carpenter | 抓取国家统计局网站然后转换成yaml

 by   snow Ruby Version: Current License: No License

kandi X-RAY | carpenter Summary

kandi X-RAY | carpenter Summary

carpenter is a Ruby library. carpenter has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

抓取国家统计局网站[最新县及县以上行政区划代码]然后转换成yaml
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            kandi-support Support

              carpenter has a low active ecosystem.
              It has 8 star(s) with 2 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              carpenter has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of carpenter is current.

            kandi-Quality Quality

              carpenter has no bugs reported.

            kandi-Security Security

              carpenter has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              carpenter does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              carpenter releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of carpenter
            Get all kandi verified functions for this library.

            carpenter Key Features

            No Key Features are available at this moment for carpenter.

            carpenter Examples and Code Snippets

            No Code Snippets are available at this moment for carpenter.

            Community Discussions

            QUESTION

            C++ pointer vs object
            Asked 2021-May-30 at 20:41

            Could you please clear up a question for me regarding pointer vs object in C++. I have the below code that has a class called "person" and a list that allows for 100 objects of that class type.

            ...

            ANSWER

            Answered 2021-May-30 at 20:27

            basically the first case works like this: you have an array of objects. To access the object fields and methods you use . operator. In the second case you have an array of pointers to an object. Pointer is just a memory address, that points to an object of some type. In your case, this is an array of pointers to class person. By default, these pointers are invalid; you have to set them to the address of some existing object. new creates an object on the heap, and returns you an address of that object. In order to access the value behind the pointer, you have to de-reference it. The syntax is this:

            Source https://stackoverflow.com/questions/67765327

            QUESTION

            Filtering by natural key?
            Asked 2021-May-25 at 09:31

            I don't have the ids of the objects I want because they were created by bulk_create: and bulk_create doesn't return objects with ids so I need to fetch them by their natural keys.

            Is it possible to fetch the objects by filtering by natural key? I've found nothing in the documentation.

            We can already do:

            ...

            ANSWER

            Answered 2021-May-25 at 09:31

            QUESTION

            Add multiple rows in existing dataframe based on a list pandas
            Asked 2021-Apr-15 at 11:55

            i have a dataframe df with 1 row and 20 columns:

            ...

            ANSWER

            Answered 2021-Apr-15 at 11:55

            You can repeat index values by length of list and then assign to new column:

            Source https://stackoverflow.com/questions/67107858

            QUESTION

            Macros to compare shop name and Invoice Number between two sheets and highlight matches
            Asked 2021-Apr-13 at 13:15

            Hi Guys I am not sure if the code for this is already given I tried similar questions but I didnt find an appropriate solution so I am asking this here

            "Note: I use Office 2010 only"

            The Problem:

            I have two sheets in excel with the entries like Tin No, Customer Name, Invoice Number, Cost, Tax, Value before Tax, Value after-tax, etc., Now I have to compare both the Customer Name and Invoice Number in both sheets and return the value or highlight the results.

            The Situation
            (Sheet 1)

            Customer Name Invoice Number Carpenter 101 Painter 102 Courier 103 Welder 104 Painter 105 Courier 106 Welder 107

            (Sheet 2)

            Customer Name Invoice Number Carpenter 101 Courier 103 Welder 104 Painter 105 Welder 107

            In Sheet 2 Invoice numbers 102 and 106 are missing I want that Highlighted in a separate column or in the same sheet with a different color.

            If it is still not clear please let me know.

            ...

            ANSWER

            Answered 2021-Apr-13 at 13:15

            You can do that with formula to cross-check both files.

            First sheet:

            Customer Name (A1) Invoice Number (B1) Key (C1) Find_Missing - formula - (D1) Carpenter (A2) 101 (B2) =A2&B2 =Iferror(Index(Sheet2!C:C;Match(A2&B2;Sheet2!C:C;0));"Not Found") Painter (A3) 102 (B3) =A3&B3 =Iferror(Index(Sheet2!C:C;Match(A3&B3;Sheet2!C:C;0));"Not Found") Courier (A4) 103 (B4) =A4&B4 =Iferror(Index(Sheet2!C:C;Match(A4&B4;Sheet2!C:C;0));"Not Found")

            Second sheet:

            Customer Name (A1) Invoice Number (B1) Key (C1) Find_Missing - formula - (D1) Carpenter (A2) 101 (B2) =A2&B2 =Iferror(Index(Sheet1!C:C;Match(A2&B2;Sheet1!C:C;0));"Not Found") Courier (A3) 103 (B3) =A3&B3 =Iferror(Index(Sheet1!C:C;Match(A3&B3;Sheet1!C:C;0));"Not Found") Welder (A4) 104 (B4) =A4&B4 =Iferror(Index(Sheet1!C:C;Match(A4&B4;Sheet1!C:C;0));"Not Found")

            Source https://stackoverflow.com/questions/67075110

            QUESTION

            How do I fix sorting issue in Cobol program?
            Asked 2021-Apr-13 at 07:49

            I have a program that is suppose to sort an input file (seq) and then output an RPT file.

            This program code should be correct, the problem should only be in the sorting of this program.

