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The diff washing machine. See your code changes clearly.
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QUESTION
zebra_owner(Owner) :-
houses(Hs),
member(h(Owner,zebra,_,_,_), Hs).
water_drinker(Drinker) :-
houses(Hs),
member(h(Drinker,_,_,water,_), Hs).
houses(Hs) :-
length(Hs, 5), % 1
member(h(english,_,_,_,red), Hs), % 2
member(h(spanish,dog,_,_,_), Hs), % 3
member(h(_,_,_,coffee,green), Hs), % 4
member(h(ukrainian,_,_,tea,_), Hs), % 5
adjacent(h(_,_,_,_,green), h(_,_,_,_,white), Hs), % 6
member(h(_,snake,winston,_,_), Hs), % 7
member(h(_,_,kool,_,yellow), Hs), % 8
Hs = [_,_,h(_,_,_,milk,_),_,_], % 9
Hs = [h(norwegian,_,_,_,_)|_], % 10
adjacent(h(_,fox,_,_,_), h(_,_,chesterfield,_,_), Hs), % 11
adjacent(h(_,_,kool,_,_), h(_,horse,_,_,_), Hs), % 12
member(h(_,_,lucky,juice,_), Hs), % 13
member(h(japanese,_,kent,_,_), Hs), % 14
adjacent(h(norwegian,_,_,_,_), h(_,_,_,_,blue), Hs), % 15
member(h(_,_,_,water,_), Hs), % one of them drinks water
member(h(_,zebra,_,_,_), Hs). % one of them owns a zebra
adjacent(A, B, Ls) :- append(_, [A,B|_], Ls).
adjacent(A, B, Ls) :- append(_, [B,A|_], Ls).
ANSWER
Answered 2021-Jun-14 at 21:46The houses list Hs is not empty at all, ever. It is created right at the very beginning with
QUESTION
I'm trying to find fractions not preceded by a word followed by a /, for example, s2. My code doesn't work for that one but it's able to capture for other ones. Can you please help modify the regex expression? The expected is given followed by _f.
...ANSWER
Answered 2021-Jun-14 at 21:16We could match either a regex lookaround to match the lower case letters ((?<=[a-z])) followed by either one or more space, comma ([, ]+) followed by any / and digits (\\d+) and other characters (.*) or (|) one or more digits and other characters and replace with blank ("")
QUESTION
I have to mark up a text inserting tags in a string as follows:
...ANSWER
Answered 2021-Jun-14 at 08:06mystring = list('123456789')
postions = [(2,4),(6,8)]
shift = 0
for pos in postions:
tag = ""
mystring.insert(pos[0] + shift, tag)
shift += 1
mystring.insert(pos[1] + shift, tag.replace('<', 'QUESTION
I am creating a system dynamics model in AnyLogic to be representative of a water mass balance for a city. One of the important aspects of this is to understand how different conservation measures affect supply-demand relationships. There are 3 different conservation measures and there are five different levels of adoption for each: 0%, 25%, 50%, 75%, and 100%. This makes a total of 125 combinations. I was thinking of linking the 3 parameters to sliders in order to choose the level of adoption, but going through each combination manually appears to be unnecessarily grueling. Does anyone know if it is possible that during run time the model is able to choose the different combinations on its own? If so, how can this be accomplished?
...ANSWER
Answered 2021-Jun-14 at 01:24Parameter variation experiment should be ideal for what you need: https://anylogic.help/anylogic/experiments/parameter-variation.html#parameter-variation-experiment
Create a parameter in main for each measure you want to vary. Then, in the experiment's properties, you can specify the range and step to define the different values you want the parameters to take.
Then, when you run it, all possible combinations will be run.
QUESTION
Is there any better or simpler solution for this task:
"A matrix of dimensions MxN is given, filled with the numbers 0 and 1. The field on which the number 0 is written represents land, and the field on which it is written number 1 represents water. Write a function largestLake(int [] [] map) which calculates the size of the largest water surface in the matrix map. The size of a water surface is the number of fields of value 1 that that water surface contains. Two water cells are considered connected if they are adjacent horizontally, vertically or diagonally." ?
Example:
Input:
4 5 //MxN
0 0 1 1 0
1 0 1 1 0
0 1 0 0 0
0 0 0 1 1
Output:
6
I tried to find it with BFS algorithm, but it ended up with too many loops. It says in the task that "The best solution has complexity O (M * N)."
I loaded matrix in main and here is my function:
...ANSWER
Answered 2021-Jun-13 at 22:55Try using recursion.
QUESTION
I'm trying to make 5 screens to show information about a team and need to print some text in each one of them. How can I avoid all these lines?
...ANSWER
Answered 2021-Jun-11 at 20:29You can have the single instance of SysFont as a class variable:
QUESTION
I'm making a game discord bot that has different channels as different "areas," but I want the same command to do different things depending on what channel it was used in.
This is what I have right now:
...ANSWER
Answered 2021-Jun-10 at 19:43channel is a discord.TextChannel instance and you're comparing it to a string, that's never True, simply cast channel to a string:
QUESTION
I've constructed a data.frame using the inefficient code below. Can you improve it, noting that if you can think of a better starting point, please include that answer.
My code takes data from the first two data frames and combines them to give the third. The first data.frame is a grid of 1s and -1s representing low or high values. The second data.frame includes all the information for me to calculate the high or low values. Note that each column has similar calculations but the calculation may differ from column to column.
...ANSWER
Answered 2021-Jun-10 at 19:02Consider refactoring with ifelse logic and filtered vectors using a user defined method since logic is very similar but across different columns:
QUESTION
I am trying to use 2 strings of
CSS:
...ANSWER
Answered 2021-Jun-10 at 15:47It is not recommend nor supported to load the Google Maps JS API twice on a single page. You will get a console warning about this.
Problem:
- double billing
- collision and unexpected behaviors
Solutions:
- Use same key for both maps on page(not sure why this wouldn't be preferred).
- If you really must, one of the maps could be embedded in an iframe.
QUESTION
I applied case_when to a text data of thousands of rows to detect strings with multiple conditions and replace them but got a wrong result because case_when doesn't execute the remaining conditions once a condition is met. I have seen a solution in How to detect more than one regex in a case_when statement, but the solution does not have multiplicity of multiple conditions such as in my data.
Any alternative to case_when will be is appreciated.
This is the dummy data:
...ANSWER
Answered 2021-Jan-22 at 06:51You may use case_when with grepl and a regex alternation:
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On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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