mutant | Automated code reviews via mutation testing - semantic code | Code Analyzer library
kandi X-RAY | mutant Summary
kandi X-RAY | mutant Summary
An automated code review tool, with a side effect of producing semantic code coverage metrics. Think of mutant as an expert developer that simplifies your code while making sure that all tests pass. That developer never has a bad day and is always ready to jump on your PR.
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Top functions reviewed by kandi - BETA
- Invokes the procedure .
- Returns a hash with the given options .
- Validates that the block is valid .
- Evaluate instance variables .
- Create a new instance
- Call the given block once .
- Creates a new File .
- Return a new environment
- Returns a quantifier instance
- Returns all the expressions of this expression .
mutant Key Features
mutant Examples and Code Snippets
Community Discussions
Trending Discussions on mutant
QUESTION
I have function defined as:
- For x < 0 function returns 0
- For x >= 0 function returns x
I implemented it as
...ANSWER
Answered 2022-Mar-23 at 16:07On the face of it this is a classic equivalent mutant. However, your if statement can be replaced with
QUESTION
theurl <- "https://cryptoslam.io/#sales-rankings-24h"
url <- curl(theurl, "rb")
urldata <- readLines(url, warn=FALSE)
data <- readHTMLTable(urldata, stringAsFactors = FALSE)
close(url)
data.2 <- data.frame(Reduce(rbind, data[1]))
data.3 <- data.2 %>% dplyr::select(Collection, Sales, Change..24h.) %>%
head(10) %>% mutate(Sales.numeric = as.numeric(gsub('[$,]', '', Sales)))
...ANSWER
Answered 2022-Mar-20 at 07:34One way to solve this is by getting names from the website,
QUESTION
I want to subset the res.gs
dataframe to keep only samples that are mutated. The sample is identified as "mutated" if the first letter in the n_mutated_group1
column is not zero. I then want to create another dataframe as wt.samp
, which retains samples that are not mutated.
ANSWER
Answered 2022-Mar-18 at 09:32One way of doing this is with filter
from dplyr
. You also need to use substr
to identify the first character of a column.
QUESTION
Samples are either wild-type or mutant. I want to find the number of samples that are wild-type wt
versus mutant mut
with respect to the respondents Responder
in the Group1
column of the res.sig
dataframe. In the n_mutated_group1
column, the first letter indicates the number of mutant and the last two digits (after or
) indicates the total number for that group. wt
is the difference between total
and mut
.
ANSWER
Answered 2022-Mar-16 at 07:53You can extract for total
everything after the of
string in your column and for mut
you can extract everything before of
. You can use this code:
QUESTION
The instructions for setting up an Angular application project are straightforward. I have had no issue with setting up and running Stryker on an application project using default settings for Karma. I am having trouble getting it to work correctly when it is a Library project instead, however.
I have looked through the configuration documentation for Stryker and I have tried adjusting the paths to the relevant files (for mutation and the karma.config)
stryker.conf.json
...ANSWER
Answered 2022-Feb-18 at 18:19With help from nicojs, I was able to get basic Stryker functionality working on my library project.
As it turns out I was missing some critical configuration.
I was able to set the testRunner as karma. I added karma.ngConfig.testArguments.project and disableTypeChecks values in stryker.conf.json
QUESTION
I am in need of assistance with my program. I have to code a three-round word scramble program using 10 keywords that will appear scrambled to the user for them to guess it. My problem is that after one word the code just simply exits the loop. My intention is for the loop to be used again for a second and third time before exiting.
