gtfs | Ruby lib for dealing with GTFS | Web Services library

 by   nerdEd Ruby Version: v0.4.0 License: MIT

kandi X-RAY | gtfs Summary

kandi X-RAY | gtfs Summary

gtfs is a Ruby library typically used in Web Services applications. gtfs has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A Ruby wrapper for the General Transit Feed Specification.
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            kandi-support Support

              gtfs has a low active ecosystem.
              It has 60 star(s) with 40 fork(s). There are 9 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 5 open issues and 5 have been closed. On average issues are closed in 299 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of gtfs is v0.4.0

            kandi-Quality Quality

              gtfs has no bugs reported.

            kandi-Security Security

              gtfs has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              gtfs is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              gtfs releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed gtfs and discovered the below as its top functions. This is intended to give you an instant insight into gtfs implemented functionality, and help decide if they suit your requirements.
            • Loads a source from the archive
            • Extracts the source from the given directory .
            • Parse the source file .
            • Raises an exception if the source exists
            • Return all entries in the temporary directory
            • The list of files
            Get all kandi verified functions for this library.

            gtfs Key Features

            No Key Features are available at this moment for gtfs.

            gtfs Examples and Code Snippets

            Getting started
            Rubydot img1Lines of Code : 20dot img1License : Permissive (MIT)
            copy iconCopy
            # Defaults to strict checking of required columns
            source = GTFS::Source.build()
            
            # Relax the column checks, useful for sources that don't conform to standard
            source = GTFS::Source.build(, {strict: false})
            
            source.agencies
            source.stops
            source.routes
            s  

            Community Discussions

            QUESTION

            Give each row in a list an ID
            Asked 2021-Apr-22 at 17:11

            I'm trying to create a timetables.txt from other files, and I have this so far.

            ...

            ANSWER

            Answered 2021-Apr-22 at 17:11

            Just see the code written below and add it.

            Source https://stackoverflow.com/questions/67216923

            QUESTION

            How to import sf to package to run a function that depends on lwgeom?
            Asked 2021-Mar-12 at 21:17

            I'm building a package that imports {sf}, and more specifically I use st_length() in one of my functions.

            I initially added only {sf} to my package "Imports", but when I checked it I got a few {lwgeom} related errors:

            ...

            ANSWER

            Answered 2021-Feb-19 at 21:23

            You can consider adding the {lwgeom} package in Suggests field of your package DESCRIPTION file. It should do the trick.

            Source https://stackoverflow.com/questions/66284820

            QUESTION

            Elegant way to open files from same folder but with different names
            Asked 2021-Mar-02 at 00:18

            I need to read a few files from the same folder but with different file names. Is there a more elegant way to do this?

            ...

            ANSWER

            Answered 2021-Mar-01 at 09:00

            you can use dict to store the dataframe, as the filename is the key.

            Source https://stackoverflow.com/questions/66419029

            QUESTION

            Download files in R with URLs that do not end with the file extensions
            Asked 2021-Feb-26 at 05:36

            Does anyone have a trick up there sleeve for downloading GTFS using R when the URL doesn't end with ".zip"? For instance, this works:

            ...

            ANSWER

            Answered 2021-Feb-24 at 08:15

            Your link is probably a redirect. Try using the httr package as described here R download file redirect error

            Source https://stackoverflow.com/questions/66346182

            QUESTION

            How to read application/octet-stream in Python
            Asked 2021-Feb-15 at 15:52

            Building off of this question, I'm using a Python script to call the API detailed in the link below:

            https://developer.wmata.com/docs/services/gtfs/operations/5cdc51ea7a6be320cab064fe?

            I use the code below to call the api:

            ...

            ANSWER

            Answered 2021-Feb-15 at 15:52

            GTFS-rt is transported in a compressed encoded representation called a "protobuf." Your Python script will need to use the gtfs-realtime.proto file (which contains a definition of the expected contents of the GTFS-rt feed) along with the Google Protobuf Python package in order to decode the response.

            Here is an example of how to read a GTFS-rt API in Python from the documentation: https://developers.google.com/transit/gtfs-realtime/examples/python-sample.

            Source https://stackoverflow.com/questions/66199324

            QUESTION

            Python HTTP Request Returns 404 or Bytes
            Asked 2021-Feb-11 at 22:58

            I'm trying to use a Python script to call the API detailed in the link below:

            https://developer.wmata.com/docs/services/gtfs/operations/5cdc51ea7a6be320cab064fe?

            When I use the code below, it always returns a 404 error:

            ...

            ANSWER

            Answered 2021-Feb-11 at 22:14

            Try changing your URL so that it is using https instead of http. The documentation that you have linked at Bus RT Trip Updates seems to indicate that https is required.

            Change this:

            Source https://stackoverflow.com/questions/66163640

            QUESTION

            How to get the desired values from a list of multiple different kind of strings
            Asked 2021-Jan-22 at 13:36

            I am building a tool to calculate PT accessibility. I just need few more data to start the quantifying process but been struggling for this issue below.

            I have this script which can get the break-leg data of public transport trips from HERE API, here is a sample result from the code:

            ...