            PROBLEM: The program successfully sorts the data correctly, my problem is that I can not get the sort file to continue after being sorted to be formatted and do calculations.

            PLEASE: show in code and explain, this is my first time trying the sort a file.

            SEQ:

            ...

            ANSWER

            Answered 2021-Apr-13 at 07:49

            In the PERFOM UNTIL... loop, you are reading BASEBALL-FILE-OUT, instead of the sorted BASEBALL-FILE-SORTED.

            Source https://stackoverflow.com/questions/67067783

            QUESTION

            UPDATED: How do I fix Sort and Release in Cobol?
            Asked 2021-Apr-12 at 20:07

            I have a program that is suppose to sort an input file (seq) and then output an RPT file.

            This program code should be correct, the problem should only be in the sorting of this program.

            CURRENTLY: Program will not compile.

            SORT: The output records need to sort LEAGUE-S (major) in descending order. TEAM-S (intermediate) ascending order. NAME-S (minor) ascending order.

            PLEASE: show in code and explain, this is my first time trying the sort a file.

            SEQ:

            ...

            ANSWER

            Answered 2021-Apr-12 at 19:42

            ARE-THERE-MORE-RECORDS = 'NO' is still true from its use in the input procedure. At the beginning of the output procedure, insert MOVE 'YES' TO ARE-THERE-MORE-RECORDS. You also need to replace the READ BASEBALL-FILE-IN with RETURN SORT-FILE, add some fields to SORT-RECORD, and use those fields for the report.

            Why do you have BASEBALL-FILE-UNSORTED-IN? It doesn't have any of the fields you need to move to SORT-RECORD.

            If you want to use BASEBALL-FILE-UNSORTED-IN, then don't use an input procedure. Instead change the SORT statement from INPUT PROCEDURE 120-SORT-INPUT-PROCEDURE to USING BASEBALL-FILE-UNSORTED-IN. Do not OPEN or CLOSE the file. That will be done by the runtime. Remove the 120- and 130- paragraphs.

            Comment everything associated with BASEBALL-FILE-IN, except 01 BASEBALL-RECORD-IN and its data items. That effectively allows the BASEBALL-RECORD-IN data definition to be used as a replacement for SORT-RECORD. That reduces the number of changes that are needed.

            Source https://stackoverflow.com/questions/67064067

            QUESTION

            How do I fix sorting program?
            Asked 2021-Apr-12 at 17:57

            I have a program that is suppose to sort an input file (seq) and they output an RPT file.

            This program code should be correct, the problem should only be in the sorting of this program. Currently, it prints is weird chunks.

            SORT: The output records need to sort LEAGUE-S (major) in descending order. TEAM-S (intermediate) ascending order. NAME-S (minor) ascending order.

            SEQ:

            ...

            ANSWER

            Answered 2021-Apr-12 at 17:57

            SORT is not being used correctly. The report is being printed in 120-SORT-INPUT-PROCEDURE using the fields from BASEBALL-RECORD-IN. It should be printed in 130-SORT-OUTPUT-PROCEDURE using the fields from SORT-RECORD.

            Furthermore, no records are sorted because there is no RELEASE statement in the input procedure. To access records after the sort, a RETURN statement is used in the same manner as a READ statement for a sequential file.

            The input procedure should be used to move the data from selected records to the sort record, after which the record is released to sort.

            The output procedure may then used to produce a report from the sorted data by returning and printing each record until the there are no more sorted records.

            Source https://stackoverflow.com/questions/67061259

            QUESTION

            How convert a list of strings to a single delimited string?
            Asked 2021-Feb-24 at 20:12

            I've been looking through dozens of threads and can't find an answer to this, but hopefully it's not too difficult. I need to take a list of strings and convert them to a single string comma delimited. Also need that single string to be held by a variable.

            I'm using this script to call keyword tags from an API.

            ...

            ANSWER

            Answered 2021-Feb-24 at 20:12

            There is a problem with getting items from json. Here is the way to get all items in image_list correctly:

            Source https://stackoverflow.com/questions/66357229

            QUESTION

            Pandas DataFrame read_csv then GroupBy - How to get just a single count instead of one per column
            Asked 2021-Feb-24 at 15:55

            I'm getting the counts I want, but I don't understand why it is creating a separate count for each data column. How can I create just one column called "count"? Would the counts only be different when a column as a Null (NAN) value?

            Also, what are the actual column names below? Is the column name a tuple?

            Can I change the groupby/agg to return just one column called "Count"?

            CSV Data:

            ...

            ANSWER

            Answered 2021-Feb-24 at 15:55

            QUESTION

            Simple Pandas DataFrame read_csv then GroupBy with Count / KeyError
            Asked 2021-Feb-24 at 04:25

            I'm just trying to get a count of rows for a values in a given column, for example:

            CSV Data:

            ...

            ANSWER

            Answered 2021-Feb-24 at 04:25

            Pandas sees the first column as 'Occupation' not Occupation.

            use this:-

            Source https://stackoverflow.com/questions/66344545

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install carpenter

            You can download it from GitHub.
            On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/snow/carpenter.git

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            gh repo clone snow/carpenter

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            git@github.com:snow/carpenter.git

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