Here is the code:
...ANSWER
Answered 2022-Jan-22 at 04:53#include
#include
#include
#include
using namespace std;
int main() {
while (true) {
enum fields { KEY, HINT, Locked };
const int NUM_WORDS = 10;
const string WORDS[NUM_WORDS][Locked] = {
{"MITCHELL", "NICKNAME IS MITCH,SO WHAT IS MY NAME?"},
{"PIZZA", "MY FAVORITE FOOD, IS ITALY."},
{"ROYCE", "SOME TUMBLE AND SOME ROLLS...?"},
{"INFINITY", "THE IMAGINARY NUMBER IS?"},
{"AMY", "FAVORITE SONIC CHARACTER IS ?"},
{"FIAT", "CRYPTO OVER; THIS TYPE OF CURRENCY?"},
{"RUSSIA", "SAINT PETERSBURG IS IN ?"},
{"DONETELLO", "TEENAGE MUTANT NINJA TURTLES"},
{"SON", "BROOKLYN PEOPLE SAY THIS WORD"},
{"FUN", "FEELING HAPPY"}
};
srand(static_cast(time(0)));
int choice = (rand() % NUM_WORDS);
string theWord = WORDS[choice][KEY]; // GUESSING THE WORDS
string theHint = WORDS[choice][HINT]; // Hint for Words
// Randomizing using the string; swapping charcters equal to the length of the words
string Jumble = theWord; // jumbled version of word
int length = Jumble.size();
for (int i = 0; i < length; ++i) {
int index1 = (rand() % length); // Random
int index2 = (rand() % length); // Random
char temp = Jumble[index1];
Jumble[index1] = Jumble[index2]; // Swapping charcters
Jumble[index2] = temp;
}
cout << "\t\t\Welcome to Word Jumble!\n\n"; // USING CARRIAGE RETURN; USING TITLE
cout << "Unscramble the letters to make a word.\n";
cout << "Enter 'hint' for a hint.\n";
cout << "Enter 'quit' to quit the game.\n\n";
cout << "The jumble is:" << Jumble;
string guess;
cout << "\n\nYour guess:";
cin >> guess;
while ((guess != theWord) && (guess != "quit")) {
if (guess == "hint") {
cout << theHint;
}
else {
cout << "Sorry, that's not it.";
}
cout << "\n\nYour guess:";
cin >> guess;
}
if (guess == theWord) {
cout << "\nTHat's it! You guessed it!\n";
}
cout << "\nThanks for playing.\n";
}
return 0;
}
QUESTION
I am trying to fetch different collection stats and iterate through them using a for loop to designate which collection I want to retrieve. I want to push each collection into another array and return that array of collections.
...ANSWER
Answered 2021-Dec-30 at 14:57Map the collection returning promises for Promise.all
to execute.
QUESTION
I have a scenario in which I have a peptide frame having 9 AA. I want to generate all possible peptides by replacing a maximum of 3 AA on this frame ie by replacing only 1 or 2 or 3 AA.
The frame is CKASGFTFS and I want to see all the mutants by replacing a maximum of 3 AA from the pool of 20 AA.
we have a pool of 20 different AA (A,R,N,D,E,G,C,Q,H,I,L,K,M,F,P,S,T,W,Y,V).
I am new to coding so Can someone help me out with how to code for this in Python or Biopython.
output is supposed to be a list of unique sequences like below:
CKASGFTFT, CTTSGFTFS, CTASGKTFS, CTASAFTWS, CTRSGFTFS, CKASEFTFS ....so on so forth getting 1, 2, or 3 substitutions from the pool of AA without changing the existing frame.
...ANSWER
Answered 2021-Dec-01 at 07:07Ok, so after my code finished, I worked the calculations backwards,
Case1, is 9c1 x 19 = 171
Case2, is 9c2 x 19 x 19 = 12,996
Case3, is 9c3 x 19 x 19 x 19 = 576,156
That's a total of 589,323 combinations.
Here is the code for all 3 cases, you can run them sequentially.
You also requested to join the array into a single string, I have updated my code to reflect that.
QUESTION
I am currently working with a large dataset I retrieved from the crossref API in which I retrieved information on scientific papers based on a DOI search.
Currently the large list contains of ~3500 elements. Each of these elements is a list of their own consisting of the metadata 'meta', the actual relevant data 'data' and an irrelevant list 'facets'.
This is an example of two of the lists based on two DOI's:
...ANSWER
Answered 2021-Oct-25 at 16:55Like this? Note - it is better to include a Minimal reprex that includes a toy data set, rather than a snapshot of what you have. This way the question will likely get answers faster.
QUESTION
I have created a mutate_v1 function that generates random mutations in a DNA sequence.
...ANSWER
Answered 2021-Oct-15 at 17:22Use range to iterate up to the number of generations, and store each generation in a list, each generation is the result of mutating the previous one:
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On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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