natalie | a unique Ruby implementation , compiled to C | Compiler library
kandi X-RAY | natalie Summary
kandi X-RAY | natalie Summary
Natalie is a very early-stage work-in-progress Ruby implementation. It provides an ahead-of-time compiler using C++ and gcc/clang as the backend. Also, the language has a REPL that performs incremental compilation.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- gets the user input
- Renders the TCP socket .
- a wrapper around this function
- Called by number
- Process an array of strings .
- Instantiate an Enumerator .
- Initialize a new instance
- Sets the alignment of the button .
- Executes the given block .
- Creates a new instance of the given class
natalie Key Features
natalie Examples and Code Snippets
Community Discussions
Trending Discussions on natalie
QUESTION
I keep getting this error. I don't even know how to identify the row that is in error as the data I am requesting is jumbled. I can't provide a URL to the API but I will provide a sample of the first few lines of data.
My code:
...ANSWER
Answered 2022-Apr-18 at 04:07Since you don't specify a separator for columns in the data, python has to guess and it guessed wrong. Be specific.
QUESTION
ANSWER
Answered 2022-Mar-22 at 06:39var _questions = [
{
"questionText":
"What year was the first Iron Man movie released, kicking off the Marvel Cinematic Universe?",
"answerText": [
{"text": "2005", "score": 5},
{"text": "2008", "score": 6},
{"text": "2010", "score": 7},
{"text": "2012", "score": 8},
]
}
];
QUESTION
How I can join the below two tables and get only the LastSucessfull Payment Date from the Transactions Table? I want to pull only LastSucesfullPaymentdates, which should also consider through the returns;
Business Rules for LastSucesfull Payment Date:
If a recent payment shows as Return or refund, it will show in Debit AMount, and Transaction Type is 'Return' or 'Refund'. It will have two entries with the same Date One as Debitamount because of return and Creditamount because we attempted to collect the amount. Then this scenario should consider the previous successful payment date.
If it is Successful without any returns on the same date, It will show in Creditamount and Transaction Type is 'Payment'. This will be the last Successful Payment Date
If the TransactionType is Settlement- This will Last Successful Payment Date
At present, this is the query that I use for above output:
Below is the Transactionaltable
Reference Number PaymentNumber TransactionType Date DebitAmount CreditAMount 10484 1 Return 06/01/2022 242.61 10484 2 Payment 06/01/2022 242.61 10484 3 Payment 06/12/2021 242.61 10484 4 Payment 08/11/2021 242.61 10484 5 Payment 06/11/2021 242.61 10559 1 Payment 13/01/2022 0 529.65 10559 2 Return 10/01/2022 529.65 10559 3 Payment 10/01/2022 529.65 10559 4 Payment 10/12/2021 529.65 10598 1 Refund 29/12/2020 121.31 10598 2 Payment 11/12/2020 121.31 37473 1 Payment 22/01/2022 0 116.08 37473 2 Payment 22/12/2021 116.08 37473 3 Payment 22/11/2021 116.08 37466 1 Settlment 28/01/2022 1300 37466 2 Payment 28/12/2021 127.00 37466 3 Payment 28/11/2021 127.00 37466 4 Payment 28/10/2021 127.00 ...ANSWER
Answered 2022-Feb-16 at 03:13Basically the query is using APPLY()
operator to get 1 transaction for each of the Reference Number
.
For Business Rule 1, this is handle by checking for following express is greater than 0
QUESTION
Consider the following incomplete function:
...ANSWER
Answered 2022-Jan-21 at 19:03I believe that the intention of this code should check if the first letter is greater, not equal, to the searched name.
So:
QUESTION
I want to delete all occurances of keynames like etag,formattedType and metadata in the object using dynamic iteration of whole object
...ANSWER
Answered 2021-Dec-17 at 12:12this recursive function will solve your problem
QUESTION
I'd like to scrape https://www.deutsche-biographie.de/ . Specifically, I'm interested in scraping the following information about each individual
- Name
- Year of birth
- Year of death
- Profession
- Place of birth ('geburt' in source code) and coordinates
- Place of death ('tod' in source code) and coordinates
- Places of activity ('wirk' in source code) and coordinates
With the code below, I scraped name, year of birth, year of death, and profession.
...ANSWER
Answered 2021-Nov-21 at 00:03I hope this solution helps:
QUESTION
In a dataset, I need to find how many instances of "mr.","mrs." and "miss." there are. For example:
...ANSWER
Answered 2021-Nov-07 at 18:28You can use a regex. The titles are distinctive enough that they should not appear anywhere else.
QUESTION
I have a DataFrame that contains a list of unordered project IDs and their respective leaders. I want to compare a new dataframe's values with the ground truth to verify that all the project IDs in the new data frame are both; in the ground truth and have the same leader. Sometimes, the new DataFrame may have different column names but they are always two and always mean the same thing.
For example, the ground truth DataFrame (df_gt):
...ANSWER
Answered 2021-Sep-13 at 16:03df_1 = pd.DataFrame(data={'Project ID': [123, 122, 145, 134], 'Leader': ['Owen Wilson', 'Samuel Jackson',
'Jack Black', 'Natalie Portman']})
df_2 = pd.DataFrame(data={'Project ID': [123, 122, 144, 146], 'Leader': ['Owen Wilson', 'Henry Cavil',
'Natalie Portman', 'Jack Black']})
df_2['new'] = df_2['Project ID'].map(df_1.set_index('Project ID')['Leader'])
df_2 = df_2[(df_2['Leader']!=df_2['new'])]
print(df_2[['Project ID', 'Leader']].values.tolist())
QUESTION
I am having trouble with removing a user based on what is inputted in a text field. My localstorage has the data below. With users being the key and the values being the list of objects with username and genrePref.
...ANSWER
Answered 2021-Aug-30 at 07:57If you really have that stored in local storage, you've encoded it in some way (perhaps JSON?) when saving. You have to decode it when retrieving it.
For instance, if it were JSON, you'd do this:
QUESTION
I am just a real novice when it comes to python but I am really enjoying the learning process. I am interested in data analysis and all I am trying to do is scrape list elements of a wikipedia page.
I have managed to pull the list and prettify it via:
...ANSWER
Answered 2021-Aug-13 at 11:17You don't need to use row.find("li")
to select
music_rows = music_box.find_all("li")
. row.find("li")
will find
row
's children, not itself. You can try this one:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install natalie
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page