i've tried to put it in a single line, but it's like the goto doesn't exist. how can i fix it?
...ANSWER
Answered 2019-Jan-05 at 10:02Without more information I think your problem are not goto
commands but if
conditionals
Suppose the user types pikachu
on the first prompt. When the first if
is reached the batch's parser will replace the variable read operation %risp%
with the value inside the variable. So, your line
QUESTION
I have text value as below, i need to find all the value between opening (
just before array['nosql']
and its corresponding closing parenthesis. There could be space or no space between (
and array['nosql']
Entire Text
...ANSWER
Answered 2018-Jul-13 at 11:50You can use the following regular expression to extract the data of interest:
(?<=\s(?=\(\sarray\['nosql'\]))([\s\w\['\]\s<@(.]*\)\))
(?<=\s(?=\(\sarray\['nosql'\]))
. Lookbehind to find whitespace that is followed by opening bracket andarray['nosql']
.([\s\w\['\]\s<@(.]*\)\))
Character class to match whitespace\s
, alphanumerical values\w
, square brackets[
and]
, characters<
,@
and)
. Finally, match the final two closing brackets))
.
You can test it live here.
Python snippet:
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Install risp
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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