            ANSWER

            Answered 2021-Jan-21 at 18:32

            You can use a very simple regular expressions:

            Source https://stackoverflow.com/questions/65832131

            QUESTION

            How to convert GTFS-RT Trip Updates data to a dataframe?
            Asked 2021-Jan-21 at 03:31

            I have downloaded some GTFS-RT Trip Updates data in dictionary format using this code:

            ...

            ANSWER

            Answered 2021-Jan-21 at 03:31

            I used this url for testing:

            Source https://stackoverflow.com/questions/65816113

            QUESTION

            How to load json nested data into bigquery
            Asked 2020-Dec-17 at 09:07

            I'm trying to load the json data from an API into bigquery table on GCP however I got an issue that the json data seem to miss a square bracket so it got an error '"Repeated record with name trip_update added outside of an array."}]'. I don't know how Here is the data sample:

            ...

            ANSWER

            Answered 2020-Dec-15 at 21:21

            Your schema definition is wrong. trip_update isn't a struct repeated, but a record nullable (or not, but not repeated)

            Source https://stackoverflow.com/questions/65313221

            QUESTION

            Computing graph from the distances between points
            Asked 2020-Oct-25 at 00:30

            I have a set of geographical points (lat, lon) and I want to compute a directed graph where:

            • the nodes are those points
            • an edge X->Y (between nodes X and Y) exists if the fastest path between X and Y doesn't pass through another node Z.

            I am able to compute the duration of the path between any pair of nodes. Right now, I'm doing the following:

            1. compute the durations between every pair of nodes
            2. for every pair of nodes X,Y, there is an edge between X and Y if there is no node Z such that the duration of X->Z plus the duration of Z->Y is the same as the duration of X->Y.

            I have tested this approach for a subset of the nodes and it seems to work, but since I have around 2000 nodes and the computation of the duration between nodes is computationally expensive (because it involves calculating the shortest path), I would like to know if there is a better approach.

            Some additional (probably not relevant) info:

            • The nodes are bus stop locations, taken from a GTFS feed
            • I'm calculating the shortest paths durations using http://project-osrm.org/

            Any help will be greatly appreciated

            ...

            ANSWER

            Answered 2020-Oct-25 at 00:30

            I would start by running a Delaunay triangulation, this will give you an idea of what the path structure "should" look like (in theory). In theory, once you have the delaunary triangulation, it is easy to find the shortest paths. In practice however, you are using road networks instead of point-to-point distances, so you have to challenge those assumptions.

            1. First build a way that given the Delaunay triangulation. Example of what the triangulation might look like below. Let's say that points HJG are within a city center and the points around it are a freeway that surrounds it. Say with a 65 mph or so speed limit. This means going from ABCG might be faster than AHG.

            2. For every edge in the Delaunay triangulation. Determine the duration of the edge in both directions. This will give you your initial weights (it may also effect the triangulation if you can determine that the shortest path for AH is actually ABH). If there isn't a way to go around for faster routes. The ABCG being faster than AHG example. Then you are probably done at this point. If not you'll have to try to contract edges, which depending on your data, might require doing all routes anyway as you can't really be sure some obscure path allows it to be faster. Sadly, triangulation can't account for differences in speed between edges.

            1. If you can set it up to tell you which point it does go through, then you can avoid having to run it on all paths. IE: If you can say have it tell you the fastest path AF, and it says it uses AHGF, then you can be reasonably sure that AHG and HGF are the shortest paths between AG and HF, and you don't need to run those. However, if you find that AF actually takes ABCEF instead, then there is clearly a great speed difference between the routes, and you should also check the fastest route to AG to ensure it's actually AHG. Whenever you find a faster edge, be sure to add to the triangulation. You may actually be able to add multiple edges. Basically the idea here is that the triangulation gives you an idea of what should be fastest routes if speed doesn't matter. However, you need to confirm or reject that hypothesis. Basically for each node. Find the shortest paths to all points via BFS. Take the longest path and explore it.

            2. To aid in #3, it would likely help to vertex path covering of the edges in the graph. Create paths to all the furthest points from each point until all points are covered. IE: ABCD ABCE AHGF AHJKL AIK (also the reverse order as it is directional). Then you can run shortest path from AD, AE, AF, AL, and AK. If those paths match the expected paths, then you are done. If not, you'll be refining things along the way in the method used for #3 above. Worst case though, I'm not sure there's a way to get this much faster than all shortest paths in theory this approach is roughly O(VE).

            3. In theory #4 requires starting at every vertex. However, vertices can be skipped if the connecting paths have been valid as being the shortest path, so I would likely recommend starting checking vertices with the least number of (un-validated?) edges. Though again, you may need to do all pairs to be 100% sure only the shortest edges connect each node.

            4. For testing I would recommend doing this: Randomly select say 10-200 of those 2000 points. Run the algorithm on those 10-200 points. Then run all paths on those points. If they don't agree take a close look at why they don't agree. Feel free to add any "exceptional" cases to your answer and comment here. Repeat many times and see if there is any disagreement. Note all disagreements. If there are no disagreements, try running on the entire 2000 point set. I would strongly recommend doing this test after step 2. There is a chance that the Delaunay graph is very close to the optimal, depending on your dataset.

            Source https://stackoverflow.com/questions/64484896

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install gtfs

            Initialize a new GTFS source:.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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