fixpoints | Fixpoints | Storage library

by motine Ruby Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(4)Vulnerabilities Install Support

kandi X-RAY | fixpoints Summary

fixpoints is a Ruby library typically used in Storage, Angular applications. fixpoints has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Fixpoints enables saving, restoring and comparing the database state before & after tests.

Support

Quality

Security

License

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Support

fixpoints has a low active ecosystem.

It has 4 star(s) with 2 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 1 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of fixpoints is current.

Quality

fixpoints has no bugs reported.

Security

fixpoints has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

fixpoints is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

fixpoints releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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fixpoints Key Features

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fixpoints Examples and Code Snippets

No Code Snippets are available at this moment for fixpoints.

Community Discussions

Trending Discussions on fixpoints

Complexity of computing Fibonacci sequence as a fixpoint

Counting Number of Pairs within a String Variable

Modify multi-level dictionaries

Extensionally equal predicates and equality of universally quantified applications

QUESTION

Complexity of computing Fibonacci sequence as a fixpoint

Asked 2020-Jul-04 at 19:11

I have realised that the following program

...

ANSWER

Answered 2020-Jul-04 at 19:11

The key idea is to share work. In the naive version, fib (n-2) is computed twice from scratch (fib n = fib (n-1) + fib (n-2) = fib (n-2) + fib (n-2) + fib (n-3)). In the list version, the argument xs represents the recursive call, which is evaluated once, and used twice.

Source https://stackoverflow.com/questions/62715399

QUESTION

Counting Number of Pairs within a String Variable

Asked 2020-Feb-06 at 13:01

For a research project, I would like to form two groups (e.g. left/right) within a panel data set of a highly fragmented party system, based on a string variable containing the coalitions the parties form, as in column (3) of the following simplified example:

...

ANSWER

Answered 2020-Feb-06 at 12:55

library(tidyverse)

d %>%
  separate_rows(coalitions) %>%
  filter(parties != coalitions) %>%
  count(parties, coalitions)

# # A tibble: 6 x 3
#   parties coalitions     n
#            
# 1 A       C              2
# 2 A       D              1
# 3 A       E              1
# 4 B       F              1
# 5 B       G              2
# 6 B       H              1

Source https://stackoverflow.com/questions/60095113

QUESTION

Modify multi-level dictionaries

Asked 2019-Apr-22 at 04:31

I want to create a data structure for storing various possible paths through a plane with polygons scattered across it. I decided on using nested, multi-level dictionaries to save the various possible paths splitting at fixed points.

A possible instance of such a dictionary would be:

...

ANSWER

Answered 2019-Apr-21 at 23:13

You can certainly write accessors for such a nested dictionary:

Source https://stackoverflow.com/questions/55787207

QUESTION

Extensionally equal predicates and equality of universally quantified applications

Asked 2018-Jul-25 at 21:08

I am trying to define a recursive predicate using well-founded fixpoints with the obligation to show F_ext when rewriting with Fix_eq. The CPDT says that most such obligations are dischargeable with straightforward proof automation, but unhappily this does not appear to be so for my predicate.

I have reduced the problem to the following lemma (from Proper (pointwise_relation A eq ==> eq) (@all A)). Is it provable in Coq without additional axioms?

...

ANSWER

Answered 2018-Jul-25 at 21:08

You might be interested in this code I wrote a while ago, which includes variants of Fix_eq for various numbers of arguments, and don't depend on function extensionality. Note that you don't need to change Fix_F, and can instead just prove variants of Fix_eq.

To answer the question you asked, rather than solve your context, the lemma you state is called "forall extensionality".

It is present in Coq.Logic.FunctionalExtensionality, where the axiom of function extensionality is used to prove it. The fact that the standard library version uses an axiom to prove this lemma is, at the very least, strong evidence that it is not provable without axioms in Coq.

Here is a proof sketch of that fact. Since Coq is strongly normalizing*, every proof of x = y in the empty context is judgmentally equal to eq_refl. That is, if you can prove x = y in the empty context, then x and y are convertible. Let f x := inhabited (Vector.t (x + 1)) and let g x := inhabited (Vector.t (1 + x)). It is straightforward to prove forall x, f x = g x by induction on x. Therefore, if your lemma were true without axioms, we could get a proof of

Source https://stackoverflow.com/questions/51507117

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install fixpoints

Add this line to your application's Gemfile: gem 'fixpoints' and make sure to add:.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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