bishop | A bayesian classifier library for Ruby
kandi X-RAY | bishop Summary
kandi X-RAY | bishop Summary
A bayesian classifier library for Ruby
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Top functions reviewed by kandi - BETA
- Builds a hash from the cache .
- Limit the number of tokens
- Guess probability .
- Merges one or more pools .
- Loads data .
- Initialize a new instance .
- Unmask the data of the pool .
- Track the number of tokens
- Load data from the YAML file
- Rename an existing pool
bishop Key Features
bishop Examples and Code Snippets
Community Discussions
Trending Discussions on bishop
QUESTION
I wanted to create a chess program using OOP. So I made a superclass Pieces
, a subclass Bishop
, and a UI class GameUI
. I created a canvas in the class GameUI. I wanted, that when I instantiate an object bishop in the class GameUI
, it shows an Image from a bishop, on the canvas.
The problem is, when I instantiate the Bishop
, I don't see any image. So I tried to do the same with a text : instead of using the method create_image from the class Canvas
, I used the method create_text, and it worked : I saw a text on the canvas. That means, the problem comes from the method create_image
, and I don't understand it.
If I create an Image directly in the class GameUi
, it works! but that's not what I want...
So I don't have any error message. I see the canvas (with a blue background), but no image on it.
Here's the code :
...ANSWER
Answered 2021-Jun-08 at 08:56To make your code work, I decided to sort of rewrite it based on this answer. It works now, but really the only thing that you needed to add was self.icon
instead of icon
. icon
gets garbage collected since there is no further reference to it, while self.icon
remains. Also, it's not entirely the same as yours was, so it probably needs a bit of rewriting too.
QUESTION
I need to do a match and join on two data frames if the string from two columns of one data frame are contained in the string of a column from a second data frame.
Example dataframe:
...ANSWER
Answered 2021-Jun-07 at 14:20The documentation says that match_fun
should be a "Vectorized function given two columns, returning TRUE
or FALSE
as to whether they are a match." It's not TRUE or FALSE, it's a function that returns TRUE
or FALSE
. If we switch your order, we can use stringr::str_detect
, which does return TRUE
or FALSE
as required.
QUESTION
I'm making a chess game. I've created a main file with the Tkinter code in a class "Window". In this class, I created a canvas. Then I've created a second file with the name "pieces", where I put the behaviour of the different pieces. In this one, I have a superclass "Pieces", and a subclass "Bishop" (because I haven't created the classes for the other pieces yet)
What I tried first to do, is to create a bishop's icon in the constructor of the class "Bishop". My class "Bishop" has the argument "color", so that, when we create an object "Bishop", we can choose if he's black or white. So I wrote :
...ANSWER
Answered 2021-May-24 at 16:18If you are familiar with Model/View approach of writing code, it will help you find your way around tkinter
applications. In such a case you would place all the code relating to views in one class and all the data is managed in the Model class(es).
In your case, you could start with the structure illustrated below and grow from it:
QUESTION
Given a infinite grid , we need to find out the minimum cost required to reach a destination from given source. Cost is calculated as below. Only diagonal movements are allowed. The cost is incremented only when direction is changed .Similar to Bishop move in chess. you can move as many cells in the same diagonal as you want that will not have any additional cost. if source is (1,1) and destination is (3,3) the cost is 1.
Can someone help me with efficient algorithm to achieve this.
...ANSWER
Answered 2021-May-20 at 13:38You can get from anywhere to anywhere with no more than 1 change in direction. so if source and destination are on same diagonal, cost is zero. Otherwise cost is 1.
To find the actual path:
QUESTION
I want to create a web app chess game, so every piece will have an event listener to wait until a player clicks on it. When a player clicks on a piece (for now I'm only working with pawns) it's id will be saved and printed out, and only after this all squares should wait for a click (I'm not working with valid squares, can be any square); and if a square is clicked, it's id should be saved and printed out.
But on console, when I click a pawn, it's id is printed twice, one time for the normal print, but another time for the square print (So it took square's print). So instead of the programm to wait to call the function that prints the square id after clicking the piece, the programm prints the piece id in the place of the square id. So I think the programm is not waiting until the first function is finished:
...ANSWER
Answered 2021-May-14 at 10:04So I think the programm is not waiting until the first function is finished
That's not what's happening. A non-async
JavaScript function always runs to completion (unless the entire environment is terminated, like closing a web page).
The click event propagates ("bubbles") from child elements to their parent element to its parent element, etc. Since your pawns are child elements of the squares, after handling the click event on the pawn, the click event bubbles to the square and gets handled there.
There are a couple of things you'll need to do:
Prevent the event from bubbling by using
event.stopPropagation();
on theevent
object in$$pawn_clicked
Have variables storing state information for your program so it knows whether it's expecting to get a click on a square. I think that you already have that in the
$piece
variable. So your click handler for squares should only do something when$piece
is not the "no piece" value (looks like you're usingundefined
for that).
QUESTION
So I have the following in cityzone.txt:
...ANSWER
Answered 2021-May-08 at 04:14You can do :
QUESTION
I wanted to create a dictionary of values called pieces,
the key of the given dictionary had to be the name of the piece and the item it's Unicode charachter representation.
I decided to write a list comprehension to retrieve the Unicode charachters and a list with all the names that I needed.
...ANSWER
Answered 2021-Apr-29 at 14:16A dict
can only have unique keys. If you give it the same key more than once - it'd only "remember" the last value. Previous values would be overwritten.
It is worth mentioning that zip
will get a length checking flag on Python 3.10 (https://www.python.org/dev/peps/pep-0618/) , which will enable raising an error when lists given to zip
- are of different sizes. I guess it can help sanity checking such cases.
QUESTION
I have a class that creates instances of another class. Occasionally it needs to react to or otherwise work with its products. However, it could create trouble if it were to be passed a product that it doesn't own. I have the following solution:
...ANSWER
Answered 2021-Apr-26 at 02:15If you're willing to take the 'globally incremented ID' approach, what you want is an Id
type with an interface like this that you can store in your Parent
and Child
types:
QUESTION
I've finished my chess game, but now I'm implementing a numpy array as the board so the chess AI I'm working on calculates faster. I know what a KeyError is, but I don't understand why its happening here. Error:
...ANSWER
Answered 2021-Apr-25 at 13:58board
contains the numbers from 0 to 12, but the IMAGES
dictionary uses the string keys "--", "bR", "bN". Hence, you cannot address the images in the IMAGES
dictionary directly with the numbers stored in board
:
Use the lookup
table to create the IAMGES
dictionary:
IMAGES[piece] = p.transform.scale(p.image.load("images/" + piece + ".png"), (SQ_SIZE, SQ_SIZE))
QUESTION
I am trying to program a chess computer. I am having a weird problem with a dictionary here. As you can see in the code below, I am only editing the pieces attribute of the Player object saved at 'w' in my dictionary self.players
. However, when I run the code, for both Player objects created (Player('w')
and Player('b')
), the d[(1,1)].piece
object appears in their respective Player.pieces['R']
. How can this be?
(In the code, only the class Board
should be really important however I included the other classes so the code works).
ANSWER
Answered 2021-Apr-23 at 21:03Your problem is on this line:
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On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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